NCERT Solutions Class 4 Mathematics Chapter 6 The Junk Seller have been provided below and is also available in Pdf for free download. The NCERT solutions for Class 4 Mathematics have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Class 4 by CBSE, NCERT and KVS. Questions given in NCERT book for Class 4 Mathematics are an important part of exams for Class 4 Mathematics and if answered properly can help you to get higher marks. Refer to more Chapter-wise answers for NCERT Class 4 Mathematics and also download more latest study material for all subjects. Chapter 6 The Junk Seller is an important topic in Class 4, please refer to answers provided below to help you score better in exams
Chapter 6 The Junk Seller Class 4 Mathematics NCERT Solutions
Class 4 Mathematics students should refer to the following NCERT questions with answers for Chapter 6 The Junk Seller in Class 4. These NCERT Solutions with answers for Class 4 Mathematics will come in exams and help you to score good marks
Chapter 6 The Junk Seller NCERT Solutions Class 4 Mathematics
NCERT Solutions for Class 4 Mathematics Math Magic for Chapter 6 The Junk Seller
Chapter -6
THE JUNK SELLER
1. What about you? Do you also find Maths difficult?
Ans.I do not find Maths difficult.
2. What is the most difficult thing in you Maths book?
Ans.The chapter entitled “The Way the World Looks” is the most difficult thing in Maths book.
3. What do you think is the easiest lesson?
Ans.The lesson “A Trip to Bhopal” is the essential.
4. Find out: how much for a cup of tea?
Ask people and find out the cost of a cup of tea
(a) At a tea stall
Ans. (a)At a tea stall, the cost of a cup is Rs 3.
(b) At a hotel
Ans. (b)At a hotel, the cost of a cup is Rs 10.
5. If a person who runs a tea stalls earns Rs 30 in a day, how much will he earn in 10 days? And in a month? How did you get the answer? Discuss.
Ans.Earning of a tea stall owner per day = Rs 30
Therefore, earning of a tea stall owner in 10 days = Rs (10 30) = Rs 300
And his, earning in a month = Rs (30 30) = Rs 900
I got the answers by multiplication.
6. Find out: What is a loan?
(a) Have you ever heard of someone taking a loan? For what?
Ans. (a)Yes, I have heard of someone taking a loan. It is taken to buy a handcart.
(b) How much loan was taken?
Ans. (b)Rs 300 was taken as loan.
(c) How much money was paid back.
Hariya and Babu went to buy a handcart for Rs 300.
Ans. (c) Hariya:I have taken a loan of Rs 300 from a Bank for six months. I will pay Rs 51 every month to the bank.
Babu:But I have taken a loan of Rs 300 from Chunnilal. After six months, I will pay back Rs 360.
(d) Who has to pay back more- Hariya or Babu?
Ans. (d)In case of Hariya: Money paid back to the bank = Rs. 6 51 = Rs 306
In case of Babu: Money paid back to Chunnilal = Rs 360
Since, Rs 360 is more than Rs 300, therefore, Babu paid back more money.
7. (a) Have 9 rickshaws of my own. I give the rickshaws on rent, each of Rs 20 a day. On Sundays I do not take any money from them? How much does Kiran earn from 9 Rickshaws in a Day?
Ans. (a)For 1 rickshaw she gets Rs 20 per day.
So, for 9 rickshaws she will earn Rs 180.
(b) How did you do it?
Ans. (b)I did it by multiplying 20 and 9 (20 9=180).
8. In a week how much does Kiran earn from one rickshaw?
Ans.Since on Sundays Kiran does not take any money for rickshaw’s rent, therefore, Kiran earns in a week on one rickshaw at the rate of Rs 20 per day = Rs 6 20 = Rs 120.
9. Do it mentally and write the answers:
(a) 2 6= __
Ans. (a)2 6= 12.
(b) 20 6 = __
Ans. (b)20 6 = 120.
(c) 2 60 = __
Ans. (c)2 60 = 120.
(d) 3 42 = __
Ans. (d)3 42 = 126.
(e) 4 80 = __
Ans. (e)4 80 = 320.
(f) 4 81 = __
Ans. (f)4 81 = 324.
(g) 9 25 = __
Ans. (g)9 25 = 225.
(h) 31 9 = __
Ans. (h)31 9 = 279.
10. 4 81 is 4 more than 4 80. Am I right?
Ans.Yes.
11. How much Kiran will pay for 31 kg newspaper?
Ans.Kiran will pay for 31 kg newspaper = Rs (51 30 + 5 1) = Rs 155.
12.
(a) How much Kiran pay for 42 kg newspaper?
Ans. (a)Kiran will pay Rs (42 5) = Rs 210.
(b) Also find the costs of:
(i) 22 kg of plastic
Ans. (b) (i)Cost of 22 kg of plastic = Rs (22 10) = Rs 220.
(ii) 23 kg of wastepaper
Ans. (b) (ii)Cost of 23 kg of newspaper = Rs (23 4) = Rs 92.
(iii) 12 kg of iron.
Ans. (b) (iii)Cost of 12 kg of iron = Rs (12 12) = Rs 144.
13. Can you do this without writing? Guess the total money Kiran will pay to the junk collectors. Will it be: More than 600? Less than 600?
Ans.Less than 600.
14. Kiran bought 1 kg of plastic for Rs 10, but sold 1 kg plastic for Rs 12. How much money does she earn on selling 1 kg plastic?
Ans.Earning on selling 1 kg of plastic = Selling price – Cost price = Rs 12 – Rs 10 = Rs 2
So, earning on selling 63 kg of plastic = Rs 2 Rs 63
60 | 3 |
60 2 | 3 2 |
120 | 6 |
On adding the numbers in the last row = 120 + 6 = 126.
So, for 63 kg of plastic, Kiran earns = Rs 126.
15. How much money will Dinu pay for 32 kg iron?
Ans.The rate of 1 kg of iron is Rs 14. So, the cost for 32kg of iron is Rs 14 32.
We write as:
30 | 2 | |
10 | 30 10 | 2 10 |
300 | 20 | |
4 | 30 4 | 2 4 |
120 | 8 |
So, for 32 kg iron, Dinu will pay Rs 448.
16. Kiran buys 1 kg iron for Rs 12, but sells it for Rs 14. How much does she earn when she sells 32 kg iron?
Ans.Earning of selling 1 kg iron = Selling price -Cost price = Rs 14 – Rs 12 = Rs 2
So, earning on selling 32 kg of iron = Rs 2 32 of iron = Rs 2 32
We write as:
30 | 2 |
30 2 | 2 2 |
60 | 4 |
So, Kiran earns Rs 64 on the sale of 32 kg iron.
17. I bought 1 kg newspaper for Rs 5, but sold it for Rs 6. How much money did I earn by selling 152 kg of newspaper?
Ans.Rs 152.
18. How much money will Dinue pay for 4 kg brass? Guess the answer first.
Ans.The rate of 1 kg brass is Rs 170. So, the cost of 4 kg brass is Rs 170 4. We guess the answer to lie between Rs 600 and Rs 800.
We write as:
4 | 100 | 70 |
100 4 | 70 4 | |
400 | 280 |
So, for 4 kg brass Dinu will pay Kiran Rs 680.
19. First guess the answer then calculate:
(a) 37 18
Ans. (a)On guessing 37 18 may be = 740.
We write as:
30 | 7 | |
10 | 30 10 | 7 10 |
300 | 70 | |
8 | 30 8 | 7 8 |
240 | 56 |
Adding the numbers = 300 + 240 + 70 + 56 = 666
So, 37 18 = 666.
(b) 45 24
Ans. (b)On guessing 45 24 = 1080
We write as:
40 | 7 | |
20 | 40 20 | 5 20 |
800 | 100 | |
4 | 40 4 | 5 4 |
160 | 20 |
Adding the numbers = 800 + 160 + 100 + 20 = 1080
So, 45 24 = 1080
(c) 69 52
Ans. (c)On guessing 69 52 = 3588
We write as:
60 | 9 | |
50 | 60 50 | 9 50 |
3000 | 450 | |
2 | 60 2 | 9 2 |
120 | 18 |
Adding the numbers = 3000 + 120 + 450 + 18 = 3588
So, 69 52 = 3588.
(d) 77 55
Ans. (d)On guessing 77 55 = 4235
We write as:
70 | 7 | |
50 | 70 50 | 7 50 |
3500 | 350 | |
5 | 70 5 | 7 5 |
350 | 35 |
Adding the numbers = 3500 + 350 + 350 + 35 = 4235
So, 77 55 = 4235.
(e) 142 5
Ans. (e)On guessing 142 5 = 710
We write as:
100 | 40 | 2 | |
5 | 100 5 | 40 5 | 2 5 |
500 | 200 | 10 |
Adding the numbers = 500 + 200 + 10 = 710
So, 142 5= 710.
(f) 382 3
Ans. (f)On guessing 382 3 =1146
We write as:
300 | 80 | 2 | |
3 | 300 3 | 80 3 | 2 3 |
900 | 240 | 6 |
Adding the numbers = 900 + 240 + 6 = 1146
So, 382 3 = 1146
(g) 2 175
Ans. (g)On guessing 2 175 = 350
We write as:
100 | 70 | 5 | |
2 | 100 2 | 70 2 | 5 2 |
200 | 140 | 10 |
Adding the numbers = 200 + 140 + 10 = 350
So, 2 175 = 350.
(h)4 206
Ans. (h)On guessing 4 206 = 824
We write as:
200 | 0 | 6 | |
4 | 200 4 | 0 4 | 6 4 |
800 | 0 | 24 |
Adding the numbers = 800 + 0 + 24 = 824
So, 4 206 = 824.
Question. 880 - 88 is equal to
(a) 968
(b) 802
(c) 792
(d) 6
Answer : C
Question. What number comes in the box?
650 - ................. tens = 450
(a) 2
(b) 10
(c) 20
(d) 200
Answer : C
Question. 200 + 30 + 1 + 60 + 4 + 3 + 400 is equal to
(a) 2300
(b) 1490
(c) 1274
(d) 698
Answer : D
Question. In which of the following divisions will the answer be a 2-digit number?
(a) 400 divide by 2
(b) 408 divide by 4
(c) 428 divide by 4
(d) 426 divide by 6
Answer : D
Question. If each jar has 10 marbles, in all how many marbles are there in the box below?
(a) 328
(b) 211
(c) 53
(d) 31
Answer : D
Question. Which of these is a 2-rupee coin?
b
Question. If I add 60 to 325 and then subtract 40, the answer I get will be equal to
(a) 325 + 20
(b) 325 + 100
(c) 325 - 20
(d) 325 - 100
Answer : A
Question. 500 - 46 gives the same answer as 400 +?
(a) 46
(b) 54
(c) 64
(d) 146
Answer : B
Question. Each big box shown below contains 100 apples and each small box contains 10 apples. In all, how many apples are there in the boxes?
(a) 500
(b) 230
(c) 320
(d) 50
Answer : B
Question. Which symbol should go into the empty box to make this number sentence true?
75 + 9 .......... 19 + 65
(a) =
(b) >
(c) <
(d) none of these
Answer : A
Question. Ritu wants to buy this teddy for her sister. On counting the coins in her piggy bank, she finds that she has 84 one-rupee coins and 80 fifty-paise coins only. How much MORE money will she need to buy it?
(a) Rs.11
(b) Rs.51
(c) Rs.87
(d) Rs.93
Answer : B
Question. 23 + 300 = 180 + 23 +............ Which of the following is a correct way of finding the number that goes into the empty box above?
(a) subtract 23 from 180
(b) subtract 180 from 300
(c) subtract 180 from 300
(d) subtract 23 from 300
Answer : B
Question. Anu's doctor has told her to take one tablet like this every morning, noon and night for a week. How many tablets will Anu need for the whole week?
(a) 3 + 7
(b) 7 + 3
(c) 7 * 3
(d) 7 * 30
Answer : A
Question. Look at this poster from an ice cream shop Abdul bought one ice cream from the shop and paid with a 20-rupee note. If the shopkeeper returned Rs. 2 to him, which ice cream did Abdul buy?
(a) King Cone
(b) Ice Lolly
(c) Double Decker
(d) Sundae
Answer : A
Question. 100 – X > 40 Which of the following could be the number in X?
(a) 76
(b) 60
(c) 85
(d) 47
Answer : D
NCERT Solutions Class 4 Mathematics Chapter 1 Building With Bricks |
NCERT Solutions Class 4 Mathematics Chapter 2 Long And Short |
NCERT Solutions Class 4 Mathematics Chapter 3 A Trip To Bhopal |
NCERT Solutions Class 4 Mathematics Chapter 4 Tick Tick Tick |
NCERT Solutions Class 4 Mathematics Chapter 5 The Way The World Looks |
NCERT Solutions Class 4 Mathematics Chapter 6 The Junk Seller |
NCERT Solutions Class 4 Mathematics Chapter 7 Jugs And Mugs |
NCERT Solutions Class 4 Mathematics Chapter 8 Carts And Wheels |
NCERT Solutions Class 4 Mathematics Chapter 9 Halves And Quarters |
NCERT Solutions Class 4 Mathematics Chapter 10 Play With Patterns |
NCERT Solutions Class 4 Mathematics Chapter 11 Tables And Shares |
NCERT Solutions Class 4 Mathematics Chapter 12 How Heavy How Light |
NCERT Solutions Class 4 Mathematics Chapter 13 Fields And Fences |
NCERT Solutions Class 4 Mathematics Chapter 14 Smart Charts |
NCERT Solutions Class 4 Mathematics Chapter 6 The Junk Seller
NCERT Solutions Class 4 Mathematics Chapter 6 The Junk Seller is available on our website www.studiestoday.com for free download in Pdf. You can read the solutions to all questions given in your Class 4 Mathematics textbook online or you can easily download them in pdf.
Chapter 6 The Junk Seller Class 4 Mathematics NCERT Solutions
The Class 4 Mathematics NCERT Solutions Chapter 6 The Junk Seller are designed in a way that will help to improve the overall understanding of students. The answers to each question in Chapter 6 The Junk Seller of Mathematics Class 4 has been designed based on the latest syllabus released for the current year. We have also provided detailed explanations for all difficult topics in Chapter 6 The Junk Seller Class 4 chapter of Mathematics so that it can be easier for students to understand all answers.
NCERT Solutions Chapter 6 The Junk Seller Class 4 Mathematics
Class 4 Mathematics NCERT Solutions Chapter 6 The Junk Seller is a really good source using which the students can get more marks in exams. The same questions will be coming in your Class 4 Mathematics exam. Learn the Chapter 6 The Junk Seller questions and answers daily to get a higher score. Chapter 6 The Junk Seller of your Mathematics textbook has a lot of questions at the end of chapter to test the students understanding of the concepts taught in the chapter. Students have to solve the questions and refer to the step-by-step solutions provided by Mathematics teachers on studiestoday to get better problem-solving skills.
Chapter 6 The Junk Seller Class 4 NCERT Solution Mathematics
These solutions of Chapter 6 The Junk Seller NCERT Questions given in your textbook for Class 4 Mathematics have been designed to help students understand the difficult topics of Mathematics in an easy manner. These will also help to build a strong foundation in the Mathematics. There is a combination of theoretical and practical questions relating to all chapters in Mathematics to check the overall learning of the students of Class 4.
Class 4 NCERT Solution Mathematics Chapter 6 The Junk Seller
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