RD Sharma Solutions Class 6 Maths Chapter 6 Fractions

Read RD Sharma Solutions Class 6 Maths Chapter 6 Fractions below, students should study RD Sharma class 6 Mathematics available on Studiestoday.com with solved questions and answers. These chapter wise answers for class 6 Mathematics have been prepared by teacher of Grade 6. These RD Sharma class 6 Solutions have been designed as per the latest NCERT syllabus for class 6 and if practiced thoroughly can help you to score good marks in standard 6 Mathematics class tests and examinations

Exercise 6.1

 

Question 1:  Write the fraction representing the shaded portion:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-

Solution 1: 
As we know :
Fraction of the shaded portion = (Number of shaded parts)/(Total number of parts)
 
(i) Number of total parts = 3
Number of Shaded parts = 2
So, Fraction of the shaded portion = 2/3
 
(ii) Number of total parts = 15
Number of Shaded parts = 11
So, Fraction of the shaded portion = 11/15
 
(iii) Number of total parts = 9
Number of Shaded parts = 8
So, Fraction of the shaded portion = 8/9
 
(iv) Number of total parts = 7
Number of Shaded parts = 3
So, Fraction of the shaded portion = 3/7
 
(v)Number of total parts = 9
Number of Shaded parts = 4
So, Fraction of the shaded portion = 4/9
 
(vi) Number of total parts = 4
Number of Shaded parts = 2
So, Fraction of the shaded portion = 2/4 = 1/2
 
(vii) Number of total parts = 2
Number of Shaded parts = 1
So, Fraction of the shaded portion = 1/2
 
(viii) Number of total parts = 5
Number of Shaded parts = 1
So, Fraction of the shaded portion = 1/5
 
(ix) Number of total parts = 4
Number of Shaded parts = 1
So, Fraction of the shaded portion = 1/4
 

Question 2:  Write the fraction representing the shaded parts:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-1

Solution 2: 
As we know:
Fraction of the shaded portion = (Number of shaded parts)/(Total number of parts)
(i) Number of total parts = 9
Number of Shaded parts = 3
So, Fraction of the shaded portion = 3/(9 ) =1/3
 
(ii) Number of total parts = 8
Number of Shaded parts = 4
So, Fraction of the shaded portion = 4/8 =1/2
 
(iii) Number of total parts = 12
Number of Shaded parts = 3
So, Fraction of the shaded portion = 3/12 =1/4
 
(iv) Number of total parts = 10
Number of Shaded parts = 5
So, Fraction of the shaded portion = 5/10 =1/2
 
 
Question 3: Write the fraction representing the shaded portion:
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-2
Solution 3: 
As We know :
Fraction of the shaded portion = (Number of shaded parts)/(Total number of parts)
(i) Number of total parts = 2
Number of Shaded parts = 1
So, Fraction of the shaded portion = 1/2
 
(ii) Number of total parts = 8
Number of Shaded parts = 4
So, Fraction of the shaded portion = 4/8 =1/2
 
 
Question 4:  Colour the part according to the fraction given:
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-3

Solution 4: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-4


Question 5:  What fraction of an hour is 20 minutes? 
Solution 5: 
As we know:
There are 60 Minutes in an hour.
So, 20 minutes of an hour = 20/60 = 1/3 
Hence, 1/3 of an hour is 20 minutes.
 
Question 6: Write the natural numbers from 2 to 12. What fraction of them are prime numbers? 
Solution 6:
As we know that the natural numbers from 2 to 12 are:
2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12.
The prime numbers from 2 to 12 are
2, 3, 5, 7 and 11.
So, there are 5 prime numbers are among the 11 numbers.
Hence, 5/11 of them are prime numbers.
 
Question 7:  Write the natural numbers from 102 to 113. What fraction of them are prime numbers? 
Solution 7: 
As we know that the natural numbers from 102 to 113 are:
102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112 and 113
The prime numbers from 102 to 113 are
103, 107, 109 and 113
So, there are 4 prime numbers are among the 12 numbers.
Hence,  4/12 =1/3  fraction of them are prime numbers.
 
Question 8:  Mukesh has a box of 24 pencils. He gives half of them to Sunita. How many does Sunita get? How many does Mukesh still have?
Solution 8: 
Mukesh has pencils box = 24
He gives half of pencils box to Sunita = 24/2 = 12 pencils box 
So, the number of pencils box Mukesh still has = 24 – 12 = 12
Hence, Mukesh gives 12 pencils box to Sunita and still has 12 pencils box.
 
Question 9:  Kavita has 44 cassettes. She gives 3/4  of them to Sonia. How many does Sonia get? How many does Kavita keep? 
Solution 9: 
Kavita has cassettes = 44
She gives 3/4  of them to Sonia = 3/4  /44 = 33
So, the number of cassettes Kavita keeps = 44 – 33 = 11
Hence, Kavita gives 33 cassettes to Sonia and still have 11 cassettes.
 
Question 10:  Shikhas has three frocks that she wears when playing. The material is good, but the colours are faded. Her mother buys some blue dye and uses it on two of the frocks. What fraction of all of the Shikha play frocks did her mother dye? 
Solution 10: 
Number of frocks of Shikha = 3
Number of frocks Shikha’s mother dyed = 2
So, the fraction of dyed frocks = 2/3
Hence, Shikha’s mother dyed 2/3 fraction of all of Shikha’s play frocks. 2/5


Exercise 6.2

Question 1:  Represent  on a number line. 

Solution 1:   The fraction of is represented on a number line as given below:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-5

 

Question 2:  Represent 0/10,1/10,5/10 and 10/10  on a number line.
 
Solution 2: 
The fraction of 0/10,1/10,5/10 and 10/10   are represented on a number line as given below:
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-6 

 

Question 3:   Represent 2/7,5/7,and  6/7 on a number line.
 
Solution 3: 
The fraction of  2/7,5/7,and  6/7 are represented on a number line as given below:
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-7
 
 
Question 4: How many fractions lie between 0 and 1. 
Solution 4: 
Number of Fractions which are lie between 0 and 1 are Infinite.
This can be done by taking numerator less than denominator in a fraction.
 
Question 5:  Represent 0/8 and 8/8 on a number line. 
Solution 5: 
The fraction  of  0/8 and 8/8 are represented on a number line as given below:
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-8
 
Exercise 6.3
  
Question 1:  Write each of the following divisions as fractions:
(i) 6 ÷ 3
(ii) 25 ÷ 5
(iii) 125 ÷ 50
(iv) 55 ÷ 11 
Solution 1: 
(i) 6 ÷ 3 = fraction can be written as 6/3.
(ii)25 ÷ 5 = fractions can be written as 25/5.
(iii) 125 ÷ 50 = fractions can be written as 125/50.
(iv) 55 ÷ 11 = fractions can be written as 55/11.
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-9
 
Exercise 6.4

Question 1:  Convert each of the following into a mixed fraction:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-10

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-11


Question 2:  Convert each of the following into an improper fraction:

(i) 7 ¼

(ii) 8 5/7

(iii) 5 3/10

(iv) 12 7/15 

Solution 2: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-12

Exercise 6.5

 

Question 1:   Write the fractions and check whether they are equivalent or not:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-13

Solution 1: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-14

 

Question 2:  Write the fractions and match fractions in Column I with the equivalent fractions in Column II.

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-15

Solution 2: 

 RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-16

 

Question 3:  Replace ☐ in each of the following by the correct number:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-17

Solution 3: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-18

 

Question 4:   Find the equivalent fraction of 3/5  having:
(i) Numerator 9
(ii) Denominator 30
(iii) Numerator 21
(iv) denominator 40
 
Solution 4: 
(i) Given fraction is  3/5
If we consider numerator = 9
As we know: 3 × 3 = 9
So, we will Multiply the numerator and denominator of the 3/5 by 3
3/5× 3/3  =  9/15
(ii) Given fraction = 3/5
If we consider denominator = 30
As we know: 5 × 6 = 30
So, we will Multiply the numerator and denominator of the 3/5 by 6
3/5× 6/6= 18/30
 
(iii) Given fraction = 3/5
If we consider numerator = 21
As we know: 3 × 7 = 21
Multiply the numerator and denominator of the 3/5 by 7
3/5× 7/7  = 21/35
 
(iv) Given fraction = 3/5
If we consider denominator = 40
As we know: 5 × 8 = 40
Multiply the numerator and denominator of the 3/5 by 8
3/5× 8/8= 24/40


Question 5:   Find the fraction equivalent to 45/60, having:
(i) Numerator 15
(ii) Denominator 4
(iii) Denominator 240
(iv) Numerator 135
 
Solution 5: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-19


Question 6:   Find the fraction equivalent of  35/42, having:
(i) Numerator 15
(ii) Denominator 18
(iii) Denominator 30
(iv) Numerator 30
 
Solution 6: 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-20
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-21


Question 7:  Check whether the given fractions are equivalent:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-22

Solution 7: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-23

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-24


Question 8:  Match the equivalent fractions and write another 2 for each:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-25

Solution 8: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-26

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-26


Question 9:  Write some equivalent fractions which contain all digits from 1 to 9 once only. 

Solution 9:   There are those equivalent fractions which contain all digits from 1 to 9 once only are:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-28

 

Question 10:  Ravish had 20 pencils, Shikha had 50 pencils and Priya had 80 pencils. After 4 months, Ravish used up 10 pencils, Shikha used up 25 pencils and Priya used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of their pencils? 

Solution 10: 

Number of pencils Ravish had = 20 pencils

Number of pencils Ravish used = 10 pencils

We take HCF of 10 and 20 by dividing the numerator and denominator

We get the fraction of pencils used = (10 ÷ 10)/ (20 ÷ 10) = 1/2

Number of pencils Shikha had = 50

Number of pencils used by Shikha = 25

We take HCF of 25 and 50 by dividing the numerator and denominator

We get the fraction of pencils used = (25 ÷ 25)/ (50 ÷ 25) = 1/2

Number of pencils Priya had = 80

Number of pencils used by Priya = 40

We take HCF of 40 and 80 by dividing the numerator and denominator

We get the fraction of pencils used = (40 ÷ 40)/ (80 ÷ 40) = 1/2

Yes, Ravish, Shikha and Priya has used an same fraction of their pencils.

 

 Exercise 6.6

Question 1:  Reduce each of the following fractions to its lowest term (simplest form):

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-29

Solution 1:


RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-30

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-32

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-33

 

Question 2:  Simplify each of the following to its lowest term:                        

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-34

Solution 2:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-35
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-36
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-37

Exercise 6.7

 

Question 1:  Write each fraction. Arrange them in ascending and descending order using correct sign <, =, > between the fractions:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-38

Solution 1: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-39

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-40

 

 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-41

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-42

 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-43

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-44

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-45

 

Question 5:  The following fractions represent just three different numbers. Separate them in to three groups of equal fractions by changing each one to its simplest form:

Solution  5:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-47

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-48

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-49


RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-50


Question 6:   Isha read 25 pages of a book containing 100 pages. Nagma read ½ of the same book. Who read less? 

Solution 6:    Number of pages in the book = 100

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-51

 

Question 7:  Arrange the following fractions in the ascending order:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-52


Solution 7: 


RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-53

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-54

 

Question 8:  Arrange in descending order in each of the following using the symbol >:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-55


Solution 8:


RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-56

 

Question 9:  Find answers to the following. Write and indicate how you solved them.

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-57

Solution 9: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-58 

 Exercise 6.8

Question 1:  Write these fractions appropriately as additions or subtractions:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-59

Solution 1: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-60

 

Question 2:  Solve:

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-61

Solution 2: 

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-62

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-63

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-64

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-65

 

Question 3:  Shikha painted 1/5 of the wall space in her room. Her brother Ravish helped and painted 3/5 of the wall space. How much did they paint together? How much the room is left unpainted?
 
Solution 3: 

 RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-66

 

Question 4:   Ramesh bought 2 ½  kg sugar whereas Rohit bought 3 ½kg of sugar. Find the total amount of sugar bought by both of them. 

Solution 4: 


RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-67

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A1

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A2

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A3

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A4

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A5

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A6

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A7

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A8

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A9

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A10

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A11

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A12

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A13


RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A14

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A15

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A16

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A17

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A18

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A19

RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A20


Question 7: Savita bought 2/5 m of ribbon and Kavita 3/4 m of the ribbon. What was the total length of the ribbon they bought?
 
Solution 7: 

Length of ribbon Kavita bought = 3/4 m
Length of ribbon Savita bought = 2/5 m
So, the total length of ribbon Kavita and Savita bought = 2/5 + 3/4
We know that the LCM of 5 and 4 is 20
So, we get
= [(2 × 4)/ (5 × 4)] + [(3 × 5)/ (4 × 5)]
On further calculation
= 8/20 + 15/20
We get
= (8 + 15)/20 = 23/20  m
Hence, the total length of the ribbon Kavita and Savita bought is 23/20 m.


Question 8:  Ravish takes 2 1/5 minutes to walk across the school ground. Rahul takes 7/4  minutes to do the same. Who takes less time and by what fraction?
 
Solution 8: 
Time taken by Ravish = 2 1/5 minutes = 11/minutes
Time taken by Rahul = 7/4   minutes
By comparing 11/ and 7/4   minutes
We know that LCM of 4 and 5 is 20
In order to convert fraction into equivalent fraction having 20 as denominator
[(11 × 4)/ (5 × 4)], [(7 × 5)/ (4 × 5)]
44/20 > 35/20
So, Rahul takes less time
written as
44/2035/20= (44 – 35)/20 = 9/20minutes
Hence, Rahul takes less time by 9/20 minutes.
 
 
Question 9:  A piece of a wire 7/meters long broke into two pieces. One piece was 1/4 meter long. How long is the other piece?
 
Solution 9: 
Given:
Length of wire = 7/8 m
Length of first piece = 1/4 m
Consider x m as the length of second piece
It can be written as
Length of wire = Length of first piece + Length of second piece
By substituting the values
7/= 1/+ x
On further calculation
x = 7/81/4
We know that the LCM of 8 and 4 is 8
x = [(7 × 1)/ (8 × 1)] – [(1 × 2)/ (4 × 2)]
We get
x = 7/8  – 2/8
By subtraction
x = (7 – 2)/ 8 = 5/8 m
Hence, the length of second piece of wire is 5/8m.


Question 10:  Shikha and Priya have bookshelves of the same size Shikha’s shelf is 5/6full of book and Priya’s shelf is 2/5full. Whose bookshelf is more full? By what fraction?
 
Solution 10: 
Fraction of Shikha’s shelf filled with books = 5/6
Fraction of Priya’s shelf filled with books = 2/5
We know that LCM of 5 and 6 is 30
In order to convert fraction into equivalent fraction having 30 as denominator
= [(5 × 5)/ (6 × 5)], [(2 × 6)/ (5 × 6)]
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A21


Question 11:   Ravish’s house is 9/10 km from his school. He walked some distance and then took a bus for 1/km up to the school. How far did he walk?
 
Solution 11: 
Given:
Distance of Ravish’s house from his school = 9/10 km
Distance covered by bus = 1/2 km
written as
Distance between house and school = Distance covered by walking + Distance covered by bus
So, we get
Distance covered by walking = Distance between house and school – Distance covered by bus
 
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A22
 
Exercise 6.10  
Mark the correct alternative in each of the following:
 
Question 1:  Which of the following is a proper fraction?
(a)  4/3  
(b) 3/4 
(c) 13/4 
(d) 21/5 
 
Solution 1: The correct answer is (b).

We know that in a proper fraction, the numerator is less than the denominator.
 
Question 2:  Which of the following is an improper fraction?
(a) 1/2
(b) 3/7
(c) 7/3
(d) 3/15
 
Solution 2:  The correct answer is (c).

We know that in an improper fraction, the numerator is more than the denominator.
 
Question 3:  Which of the following is a fraction equivalent of 2/3?
(a) 4/5
(b) 8/6
(c)  10/25
(d) 10/15
 
Solution 3:  The correct answer is (d).

10/15 = 2/3
By cross multiplication
10 × 3 = 2 × 15
We get
30 = 30
 
Question 4:  A fraction equivalent to 3/5  is
(a)  (3+2)/(5+2)
(b) (3-2)/(5-2)
(c) (3×2)/(5 ×2)
(d) None of these 
 
Solution 4:  The correct answer is (c).
 
We know that by dividing the numerator and denominator by 2, we obtain 3/5.
 
Question 5:  If 5/12 is equivalent of x/3, then x =
(a) 5/4
(b) 4/5
(c) 5/3
(d) 3/5 

Solution 5: The correct answer is (a). 

Consider 5/12 = x/3 
By cross multiplication 
5 × 3 = 12 × x 
So we get 
x = (( 5 × 3))/12  = (( 5 × 3))/((4 ×3))  =  5/4 
 
 
Question 6:   Which of the following are like fractions?
(a) 3/5, 3/7,  3/11 ,  3/16 
(b) 5/11, 7/11,  15/11 , 2/11
(c) 2/3,  3/4 , 4/5, 6/7
(d) None of these
 
Solution 6:  The correct answer is (b).
 
We know that like fractions are the fractions with the same denominator.
 
Question 7:  If 11/4 =77/x, then x =
(a) 28
(b)  77/28
(c) 44
(d) 308
 
Solution 7:  The correct answer is (a).

11/4 =77/x
By cross multiplication
11 × x = 77 × 4
x = (77 × 4)/ 11 = (7 × 11 × 4)/ 11
Dividing both the numerator & denominator by 11, we obtain 28.
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A24
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A25
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A26
 
Question 11:  Which of the following fractions is the smallest?
1/2,  3/7,  3/5,  4/9
(a) 4/9
(b) 3/5
(c) 3/7
(d) 1/2
 
Solution 11:  The correct answer is (c).

We know that the LCM of numerator is 12
By converting each fraction to an equivalent fraction having 12 as numerator
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A28
We know that if the denominator is same the fraction having larger numerator is the greatest.
Hence, 7/8 is the greatest fraction.
 
Question 13:  What is the value of a+b/ a−b, If a/b=4?
(a) 3/5
(b) 5/3
(c) 4/5
(d) 5/4
 
Solution 13:  The correct answer is (b).
It is given that a/b = 4
We can write it as a = 4b
By substituting the value of a in a+b/a-b
a+b/a-b = 4b+b/4b-b = 5b/3b
Dividing numerator and denominator by b, the value is 5/3.
 
Question 14:  If a/b = 4/3, then the value of 6a+4b/ 6a-5b is
(a) −1
(b) 3
(c) 4
(d) 5
 
Solution 14:  The correct answer is (c).
It is given that a/b = 4/3
We can write it as a = 4b/3
By substituting the value of a in 6a+4b/6a-5b
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A29
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A30
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A31
 
 
 
Question 17:  If 45/(60) is equivalent to 3/x, then x =
(a) 5
(b) 4
(c) 6
(d) 20
 
Solution 17:  The correct answer is (b).
Given:
45/60 = 3/x
By cross multiplication
45 × x = 3 × 60
x = (3 × 60)/45 = 180/45
Dividing the fraction by HCF
(180 ÷ 45)/(45÷45) = 4
 
 
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A32
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions-A33
 
 


 

RD Sharma Solutions Class 6 Maths
RD Sharma Solutions Class 6 Maths Chapter 1 Knowing our Numbers
RD Sharma Solutions Class 6 Maths Chapter 2 Playing with Numbers
RD Sharma Solutions Class 6 Maths Chapter 3 Whole Numbers
RD Sharma Solutions Class 6 Maths Chapter 4 Operations on Whole Numbers
RD Sharma Solutions Class 6 Maths Chapter 5 Negative Numbers and Integers
RD Sharma Solutions Class 6 Maths Chapter 6 Fractions
RD Sharma Solutions Class 6 Maths Chapter 7 Decimals
RD Sharma Solutions Class 6 Maths Chapter 8 Introduction to Algebra
RD Sharma Solutions Class 6 Maths Chapter 9 Ratio Proportion and Unitary Method
RD Sharma Solutions Class 6 Maths Chapter 10 Basic Geomatrical Concepts
RD Sharma Solutions Class 6 Maths Chapter 11 Angles
RD Sharma Solutions Class 6 Maths Chapter 12 Triangle
RD Sharma Solutions Class 6 Maths Chapter 13 Quadrilaterals
RD Sharma Solutions Class 6 Maths Chapter 14 Circles
RD Sharma Solutions Class 6 Maths Chapter 15 Pair of Lines and Transversal
RD Sharma Solutions Class 6 Maths Chapter 16 Understanding Three Dimensional Shapes
RD Sharma Solutions Class 6 Maths Chapter 17 Symmetry
RD Sharma Solutions Class 6 Maths Chapter 18 Basic Geometrical Tools
RD Sharma Solutions Class 6 Maths Chapter 19 Geometrical Constructions
RD Sharma Solutions Class 6 Maths Chapter 20 Mensuration
RD Sharma Solutions Class 6 Maths Chapter 21 Data Handling Presentation of Data
RD Sharma Solutions Class 6 Maths Chapter 22 Data Handling Pictographs
RD Sharma Solutions Class 6 Maths Chapter 23 Data Handling Bar Graphs