NCERT Solutions Class 4 Mathematics Chapter 13 Fields And Fences

NCERT Solutions Class 4 Mathematics Chapter 13 Fields And Fences have been provided below and is also available in Pdf for free download. The NCERT solutions for Class 4 Mathematics have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Class 4 by CBSE, NCERT and KVS. Questions given in NCERT book for Class 4 Mathematics are an important part of exams for Class 4 Mathematics and if answered properly can help you to get higher marks. Refer to more Chapter-wise answers for NCERT Class 4 Mathematics and also download more latest study material for all subjects. Chapter 13 Fields And Fences is an important topic in Class 4, please refer to answers provided below to help you score better in exams

Chapter 13 Fields And Fences Class 4 Mathematics NCERT Solutions

Class 4 Mathematics students should refer to the following NCERT questions with answers for Chapter 13 Fields And Fences in Class 4. These NCERT Solutions with answers for Class 4 Mathematics will come in exams and help you to score good marks

Chapter 13 Fields And Fences NCERT Solutions Class 4 Mathematics

NCERT Solutions for Class 4 Mathematics Math Magic for Chapter 13 Fields And Fences

1. I need a fence around my field. How much wire should I buy.

Ans. The length of the wire required for fencing the field is equal to the boundary of the field.


2. Can you find it from this picture?

Ans. Yes, I can find its boundary. It is equal to 21m + 15m + 9m + 9m = 54m of the field.


3. How much wire did Rahmat give Ganpat?

Ans. Rahmat gave Ganpat a wire of length 70m – 54 m = 16m.


4. How long is the boundary of Ganpat’s field?

Ans. Boundary of the Ganpat’s field = 18m + 9m + 15m + 15m + 9m = 66 metres.


5. How much wire will Ganpat need for his field?

Ans. Ganpat’s total requirement of wire = 66 metres

Length of wire given by Rahmat = 16 metres

Therefore, the length of more wire needed by Ganpat = (66-16) = 50 metres.
 

6. Here are the picture of some more fields. Find out which one has the biggest boundary.

(a)

Ans. Boundary = (24 + 15 + 6 + 15) metres= 60 metres

(b)

Ans. Boundary = (12 + 6 +6 + 3 +6 + 9) metres = 42 metres.

(c)

Ans. Boundary = (15 + 12 + 9) metres = 36 metres.

(d)

Ans. (d)Boundary = (9 + 15 + 15 + 9 + 15 + 15) metres = 78 metres.


7. Chandu’s father is called the “young old man” in his village. At 70 years age, he is fully fit. Do you know his secret? He goes for a walk around the field every morning. Everyday he takes four rounds of Chandu’s fields. What is the total distance he covers.

4 ___ = _____ m = ________ km

Ans. Boundary of Chandu’s field = 100 m + 150 m + 100 m + 150 m = 500m.

Total Distance covered by Chandu’s father = 4x Boundary of Chandu’s field

= 4 x 500m = 2000 m = 2 km.


8. Look at the picture of the table cloth and tell how much is used for one table cloth.

Ans. Length of lace = 2 x (1m 50 cm + 50 cm) = 2 x 2m = 4m.


9. How much lace will be used in 3 such table clothes? How much lace will be left in the roll?

Ans. Lace used for one table cloth = 1m 50 cm + 50 cm + 1m 50 cm + 50 cm = 4metres

Lace used for 3 such table cloths = 3 x 4 Lace used for on one table cloth

= 3 x 4 metres = 12 metres.

Lace left in the roll = Total Lace – Lace used = 100m – 12m = 88m.


10. Find out the length of the boundary of these shapes.

Ans. To find the length of the boundary, take a long piece of thread and carefully place it along the boundary of the shape. Cut out the exact length of the thread needed for covering the shape, starting from one point and coming back to the same point. On measuring the length of this thread, we obtain the length of this thread, we obtain boundary of the shape. Repeat the process for each shape.


11. Now count the square and find out:

(a) How many squares are there in each shape?

Ans. The number of complete squares in shape A is 1, in shape B is 2, in shape C is 3 and shape D is 2.

(b) Which shape covers the least number of squares?

Ans. The least number of complete squares are in shape A.

(c) Which shape covers the most number of squares?

Ans. Shape C has the most number of complete squares.


12. A square has a boundary of 12 cm.

(a) From the corner of this square, a small square of side 1 cm is cut off. Will the boundary of B be less or more? Find its length.

Ans. Boundary of B = 3cm + 2 cm + 1 cm + 2 cm +3 cm = 12cm

Since the boundary of A is also 12 cm.

So, the boundary of B is neither less nor more than that of A. But their boundaries are equal.

(b) If you cut 1 cm square to get shape C what will be the length of the boundary of C?

Ans. Boundary of C = 3cm + 3cm + 1cm + 1cm + 1 cm +1cm + 1cm + 3 cm = 14 cm.


13. (a) Find the length of the boundary of square D.

Ans. Length of the boundary of square D = 5cm + 5cm + 5cm + 5cm = 20cm

(b) The boundary of this square (1cm) is ___ + ____ + ____ + ____.

Ans. The boundary of this square (1cm) is 1cm + 1cm+ 1cm + 1cm = 4cm.

Yes, we can also say that the boundary is 4 x 1 cm.


14. A hockey field is 91 metres 40cm and 55 metres wide. How long is the boundary of the field?

Ans. Length of the boundary of a hockey field = 91m + 40cm +55m + 91m 40 cm +55m

= 292 m 80 cm


15. Usha and Valsamma are running a race. Usha is running on the inner circle. Valsamma is running on the outer circle. Valsamma runs after than Usha. But still loses the race. Can you guess why?

Ans. Since inner boundary is smaller than the outer boundary and as such Valsamma has to run for more distance, therefore, she loses the race.


16.Have you seen any race where runners start from different places – like in this picture? Guess why?

Ans. In order to make their running distances equal.


17. How will Neetu find out if the two gardens are equally big?

Ans. To find out if the two gardens are equally big:

Let us cover each garden with cardboards of same size without overlapping. We see that the same number of cardboards cover each garden. Therefore, we can say that the two gardens are equally big.


18. (a) How many small squares of size 1cm are there in this big green square?

Ans. There are 36 small squares of size 1 cm in the big green square.

(b) Can you think of a faster way to know the total number of small square without counting it?

Ans. Yes, there is a faster way to find the total number of small square. Just find: 6 x 6=36.


19. Guess how many squares of one centimetre can fill this rectangle? Checking your guess by completing the grid.

Ans. By completing the grid with squares of one centimetre, we find the number of such squares is 32.

 

Quesrion. Look at the three trees and the paths between them. Vani walks from to Tree 1 to Tree 2 and then to Tree 3 - covering 335 metres in all. Raj walks from Tree 2 to Tree 3, then to Tree 1, and finally returns to Tree 2 - covering 540 metres in all, How far is Tree 1 from Tree 3?

""NCERT-Solutions-Class4-Mathematics-Chapter-13-Fields-And-Fences-3

(a) 875 metres
(b) 215 metres
(c) 205 metres
(d) (we can't say)

Answer : C

Quesrion. How many squares in the grid below do NOT have cross marks (X) in them?

""NCERT-Solutions-Class4-Mathematics-Chapter-13-Fields-And-Fences-2

(a) 95
(b) 76
(c) 67
(d) 59

Answer : C

Quesrion. What is ............ if 8 x 9 = 2 x ............ x 9 ?
(a) 32
(b) 4
(c) 3
(d) 5

Answer : B

Quesrion. See the figure given here. I have 2 matchsticks. I want to place them in the above figure in such a way that there are EXACTLY 2 matchsticks inside the circle but ONLY 1 inside the rectangle. How should I place the matchsticks?

""NCERT-Solutions-Class4-Mathematics-Chapter-13-Fields-And-Fences-1

Answer : D

Quesrion. In which of the following figures exactly three circles are there?

""NCERT-Solutions-Class4-Mathematics-Chapter-13-Fields-And-Fences

Answer : A

NCERT Solutions Class 4 Mathematics Chapter 13 Fields And Fences

NCERT Solutions Class 4 Mathematics Chapter 13 Fields And Fences is available on our website www.studiestoday.com for free download in Pdf. You can read the solutions to all questions given in your Class 4 Mathematics textbook online or you can easily download them in pdf.

Chapter 13 Fields And Fences Class 4 Mathematics NCERT Solutions

The Class 4 Mathematics NCERT Solutions Chapter 13 Fields And Fences are designed in a way that will help to improve the overall understanding of students. The answers to each question in Chapter 13 Fields And Fences of Mathematics Class 4 has been designed based on the latest syllabus released for the current year. We have also provided detailed explanations for all difficult topics in Chapter 13 Fields And Fences Class 4 chapter of Mathematics so that it can be easier for students to understand all answers.

NCERT Solutions Chapter 13 Fields And Fences Class 4 Mathematics

Class 4 Mathematics NCERT Solutions Chapter 13 Fields And Fences is a really good source using which the students can get more marks in exams. The same questions will be coming in your Class 4 Mathematics exam. Learn the Chapter 13 Fields And Fences questions and answers daily to get a higher score. Chapter 13 Fields And Fences of your Mathematics textbook has a lot of questions at the end of chapter to test the students understanding of the concepts taught in the chapter. Students have to solve the questions and refer to the step-by-step solutions provided by Mathematics teachers on studiestoday to get better problem-solving skills.

Chapter 13 Fields And Fences Class 4 NCERT Solution Mathematics

These solutions of Chapter 13 Fields And Fences NCERT Questions given in your textbook for Class 4 Mathematics have been designed to help students understand the difficult topics of Mathematics in an easy manner. These will also help to build a strong foundation in the Mathematics. There is a combination of theoretical and practical questions relating to all chapters in Mathematics to check the overall learning of the students of Class 4.

Class 4 NCERT Solution Mathematics Chapter 13 Fields And Fences

NCERT Solutions Class 4 Mathematics Chapter 13 Fields And Fences detailed answers are given with the objective of helping students compare their answers with the example. NCERT solutions for Class 4 Mathematics provide a strong foundation for every chapter. They ensure a smooth and easy knowledge of Revision notes for Class 4 Mathematics. As suggested by the HRD ministry, they will perform a major role in JEE. Students can easily download these solutions and use them to prepare for upcoming exams and also go through the Question Papers for Class 4 Mathematics to clarify all doubts

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