NEET Physics Energy in Simple Harmonic Motion MCQs

a) square of amplitude of motion

b) velocity in equilibrium position

c) frequency of oscillation

d) displacement from equilibrium position

Answer: square of amplitude of motion

Question:  The potential energy of a particle (U_x) executing S.H.M. is given by

a)

b)

c)

d)

Answer:

Question:

a)

b)

c)

d)

Answer:

Question: Which of the following is true about total mechanical energy of SHM ?

a) It is never zero

b) It is always zero

c) It is zero at extreme position

d) It is zero at mean position

Answer: It is never zero

Question:  The total mechanical energy of a harmonic oscillator is given as

a)

b)

c)

d)

Answer:

Question: Assertion : The graph of total energy of a particle in SHM w.r.t. position is a straight line with zero slope.
Reason : Total energy of particle in SHM remains constant throughout its motion

a) Assertion is correct, reason is correct; reason is a correct explanation for assertion.

b) Assertion is correct, reason is correct; reason is not a correct explanation for assertion

c) Assertion is correct, reason is incorrect

d) Assertion is incorrect, reason is correct

Answer: Assertion is correct, reason is correct; reason is a correct explanation for assertion.

Question:  In S.H.M. the ratio of kinetic energy at mean position to the potential energy when the displacement is half of the amplitude is

a)

b)

c)

d)

Answer:

Question:   Starting from the origin a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy?

a)

b)

c)

d)

Answer:

Question:

a)

b)

c)

d) None of these

Answer:

Question:  If < E > and < U > denote the average kinetic and the average potential energies respectively of mass describing a simple harmonic motion, over one period, then the correct relation is

a) < E > = < U >

b) < E > = –2< U >

c) < E > = 2< U >

d) < E > = – < U >

Answer: < E > = < U >

Question:  What do you conclude from the graph about the frequency of KE, PE and SHM ?

a) Frequency of KE and PE is double the frequency of SHM.

b) Frequency of KE and PE is four times the frequency SHM.

c) Frequency of PE is double the frequency of K.E.

d) Frequency of KE and PE is equal to the frequency of SHM.

Answer:  Frequency of KE and PE is double the frequency of SHM.

Question:

a)

b)

c)

d)

Answer:

Question: A mass of 4 kg suspended from a spring of force constant 800 N m^–1 executes simple harmonic oscillations. If the total energy of the oscillator is 4 J, the maximum acceleration (in m s^–2) of the mass is

a) 20

b) 45

c) 15

d) 5

Answer: 20

Question:  A particle of mass m executes simple harmonic motion with amplitude a and frequency n. The average kinetic energy during its motion from the position of equilibrium to the end is

a)

b)

c)

d)

Answer:

Question:

a) I, III

b) II, IV

c) II, III

d) I, IV

Answer: I, III