CBSE Class 12 Chemistry Solutions Chapter Notes

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Revision Notes for Class 12 Chemistry Unit 02 Solutions

Class 12 Chemistry students should refer to the following concepts and notes for Unit 02 Solutions in Class 12. These exam notes for Class 12 Chemistry will be very useful for upcoming class tests and examinations and help you to score good marks

Unit 02 Solutions Notes Class 12 Chemistry

 

Ch. 2: Solutions 

Chemistry

Top formulae

1. Mass percentage of a component =Mass of component in solution / Toal mass of solution *100

2. Volume percentage of a component = Volume of component/ 100 Total volume of solution *100 

3. Mole fraction of a component (x) = Number ofmoles of component  / Total number ofmoles of all components 

4. ppm=  Number of parts of component / Total number of parts of all components of solution *106 

5.  Molarity=Number of moles of solute / Volumeof solution in litres 

6.  Molarity=Number of moles of solute / Mass of solvent in kilograms  

7. Normality=Number of gram equivalent of solute / Volumeof solution in litres 

8. p10 - p1 /p10 =x2 

9. ΔT = Tb- Tbo

ΔTb = Kb*1000*W2 /M2* w1

10. ΔT =Tfo -Tf

ΔTf = Kf*1000*w2 /M2*w1

11∏ = CRT

12. M2 =w2 RT / ∏V 

class_12_chemistry_concept_7

Key Learnings

1. Solutions are the homogeneous mixtures of two or more than two components.

2. Binary solution: A solution having two components is called a binary solution. Components of a binary solution are solute and solvent.

a. When the solvent is in solid state, solution is called solid solution.

b. When the solvent is in liquid state, solution is called liquid solution.

c. When the solvent is in gaseous state, solution is called gaseous solution.

3. Concentration is the amount of solute in given amount of solution.

4. Mass by volume percentage (w/v): Mass of the solute dissolved in 100 mL of solution.

5. Molality (m) is the number of moles of solute present in 1kg of solvent.

6. Molarity (M) is the number of moles of solute present in 1L of solution.

7. Normality is the number of gram equivalent of solute dissolved per litre of solution.

8. Solubility is its maximum amount that can be dissolved in a specified amount of solvent at a specified temperature.

9. A solution in which no more solute can be dissolved at the same temperature and pressure is called a saturated solution.

10. In a nearly saturated solution if dissolution process is an endothermic process, solubility increases with increase in temperature.

11. In a nearly saturated solution if dissolution process is an exothermic process, solubility decreases with increase in temperature.

12. Henry’s Law: The law states at a constant temperature the solubility of gas in a liquid is directly proportional to the pressure of gas. Henry’s law can also be stated as the partial pressure of gas in vapour phase is proportional to the mole fraction of the gas in the solution.

 

P = KH x
13. When a non-volatile solute is dissolved in a volatile solvent, the vapour pressure of solution is less than that of pure solvent.

14. According to Raoult’s law for a solution of volatile liquids the partial vapour pressure of each component in the solution is directly proportional to its mole fraction.
p1 = po1 x1 ; p2 = po2 x2
Using Dalton’s law of partial pressure the total pressure of solution is calculated.

15. On comparison of Raoult’ law and Henry’s law, it is observed that the partial pressure of volatile component or gas is directly proportional to its mole fraction in solution. In case of Henry’s Law the proportionality constant is KH and it is different from p10 which is partial pressure of pure component. Raoult’s Law becomes a special case of Henry’s Law when KH becomes equal to p10 in Henry’s law.

16. Liquid –liquid solutions can be classified into ideal and non-ideal solutions on basis of Raoult’s Law.

CBSE Class 12 Chemistry - Solutions Chapter Notes

 

18. Azeotropes are binary mixtures having same composition in liquid and vapour phase and boil at constant temperature. Liquids forming azeotrope cannot be separated by fractional distillation.

19. There are two types of azeotropes called minimum boiling azeotrope and maximum boiling azeotrope.

20. The solutions which show a large positive deviation from Raoult’s law form minimum boiling azeotrope at a specific composition.

21. The solutions that show large negative deviation from Raoult’s law form maximum boiling azeotrope at a specific composition.

22. Properties of solution which depends on only the number of solute particles but not on the nature of solute are called colligative properties.

23. There are four colligative properties:
a. Relative lowering of vapour pressure
b. Eleveation of boiling point
c. Depression of freezing point
d. Osmotic pressure

24. Relative lowering of vapour pressure: Difference in the vapour pressure of pure solvent ( o1 p ) and solution ( 1 p ) represents lowering in vapour pressure ( o1 p - 1 p ). Dividing lowering in vapour pressure by vapour pressure of pure solvent is called relative lowering of vapour pressure 

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CBSE Class 12 Chemistry Unit 02 Solutions Notes

We hope you liked the above notes for topic Unit 02 Solutions which has been designed as per the latest syllabus for Class 12 Chemistry released by CBSE. Students of Class 12 should download and practice the above notes for Class 12 Chemistry regularly. All revision notes have been designed for Chemistry by referring to the most important topics which the students should learn to get better marks in examinations. Our team of expert teachers have referred to the NCERT book for Class 12 Chemistry to design the Chemistry Class 12 notes. After reading the notes which have been developed as per the latest books also refer to the NCERT solutions for Class 12 Chemistry provided by our teachers. We have also provided a lot of MCQ questions for Class 12 Chemistry in the notes so that you can learn the concepts and also solve questions relating to the topics. We have also provided a lot of Worksheets for Class 12 Chemistry which you can use to further make yourself stronger in Chemistry.

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