Refer to NEET Chemistry The P Block Elements MCQs Set A provided below available for download in Pdf. The MCQ Questions for Full Syllabus Chemistry with answers are aligned as per the latest syllabus and exam pattern suggested by NEET, NCERT and KVS. Multiple Choice Questions for The P Block Elements are an important part of exams for Full Syllabus Chemistry and if practiced properly can help you to improve your understanding and get higher marks. Refer to more Chapter-wise MCQs for NEET Full Syllabus Chemistry and also download more latest study material for all subjects
MCQ for Full Syllabus Chemistry The P Block Elements
Full Syllabus Chemistry students should refer to the following multiple-choice questions with answers for The P Block Elements in Full Syllabus.
The P Block Elements MCQ Questions Full Syllabus Chemistry with Answers
Question: On moving down the group 13 density
- a) Increases
- b) Decreases
- c) First decreases then increases
- d) Remains same
Answer: Increases
Question: High melting point of boron is due to its existance as
- a) Small covalent molecule
- b) Giant covalent molecule
- c) Giant covalent solid
- d) Giant ionic molecule
Answer: Giant covalent solid
Question: Elements of group 13 mainly form covalent compounds because
- a) Size of ions is small
- b) Sum of three ionization energies is very high
- c) Electronegativity values are high
- d) All of these
Answer: All of these
Question: Oxidation state shown by group 13 elements is
- a) +1 and +3
- b) +1, +2 and +3
- c) +2, +3 and +4
- d) +1 and +4
Answer: +1 and +3
Question: Which one of the following elements of group 13 can react with alkali solutions to give H2 gas?
- a) Boron
- b) Aluminium
- c) Gallium
- d) All of these
Answer: All of these
Question: Lewis acid character of boron trihalides is as follows
- a) BI3> BBr3> BCl3> BF3
- b) BF3> BCl3> BBr3> BI3
- c) BCl3> BF3> BBr3> BI3
- d) BI3> BBr3< BF3< BCl3
Answer: BI3> BBr3> BCl3> BF3
Question: Dimer Al2Cl6 is formed because
- a) Al is electron rich
- b) Aluminium is having lone pair of electron
- c) Aluminium forms coordinate bonds with chlorine to complete its octet
- d) Aluminium donates lone pair to form bridge
Answer: Aluminium forms coordinate bonds with chlorine to complete its octet
Question: When we heat borax strongly then it will yield the following compound
- a) NaBO2
- b) B2O3
- c) Na2B4O7
- d) Both (1) & (2)
Answer: Both (1) & (2)
Question: B(OH)3 accept how many OH– ions?
- a) 1
- b) 2
- c) 3
- d) 4
Answer: 1
Question: Boric acid is having a polymeric type structure because of its
- a) Basic nature
- b) Acidic nature
- c) Hydrogen bonds
- d) Co-ordinate bonds
Answer: Hydrogen bonds
Question: Select the incorrect statement for B2H6
- a) It contains B—B ionic bond
- b) Each boron is sp3 hybridised
- c) It has two types of hydrogen bonds
- d) All of these
Answer: It contains B—B ionic bond
Question: In diborane each boron forms
- a) Two bonds
- b) Three bonds
- c) Four bonds
- d) Five bonds
Answer: Four bonds
Question: Which one of the following compounds has similar structure to that of graphite?
- a) Boron nitride
- b) Boron carbide
- c) Aluminium oxide
- d) Aluminium carbide
Answer: Boron nitride
Question: The number of sigma and pi bonds present in inorganic benzene are respectively
- a) 3σ, 12π
- b) 12σ, 3π
- c) 3σ, 3π
- d) 12σ, 12π
Answer: 12σ, 3π
More Questions...........................................
Question: Aluminium is used for making alloys because of its
- a) Resistance to corrosion
- b) Poor conductivity
- c) Heaviness
- d) All of these
Answer: Resistance to corrosion
Question: Group 14 elements have general electronic configuration
- a) ns2
- b) ns2np4
- c) ns2np6
- d) ns2np2
Answer: ns2np2
Question: Tendency of carbon for catenation is because carbon–carbon atom bond energy is
- a) Low
- b) High
- c) Zero
- d) Negative
Answer: High
Question: All elements except carbon have tendency to show maximum covalency of six
- a) Due to absence of vacant d-orbitals
- b) Due to presence of vacant d-orbitals
- c) Due to presence of partially filled d-orbitals
- d) Due to presence of completely filled d-orbitals
Answer: Due to presence of vacant d-orbitals
Question: Most abundant metal by mass in earth crust is
- a) Silicon
- b) Germanium
- c) Aluminium
- d) Arsenic
Answer: Aluminium
Question: Which one of the following elements is a metalloid?
- a) Carbon
- b) Germanium
- c) Lead
- d) All of these
Answer: Germanium
Question: On moving down the group, acidic nature of oxides of group 14
- a) Decreases
- b) Increases
- c) Remains same
- d) Increases then decreases
Answer: Decreases
Question: In diamond, carbon have
- a) sp3hybridisation
- b) sp hybridisation
- c) sp2 hybridisation
- d) sp3d2 hybridisation
Answer: sp3hybridisation
Question: Which one of the following elements forms double or triple bond involving pπ-pπ bonding?
- a) Carbon
- b) Silicon
- c) Germanium
- d) Tin
Answer: Carbon
Question: Allotropy is due to
- a) Difference in the number of atoms in the molecules
- b) Difference in the arrangement of atoms in the molecules in the crystal
- c) Difference in chemical properties
- d) All of these
Answer: Difference in the arrangement of atoms in the molecules in the crystal
Question: Graphite has
- a) 2-D sheet structure
- b) Van der Waals forces between different layers
- c) sp2 hybridised carbon linked with other three carbon atoms in hexagonal planar structure
- d) All of these
Answer: All of these
Question: In graphite, the bond is
- a) Ionic
- b) Covalent
- c) Co-ordinate
- d) Metallic
Answer: Covalent
Question: Which one of the following is properties of CO gas?
- a) It is a colourless gas
- b) It is an odourless gas
- c) It is a neutral oxide
- d) All of these
Answer: All of these
Question: Carbonic acid is a
- a) Weak tribasic acid
- b) Weak dibasic acid
- c) Strong tribasic acid
- d) Strong dibasic acid
Answer: Weak dibasic acid
Question: Organosilicon polymers containing Si—O—Si linkage is called
- a) Silicates
- b) Silicones
- c) Glass
- d) Silica
Answer: Silicones
Question: SiO44- ion has geometry
- a) Triangular
- b) Tetrahedral
- c) Pentagonal bipyramidal
- d) Linear
Answer: Tetrahedral
Question: Maximum covalent character is shown by
- a) NCl3
- b) PCl3
- c) AsCl3
- d) SbCl3
Answer: NCl3
Question: HNO2 on disproportionation gives HNO3 and
- a) NO2
- b) N2O5
- c) NO
- d) All of these can form
Answer: NO
Question: The correct order of acidic character is
- a) P4O10> P4O6
- b) N2O5> N2O3
- c) N2O3> P4O6
- d) All of these
Answer: All of these
Question: In which of the following reactions, products given are not correct?
- a)
- b)
- c)
- d)
Answer:
Question: Oxide of nitrogen which is acidic in nature and blue coloured liquid at –30°C
- a) N2O
- b) NO
- c) N2O3
- d) NO2
Answer: N2O3
Question: Covalency and oxidation numbers of nitrogen in N2O5 is respectively
- a) 5, +5
- b) 4, +5
- c) 3, +3
- d) 3, +5
Answer: 4, +5
Question: Which has maximum melting point?
- a) NH3
- b) PH3
- c) AsH3
- d) SbH3
Answer: NH3
Question: In which of the following N–N bond is not present?
- a) N2O5
- b) N2O
- c) N2O4
- d) N2O3
Answer: N2O5
Question: Which set of oxide of nitrogen is paramagnetic in monomeric state?
- a) NO, N2O
- b) NO2, N2O
- c) NO, NO2
- d) N2O, NO, NO2
Answer: NO, NO2
Question: The incorrect statement among the following is
- a) Reducing character of hydrides of group 15 increases down the group
- b) Basicity of hydrides of group 15 increases down the group
- c) Phosphorus and arsenic can form pπ–dπ bond but not nitrogen
- d) NCl5 does not exist
Answer: Basicity of hydrides of group 15 increases down the group
Question: Metal which become passive with conc. HNO3
- a) Cr
- b) Zn
- c) Al
- d) Both (1) & (3)
Answer: Both (1) & (3)
Question: Allotrope of phosphorus which is polymeric consisting of chains of P4 tetrahedral linked together is
- a) White phosphorus
- b) Red phosphorus
- c) Yellow phosphorus
- d) Both (1) & (2)
Answer: Red phosphorus
Question: Which is dibasic?
- a) Orthophosphoric acid
- b) Pyrophosphoric acid
- c) Orthophosphorus acid
- d) Hypophosphorus acid
Answer: Orthophosphorus acid
Question: In brown ring test for nitrate ions, brown ring is formed having composition
- a) [Fe(H2O)6]2+
- b) [Fe(H2O)5NO]2+
- c) [Fe(H2O)5NO]3+
- d) [Fe(H2O)5NO2]2+
Answer: [Fe(H2O)5NO]2+
Question: Cyclotrimeta phosphoric acid has total number of P=O & P–O bonds respectively
- a) 5, 3
- b) 3, 9
- c) 3, 6
- d) 5, 6
Answer: 3, 9
Question: The one with lowest negative electron affinity in group 16 is Because of small
- a) Oxygen
- b) Sulphur
- c) Selenium
- d) Tellurium
Answer: Oxygen
Question: The hybridisation and shape of SF4 is respectively
- a) sp3d2, square planar
- b) sp3d2, octahedral
- c) sp3d, see-saw
- d) sp3d, trigonal bipyramidal
Answer: sp3d, see-saw
Question: Correct order of boiling point of group 16 hydrides
- a) H2O < H2S < H2Se < H2Te
- b) H2Te < H2Se < H2S < H2O
- c) H2S < H2Se < H2Te < H2O
- d) H2O < H2Te < H2Se < H2S
Answer: H2S < H2Se < H2Te < H2O
Question: Dioxygen can be prepared by
- a) Heating KClO3
- b) Thermal decomposition of oxides like Ag2O, Pb3O4 etc
- c) Electrolysis of water
- d) All of these
Answer: All of these
Question: The set containing acidic oxides only are
- a) SO2, Cl2O7, CO
- b) Al2O3, NO, N2O5
- c) NO, N2O3, N2O5
- d) N2O3, SO2, N2O5
Answer: N2O3, SO2, N2O5
Question: The incorrect statement regarding structure of ozone
- a) The two oxygen-oxygen bond length in ozone are identical
- b) It is linear
- c) Bond angle is less than 120º
- d) Both (2) & (3)
Answer: It is linear
Question: Form of sulphur which shows paramagnetic behaviour
- a) S8– Rhombic
- b) S8– Monoclinic
- c) S2 in vapour state
- d) Not possible
Answer: S2 in vapour state
Question: Which has bleaching action due to reduction and it is temporary?
- a) H2O2
- b) O3
- c) SO2
- d) Cl2
Answer: SO2
Question: On reaction of moist SO2 with potassium permangnate, (Acidic) which is correctly observed?
- a) Colour of KMnO4 is decolourised
- b) SO2 is oxidised to SO3
- c) MnO-4 is reduced to MnO2
- d) All of these
Answer: Colour of KMnO4 is decolourised
Question: S–S bond is present in
- a) H2S2O7
- b) H2S2O8
- c) H2S2O6
- d) H2SO5
Answer: H2S2O6
Question: Deacon’s process of manufacture of chlorine is represented by the equation
- a)
- b)
- c)
- d)
Answer:
Question: The colour shown by halogen is incorrectly given by
- a) F2= Yellow
- b) Cl2= Colourless
- c) Br2= Red
- d) I2= Violet
Answer: Cl2= Colourless
Question: Which is incorrectly given according to order indicated?
- a) F2> Cl2> Br2> I2; Oxidising power
- b) HI > HBr > HCl > HF ; Acidic strength
- c) F2> Cl2> Br2> I2; Bond dissociation enthalpy
- d) HF > HI > HBr > HCl ; Boiling point
Answer: F2> Cl2> Br2> I2; Bond dissociation enthalpy
Question: Cl2 on reaction with excess of NH3 gives
- a) NH4Cl + N2
- b) NCl3+ HCl
- c) NH4Cl only
- d) NH4Cl + NCl3
Answer: NH4Cl + N2
Question: Cl2 on reaction with cold and dilute NaOH gives NaCl and
- a) NaOCl
- b) NaClO3
- c) NaClO4
- d) NaClO2
Answer: NaOCl
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MCQs for The P Block Elements Chemistry Full Syllabus
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