Read and download free pdf of CBSE Class 11 Physics Laws of Motion Worksheet Set A. Download printable Physics Class 11 Worksheets in pdf format, CBSE Class 11 Physics Chapter 5 Laws of Motion Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Physics Class 11 Assignments and practice them daily to get better marks in tests and exams for Class 11. Free chapter wise worksheets with answers have been designed by Class 11 teachers as per latest examination pattern
Chapter 5 Laws of Motion Physics Worksheet for Class 11
Class 11 Physics students should refer to the following printable worksheet in Pdf in Class 11. This test paper with questions and solutions for Class 11 Physics will be very useful for tests and exams and help you to score better marks
Class 11 Physics Chapter 5 Laws of Motion Worksheet Pdf
Question. Physical independence of force is a consequence of
(a) third law of motion
(b) second law of motion
(c) first law of motion
(d) all of these laws
Answer. C
Question. A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by
(a) 68%
(b) 41%
(c) 200%
(d) 100%
Answer. B
Question. A cricketer catches a ball of mass 150 gm in 0.1 sec moving with speed 20 m/s, then he experiences force of
(a) 300 N
(b) 30 N
(c) 3 N
(d) 0.3 N
Answer. B
Question. If the force on a rocket, moving with a velocity of 300 m/s is 210 N, then the rate of combustion of the fuel is
(a) 0.07 kg/s
(b) 1.4 kg/s
(c) 0.7 kg/s
(d) 10.7 kg/s
Answer. C
Question. A bullet is fired from a gun. The force on the bullet is given by F = 600 – 2 × 105 t where, F is in newton and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?
(a) 9 Ns
(b) zero
(c) 1.8 Ns
(d) 0.9 Ns
Answer. D
Question. A 5000 kg rocket is set for vertical firing. The exhaust speed is 800 m s–1. To give an initial upward acceleration of 20 m s–2, the amount of gas ejected per second to supply the needed thrust will be (g = 10 m s–2)
(a) 185.5 kg s–1
(b) 187.5 kg s–1
(c) 127.5 kg s–1
(d) 137.5 kg s–1
Answer. B
Question. A force of 6 N acts on a body at rest and of mass 1 kg. During this time, the body attains a velocity of 30 m/s. The time for which the force acts on the body is
(a) 7 seconds
(b) 5 seconds
(c) 10 seconds
(d) 8 seconds
Answer. B
Question. A 10 N force is applied on a body produce in it an acceleration of 1 m/s2. The mass of the body is
(a) 15 kg
(b) 20 kg
(c) 10 kg
(d) 5 kg
Answer. C
Question. In a rocket, fuel burns at the rate of 1 kg/s. This fuel is ejected from the rocket with a velocity of 60 km/s.This exerts a force on the rocket equal to
(a) 6000 N
(b) 60000 N
(c) 60 N
(d) 600 N
Answer. B
Question. A 600 kg rocket is set for a vertical firing. If the exhaust speed is 1000 m s–1, the mass of the gas ejected per second to supply the thrust needed to overcome the weight of rocket is
(a) 117.6 kg s–1
(b) 58.6 kg s–1
(c) 6 kg s–1
(d) 76.4 kg s–1
Answer. C
Question. A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity.The impulse experienced by the body is
(a) MV
(b) 1.5MV
(c) 2MV
(d) zero
Answer. C
Question. A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle of 30° with the wall. It is reflected with the same speed at the same angle. If the ball is in contact with the wall for 0.25 seconds, the average force acting on the wall is
(a) 96 N
(b) 48 N
(c) 24 N
(d) 12 N
Answer. C
Question. An explosion breaks a rock into three parts in a horizontal plane. Two of them go off at right angles to each other. The first part of mass 1 kg moves with a speed of 12 m s–1 and the second part of mass 2 kg moves with 8 m s–1 speed. If the third part flies off with 4 m s–1 speed, then its mass is
(a) 7 kg
(b) 17 kg
(c) 3 kg
(d) 5 kg
Answer. D
Question. A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth surface and fires 10 shots horizontally, in 5 s. Each bullet has a mass of 10 g with a muzzle velocity of 800 m s–1. The final velocity acquired by the person and the average force exerted on the person are
(a) – 0.08 m s–1, 16 N
(b) – 0.8 m s–1, 8 N
(c) – 1.6 m s–1, 16 N
(d) – 1.6 m s–1, 8 N
Answer. A
Question. An explosion blows a rock into three parts. Two parts go off at right angles to each other. These two are, 1 kg first part moving with a velocity of 12 m s s–1 and 2 kg second part moving with a velocity 8 m s–1.If the third part flies off with a velocity of 4 m s–1, its mass would be
(a) 7 kg
(b) 17 kg
(c) 3 kg
(d) 5 kg
Answer. D
Question. A mass of 1 kg is thrown up with a velocity of 100 m/s. After 5 seconds, it explodes into two parts.One part of mass 400 g comes down with a velocity 25 m/s. The velocity of other part is (Take g = 10 m s–2)
(a) 40 m/s
(b) 80 m/s
(c) 100 m/s
(d) 60 m/s
Answer. C
Question. A shell, in flight, explodes into four unequal parts.Which of the following is conserved?
(a) Potential energy
(b) Momentum
(c) Kinetic energy
(d) Both (a) and (c).
Answer. B
Question. A man fires a bullet of mass 200 g at a speed of 5 m/s.The gun is of one kg mass. By what velocity the gun rebounds backward?
(a) 1 m/s
(b) 0.01 m/s
(c) 0.1 m/s
(d) 10 m/s.
Answer. A
Question. A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be
(a) 7 2
(b) 5 2
(c) 3 2
(d) 2
Answer. A
Question. Which one of the following statements is incorrect?
(a) Rolling friction is smaller than sliding friction.
(b) Limiting value of static friction is directly proportional to normal reaction.
(c) Frictional force opposes the relative motion.
(d) Coefficient of sliding friction has dimensions of length.
Answer. D
Question. A conveyor belt is moving at a constant speed of 2 m s–1. A box is gently dropped on it. The coefficient of friction between them is m = 0.5. The distance that the box will move relative to belt before coming to rest on it, taking g = 10 m s–2, is
(a) 0.4 m
(b) 1.2 m
(c) 0.6 m
(d) zero
Answer. A
Question. A block of mass 10 kg placed on rough horizontal surface having coefficient of friction m = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be
(a) 10 m/s2
(b) 5 m/s2
(c) 15 m/s2
(d) 0.5 m/s2
Answer. B
Question. On the horizontal surface of a truck a block of mass 1 kg is placed (m = 0.6) and truck is moving with acceleration 5 m/s2 then the frictional force on the block will be
(a) 5 N
(b) 6 N
(c) 5.88 N
(d) 8 N
Answer. A
Question. A block has been placed on a inclined plane with the slope angle q, block slides down the plane at constant speed. The coefficient of kinetic friction is equal to
(a) sinq
(b) cosq
(c) g
(d) tanq
Answer. D
Question. Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is (taking g = 10 m/s2)
(a) 30 m
(b) 40 m
(c) 72 m
(d) 20 m
Answer. B
Question. A heavy uniform chain lies on horizontal table top.If the coefficient of friction between the chain and the table surface is 0.25, then the maximum fraction of the length of the chain that can hang over one edge of the table is
(a) 20%
(b) 25%
(c) 35%
(d) 15%
Answer. A
Question. Starting from rest, a body slides down a 45° inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of friction between the body and the inclined plane is
(a) 0.80
(b) 0.75
(c) 0.25
(d) 0.33
Answer. B
Question. A block of mass 10 kg is in contact against the inner wall of a hollow cylindrical drum of radius 1 m.The coefficient of friction between the block and the inner wall of the cylinder is 0.1. The minimum angular velocity needed for the cylinder to keep the block stationary when the cylinder is vertical and rotating about its axis, will be (g = 10 m/s2)
(a) 10 π rad/s
(b) √10 rad/s
(c) 10/2π rad/s
(d) 10 rad/s
Answer. D
Question. Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r/2 and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces.
The value of n is
(a) 4
(b) 1
(c) 2
(d) 3
Answer. C
Question. A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is
(a) p/3
(b) p/6
(c) p/4
(d) 0°
Answer. C
Question. A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If the banking angle is 45°, the speed of the car is
(a) 20 m s–1
(b) 30 m s–1
(c) 5 m s–1
(d) 10 m s–1
Answer. B
Question. A roller coaster is designed such that riders experience “weightlessness” as they go round the top of a hill whose radius of curvature is 20 m. The speed of the car at the top of the hill is between
(a) 16 m/s and 17 m/s
(b) 13 m/s and 14 m/s
(c) 14 m/s and 15 m/s
(d) 15 m/s and 16 m/s
Answer. C
Question. A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/hr. The centripetal force is
(a) 1000 N
(b) 750 N
(c) 250 N
(d) 1200 N
Answer. A
Question. A ball of mass 0.25 kg attached to the end of a string of length 1.96 m is moving in a horizontal circle. The string will break if the tension is more than 25 N.What is the maximum speed with which the ball can be moved ?
(a) 5 m/s
(b) 3 m/s
(c) 14 m/s
(d) 3.92 m/s.
Answer. C
Question. When milk is churned, cream gets separated due to
(a) centripetal force
(b) centrifugal force
(c) fricitional force
(d) gravitational force
Answer. B
Question. Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is
(a) g
(b) g/2
(c) g/5
(d) g/10
Answer. C
Question. A person of mass 60 kg is inside a lift of mass 940 kg and presses the button on control panel. The lift starts moving upwards with an acceleration 1.0 m/s2. If g = 10 m s–2, the tension in the supporting cable is
(a) 8600 N
(b) 9680 N
(c) 11000 N
(d) 1200 N
Answer. C
Question. The mass of a lift is 2000 kg. When the tension in the supporting cable is 28000 N, then its acceleration is
(a) 4 m s–2 upwards
(b) 4 m s–2 downwards
(c) 14 m s–2 upwards
(d) 30 m s–2 downwards
Answer. A
Question. A block of mass m is placed on a smooth wedge of inclination q. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block will be (g is acceleration due to gravity)
(a) mg cosq
(b) mg sinq
(c) mg
(d) mg/cosq
Answer. D
Question. A man weighs 80 kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5 m/s2. What would be the reading on the scale ? (g = 10 m/s2)
(a) zero
(b) 400 N
(c) 800 N
(d) 1200 N
Answer. D
Question. A monkey of mass 20 kg is holding a vertical rope.The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope?
(g = 10 m/s2)
(a) 5 m/s2
(b) 10 m/s2
(c) 25 m/s2
(d) 2.5 m/s2
Answer. D
Question. A lift of mass 1000 kg which is moving with acceleration of 1 m/s2 in upward direction, then the tension developed in string which is connected to lift is
(a) 9800 N
(b) 10,800 N
(c) 11,000 N
(d) 10,000 N
Answer. B
Question. A mass of 1 kg is suspended by a thread. It is
(i) lifted up with an acceleration 4.9 m/s2,
(ii) lowered with an acceleration 4.9 m/s2.
The ratio of the tensions is
(a) 1 : 3
(b) 1 : 2
(c) 3 : 1
(d) 2 : 1
Answer. C
Question. A monkey is decending from the branch of a tree with constant acceleration. If the breaking strength of branch is 75% of the weight of the monkey, the minimum acceleration with which monkey can slide down without breaking the branch is
(a) g
(b) 3g/4
(c) g/4
(d) g/2
Answer. C
Short Answer
Question. What do you mean by the law of conservation of momentum?
Answer. The law of conservation of momentum states that momentum only moves from one place to another, since it is neither created nor destroyed. The total energy of an isolated system remains constant; it is said to be conserved over time, for example: friction, act on the system.
Question. What is the law of inertia?
Answer. The law of Inertia states that a mass at rest tends to remain at rest; a mass moving at a constant velocity tends to keep moving at that velocity, unless acted upon by an outside force, for example: one's body movement to the side when a car makes a sharp turn or tightening of seat belts in a car when it stops quickly.
Question. Distinguish between kinetic friction and static friction?
Answer.
1. Kinetic friction is the retarding force between two objects in contact that are moving against each other whereas static friction is the force that has to be overcome in order to get an object to move.
2. Kinetic friction coefficient is smaller than the static friction whereas static friction coefficient exceeds the one from kinetic energy.
Question. What do you mean by Aristotle Fallacy?
Answer.
Aristotle made observations from practical experiences and came to the conclusion that an external force is required to keep a body in uniform motion. This is known as the Aristotle's fallacy. It is the frictional force between and the body and the surface that opposes motion and to overcome this frictional force, we need to apply some external force greater than this frictional force.
Question. Define circular motion?
Answer. Circular motion is the motion in which velocity is tangential to the circular path. Since the object is moving counter clockwise, at the top of the circle this tangent line points to the left, for example: an artificial satellite orbiting the earth at a constant height, a ceiling fan's blades rotating around a hub, a stone which is tied to a rope and is being swung in
Long Answer
Question. Difference between momentum and inertia?
Answer. 1. Momentum is the product of the velocity and the inertial mass of the object whereas inertia explains how hard it is to change the current state of the system.
2. Momentum is the physically calculable property whereas inertia cannot be calculated using a formula.
3. Momentum is the property of the moving object whereas inertia is a concept that helps us to understand and define the mechanics better.
4. Momentum has to forms linear momentum and angular momentum whereas inertia comes only in one form.
5. Momentum is conserved in some of the cases and it is useful in solving the problems whereas inertia does not have to be conserved in any case.
Question. Write short note on friction?
Answer. Friction is a force between two surfaces that are sliding, or trying to slide, across each other. Friction is everywhere that objects come into contact with each other. Friction always works in the direction opposite to the direction in which the object is moving, or trying to move, for example: when we try to push a book along the floor, friction makes this difficult. Friction is a force that resists the relative motion between two objects or materials. The causes of this resistive force are molecular adhesion, surface roughness, and deformations. Adhesion is the molecular force resulting when two materials are brought into close contact with each other. There are four types of friction: static, sliding or kinetic, rolling, and fluid friction. Static, sliding, and rolling friction occur between solid surfaces. In liquids friction is the resistance between moving layers of a fluid, which is also known as viscosity. More viscous fluids are thicker, so honey has more fluid friction than water. The atoms inside a solid material can experience friction as well, for example, if a solid block of metal gets compressed all the atoms inside the material move and creating internal friction. In nature, there are not completely frictionless environments, even in deep space; tiny particles of matter may interact, causing friction.
Question. Explain first and second Newton’s law of motions?
Answer. Newton’s first law: Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. If an object is at rest in one frame of reference, it will appear to be moving in a straight line to an observer in a reference frame which is moving by the object, for example: the motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere or the motion of a kite when the wind changes. If the net external force on a body is zero its acceleration can be non-zero only if there is a net external force on the body.
Newton’s second law: The second law states that the acceleration of an object is dependent upon two variables the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased. Newton's Second Law of Motion F = ma is very important because it shows the relationship between forces and motion. It allows you to calculate the acceleration and therefore velocity and position of an object with known forces, for example: riding the bicycle is the good example of the second law of motion at work. Our bicycle is the mass, our leg muscles pushing on the pedals of the bicycle is the force.
Question. What are the steps used for solving the problems in mechanism?
Answer. The steps used for solving the problems in mechanism are:
1. Draw the diagram showing schematically the various parts of the assembly bodies are the links, supports etc.
2. Choose the convenient part of the assembly as one of the system.
3. Draw a separate diagram which shows the system and all the forces on the system by reassembling part of the assembly. It also includes the forces in the system by other agencies; do not include the forces on the environment by the system.
4. A free body diagram include the information about forces their magnitudes and the directions that are either given or we are sure of the directions and the magnitude of tension in a string along its length. The rest it should be treated as unknowns to be determined by using the law of motion.
5. The same procedure for another choice of the system, for doing that we have to follow Newton’s third law of motion.
Question. Explain Newton’s third law of friction?
Answer. Newton's Third Law of Motion states that to every action there is an equal and opposite reaction. The action and reaction are equal and opposite. In aerospace engineering, the principal of action and reaction is very important. So the net force on a body of zero mass is always zero, whatever forces act upon it. Therefore if only two forces act on a body of mass zero, they must add to zero, and therefore must be equal size and oppositely directed, for example: when someone fire gun the reaction force push the gun backward or when we slap someone our hand feel pain as well as the check of the victim. The terms action and reaction men nothing else but the force. Forces always occur in pairs. Force on a body A by B is equal and opposite to the force on the body B by A. There is no cause effect relation implied in the third law. The force on A by B and the force on B by A, act the same instant. Action and reaction forces act on the different bodies not on the same body.
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CBSE Class 11 Physics Chapter 5 Laws of Motion Worksheet
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Worksheet for Physics CBSE Class 11 Chapter 5 Laws of Motion
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Chapter 5 Laws of Motion worksheet Physics CBSE Class 11
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Chapter 5 Laws of Motion CBSE Class 11 Physics Worksheet
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Worksheet for CBSE Physics Class 11 Chapter 5 Laws of Motion
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