CBSE Class 10 Science Human Eye and Colorful World Assignment Set A

Read and download free pdf of CBSE Class 10 Science Human Eye and Colorful World Assignment Set A. Get printable school Assignments for Class 10 Science. Class 10 students should practise questions and answers given here for Chapter 11 Human Eyes And Colourful World Science in Class 10 which will help them to strengthen their understanding of all important topics. Students should also download free pdf of Printable Worksheets for Class 10 Science prepared as per the latest books and syllabus issued by NCERT, CBSE, KVS and do problems daily to score better marks in tests and examinations

Assignment for Class 10 Science Chapter 11 Human Eyes And Colourful World

Class 10 Science students should refer to the following printable assignment in Pdf for Chapter 11 Human Eyes And Colourful World in Class 10. This test paper with questions and answers for Class 10 Science will be very useful for exams and help you to score good marks

Chapter 11 Human Eyes And Colourful World Class 10 Science Assignment

Question. To get line spectrum, the substances are excited in their
(a) solid state
(b) molecular state
(c) gaseous state
(d) atomic state
Answer : D

Question. Sometimes blurred and less sharply defined images are formed. This defect is called
(a) Chromatic aberration
(b) Spherical aberration
(c) Blurred lens
(d) None of the above
Answer : B


Question. A prism ABC (with BC as base) is placed in different orientations. A narrow beam of white light is incident on the prism as shown in figure. In which of the following cases, after dispersion, the sixth colour from the top corresponds to the colour of the sun?

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(a) (I)
(b) (II)
(c) (III)
(d) (IV)
Answer : B

Question. A glass slab is placed over a page on which the word VIBGYOR is printed with each letter in corresponding colour. Then, which of the following is correct?
(a) The images of all the letters will be in the same place as that on paper
(b) Letter V is raised more
(c) Letter R is raised more
(d) None of the above
Answer : B

Question. For a healthy eye, the rays of light entering the eye form a sharp image on retina. For a myopic eye, the rays from distant objects focus in front of the retina forming a blurred image. Which of the following lenses  shown below will help to correct myopia?
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Answer : D

Question. The following one is not a primary colour
(a) Yellow
(b) Red
(c) Green
(d) Blue
Answer : A

Question. In given figure, a light ray AB is incident normally on one face PQ of an equilateral glass prism. Find out the angles at faces PQ and PR.
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(a) 60c
(b) 30c
(c) 45c
(d) 90c
Answer : A

Question. A person cannot see objects clearly which are nearer than 75 cms from his eyes, the disease he suffering from is
(a) Astigmatism
(b) Myopia
(c) Hypermetropia
(d) Presbyopia
Answer : C

Question. Light rays are deviated by a prism
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The deviation angle d is measured for light rays of different frequency, including blue light and red light. Which graph is correct?

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Answer : D

Question. A person with a myopic eye cannot see object beyond -1.2m distinctly. The power of the corrective lens used to restore proper vision is
(a) -0.83 D
(b) -0.92 D
(c) +0.21D
(d) +0.91D
Answer : A

Question. Fraunhofer lines in the sun’s spectrum are present because
(a) Vapours of certain elements present in the atmosphere absorb certain colours
(b) The temperature of the sun is very high 
(c) The sun does emit certain light
(d) Certain elements present in the sun interfere
Answer : D

Question. When a mirror is rotated an angle the reflected ray moves through double that angle, the instrument based on the above principle is
(a) Periscope
(b) Odometer
(c) Refractometer
(d) Sextant
Answer : D

Question. The splitting of white light into several colours on passing through a glass prism is due to
(a) refraction
(b) reflection
(c) interference
(d) diffraction
Answer : A

Question. At sun rise or at sun set the sun appears to be reddish while at mid-day it looks white. This is because
(a) Scattering due to dust particles and air molecules causes this phenomenon
(b) The sun is cooler at sun rise or at sunset
(c) Refraction causes this phenomenon
(d) Diffraction sends red rays to the earth at these times.
Answer : A

Question. The frequency of light whose wavelength is 5000 Ac is
(a) 15#1013 cycles per second
(b) 5000 cycles per second
(c) 6#1014 cycles per second
(d) 15#1016 cycles per second
Answer : C

Question : The far point of a healthy person is 
a. 0.15m
b. Infinity
c. 100m.
d. 15cm
Answer : B
Explanation: The far point is infinity for normal eye. It is the farthest point upto which the eye can see object clearly.
 
Question :  Ability of the eye lens to adjust its focal length is called 
a. Accommodation
b. None of these
c. Power
d. Adjustment
Answer : A
Explanation: The ability of the eye to focus both near and distant objects, by adjusting the focal length of the eye lens, is called the accommodation of the eye.
 
Question : At noon the sun appears white as
(a) light is least scattered.
(b) All the colors of the white light are scattered away.
(c) Blue color is scattered the most.
(d) Red color is scattered the most.
Answer : A
 
Question. A light ray is incident perpendicularly to one face of a 90c prism and is totally internally reflected at the glass-air interface. If the angle of reflection is 45c, we conclude that the refractive index
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Answer : B

Question : Which of the following phenomena contributes significantly to the reddish appearance of the sun at sunrise or sunset?
(a) Dispersion of light
(b) Scattering of light
(c) Total internal reflection of light
(d) Reflection of light from the earth.
Answer : B

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Identify the wrong description of the above figures
(a) 1 represents far-sightedness
(b) 2 correction for short sightedness
(c) 3 represents far sightedness
(d) 4 correction for far-sightedness
Answer : A

Question : While performing the experiment to trace the path of a ray of light passing through a glass prism, four students marked the incident ray and the emergent ray in their diagrams in the manner shown below.

 Class 10 Science Human Eyes And Colourful World_3

The correct path of the rays has been shown by:
(a) I
(b) II
(c) III
(d) IV
Answer : C

 

Matching Questions

Question. 

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Answer : A-s, B-r, p, C-q, D-q

Question. Column II gives lens that can be use to correct the defect of vision given in column I, match them correctly.

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Answer : A-q, B-p, C-r, D-s

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Answer : (a) A-s, r, B-r, p, C-q, D-q

Question. Angle of deviation is given in Column-I and ray diagram for angle of deviation in Column -II

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Answer : (a) A-t, B-p, C- q, s, D-r

 

Very Short Answer

 
Question :  What is the function of rods on the retina ? 
Answer : Rods are sensitive to light. More the intensity of light, more are they excited.
 
Question :  What is the relation between intensity of scattered light and its amplitude? 
Answer :  The intensity of scattered light is directly proportional to the square of the amplitude 
a. of scattered light, i.e 
 Im-34
means greater the amplitude greater will be intensity of refraction and vice versa.

Question : Which phenomenon is responsible for making the path of light visible?
Answer :  Tyndall effect is responsible for making the path of light visible. 

Question : What will the color of the sky be for an astronaut staying in the international space station orbiting the earth?
Answer :  For an astronaut staying in the international space station orbiting the Earth the color of the sky will be black because the light reaching it does not scatter.

  

Short Answer 

 
Question : Why are we not able to see the object clearly for some time when we enter bright light to a room with dim light ? 
Answer :  The pupil of the eye acts as a variable aperture whose size can be varied with the help of the iris. When the light is very bright, the iris contracts the pupil to allow less light to enter the eye. However in dim light the iris expands the pupil to allow more light to enter the eye. When we enter from a bright light area to a dim light area, the pupil is  not able to expand quickly to allow more light into the eye. We are therefore not able to see the objects in dim light room momentarily. 

Question : When white light passes through a glass prism; seven colors namely red, orange, yellow, green, blue, indigo and violet are seen on the white screen. All these colors have different angles of deviation. Explain why?
Answer :  Speed of color in a medium depends upon its wavelength. All the colors have different wavelength. The red color has the longest wavelength and violet color has the last wavelength. Therefore, red color has the highest speed in the glass prism and the violet color has the lowest speed in the glass prism. Hence, all colors of white light are refracted by different amounts while passing through the glass prism. Therefore, all the colors have different angles of deviations. 

Question : (a) What is hypermetropia?
(b) What are the two causes of the defect of vision?
(c) How can this defect of the eye be corrected? Illustrate your answer by drawing ray diagrams to show the formation of image by
(i) a hypermetropic eye
(ii) a hypermetropic eye corrected with a suitable lens.
Answer : (a) Hypermetropia: It is also called long-sightedness. The person with this eye defect can see far off objects but cannot see nearby objects clearly. The image is formed beyond retina.
(b) Two causes
(i) Focal length of the lens increases
(ii) Eye ball becomes smaller
(c) Correction: It can be corrected by using a convex lens. It is a converging lens which shifts the image of the object on the retina.

Question :  Explain why the planets do not twinkle? 
Answer :  As Planets can be considered as a collection of a large number of point-size sources of light, Planets do not twinkle because they appear larger in size than the stars as they are relatively closer to earth. The different parts of these planets produce either brighter or dimmer effect in such a way that the average of brighter and dimmer effect is zero. Hence, the twinkling effects of the planets are nullified and they do not twinkle.

Question : What is hypermetropia? State the two causes of hypermetropia. With the help of ray diagram show:
(i) the eye defect hypermetropia.
(ii) correction of hypermetropia by using a lens
Ans.
Hypermetropia: Defect of a vision in which a person can see distant objects clearly but cannot see nearby objects clearly.
Causes: (a) Focal length of the eye lens is too large.
(b) Eye ball has become too small.

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Long Answer

Question :  A 14 year old student is not able to see clearly the questions written of the black board placed at a distance of 5 m from him. 
a. Name the defect of vision he is suffering from?
b. Draw the diagram to show this defect?
c. Name the type of lens used to correct this defect?
d. Name two possible cause of this defect.
e. Draw the diagram to show how this defect can be corrected.
Answer : 
 a. The student is suffering from myopia.
Im-35
 
c. Concave lens
i. Decrease in the focal length of the eye lens
ii. Eye ball gets elongated.
Im-36
 

 

Question : A narrow beam PQ of white light is passing through a glass prism ABC as shown in the diagram.
(i) Write the name and cause of the phenomenon observed.
(ii) Where else in nature is this phenomenon observed?
(iii) Based on this observation, state the conclusion which can be drawn about the constituents of white light.

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Answer : 
 (i) The phenomenon of splitting of white light into seven colors on passing through a glass-prism is called dispersion of light. The dispersion of white light occurs because colors of white light travel at different speeds through the glass prism.
(ii) Formation of rainbow is an example of dispersion of white light in nature.
(iii) The formation of spectrum of seven colors shows that white light is made up of lights of seven different colors mixed together. That is, white light is a mixture of seven colors (or seven colored lights), i.e., red, orange, yellow, green, blue, indigo and violet.

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Chapter 01 Chemical Reactions and Equations
CBSE Class 10 Science Chemical Reactions and Equations Assignment

CBSE Class 10 Science Chapter 11 Human Eyes And Colourful World Assignment

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