CBSE Class 11 Motion in Straight Line Worksheet A

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1.Under what condition is the relation s =ut correct?

2. Two balls of different masses are thrown vertically upward with same initial speed. Which one will rise to a greater height?

3. What is the relative velocity of two bodies having equal velocities?

4. Write the characteristics of displacement?

5. Draw displacement time graph for uniformly accelerated motion. What is its shape?

6. Sameer went on his bike from Delhi to Gurgaon at a speed of 60km/hr and came back at a speed of 40km/hr. what is his average speed for entire journey.

7. Define V = v + at from velocity time graph.

8. A particle is moving along a straight line and its position is given by the relation  x = (t³ - 6t ² -15t + 40) m

Find (a) The time at which velocity is zero.

(b) Position and displacement of the particle at that point.

(c) Acceleration for the particle at that line.                               

9. Velocity time graph of a moving particle is shown. Find the displacement (1) 0 – 4 s (2) 0 – 8 (3) 0 12 s from the graph. Also write the differences between distance and displacement

Question. The relative velocity VAB or VBA of two bodies A & B may be
(1) greater than velocity of body A
(2) greater than velocity of body B
(3) less than the velocity of body A
(4) less than the velocity of body B
(a) (1) and (2) only
(b) (3) and (4) only
(c) (1), (2) and (3) only
(d) (1), (2), (3) and (4)

Answer: D

Question. A stone is thrown vertically upwards. When the particle is at a height half of its maximum height, its speed is 10m/sec, then maximum height attained by particle is (g = 10m/sec²)
(a) 8 m
(b) 10 m
(c) 15 m
(d) 20 m

Answer: B

Question. From a 10m high building a stone ‘A’ is dropped & simultaneously another stone ‘B’ is thrown horizontally with an initial speed of 5 m/sec–1. Which one of the following statements is true?
(a) It is not possible to calculate which one of two stones will reach ground first
(b) Both stones ‘A’ & ‘B’ will reach the ground simultaneously.
(c) ‘A’ stones reach the ground earlier than ‘B’
(d) ‘B’ stones reach the ground earlier than ‘A’

Answer: B

Question. An automobile travelling with a speed of 60 km/h, can apply brake to stop within a distance of 20m. If the car is going twice as fast i.e., 120 km/h, the stopping distance will be
(a) 60 m
(b) 40 m
(c) 20 m
(d) 80 m

Answer: D

Question. Figure shows the position of a particle moving along the X-axis as a function of time. 

Which of the following is correct?
(a) The particle has come to the rest 6 times
(b) The maximum speed is at t = 6 s.
(c) The velocity remains positive for t = 0 to t = 6 s.
(d) The average velocity for the total period shown is negative.

Answer: A

Question. From a 200 m high tower, one ball is thrown upwards with speed of 10 ms-1 and another is thrown vertically downwards at the same speeds simultaneously. The time difference of their reaching the ground will be nearest to
(a) 12 s
(b) 6 s
(c) 2 s
(d) 1 s

Answer: C

Question. A particle starting from rest falls from a certain height. Assuming that the acceleration due to gravity remain the same throughout the motion, its displacements in three successive half second intervals are S₁, S₂ and S₃ then
(a) S₁ : S₂ : S₃ = 1 : 5 : 9
(b) S₁ : S₂ : S₃ = 1 : 3 : 5
(c) S₁ : S₂ : S₃ = 9 : 2 : 3
(d) S₁ : S₂ : S₃ = 1 : 1 : 1

Answer: B

Question. A particle travels half the distance with a velocity of 6 ms^-1. The remaining half distance is covered with a velocity of 4 ms^-1 for half the time and with a velocity of 8 ms-1 for the rest of the half time. What is the velocity of the particle averaged over the whole time of motion ?
(a) 9 ms^–1
(b) 6 ms^–1
(c) 5.35 ms^–1
(d) 5 ms^–1

Answer: B

Question. The displacement x of a particle along a straight line at time t is given by : x = a₀ + a₁t/2 + a₂/3 t². The acceleration of the particle is
(a) a₂/3
(b) 2a₂/3
(c) a₁/2
(d) a₀ + a₂/3

Answer: B

Question. A particle is moving in a straight line with initial velocity and uniform acceleration a. If the sum of the distance travelled in tth and (t + 1)^th seconds is 100 cm, then its velocity after t seconds, in cm/s, is
(a) 80
(b) 50
(c) 20
(d) 30

Answer: B

Question. Similar balls are thrown vertically each with a velocity 20 ms^–1, one on the surface of earth and the other on the surface of moon. What will be ratio of the maximum heights attained by them? (Acceleration on moon = 1.7 ms^–2 approx)
(a) 6
(b) 1/6
(c) 1/5
(d) None of these

Answer: B

Question. A body dropped from a height ‘h’ with an initial speed zero, strikes the ground with a velocity 3 km/hour. Another body of same mass dropped from the same height ‘h’ with an initial speed u' = 4 km/hour. Find the final velocity of second mass, with which it strikes the ground
(a) 3 km/hr
(b) 4 km/hr
(c) 5 km/hr
(d) 6 km/hr

Answer: C

Question. An electron starting from rest has a velocity that increases linearly with time i.e. v = kt where k = 2 ms^-2 . The distance covered in the first 3 second is
(a) 9 m
(b) 16 m
(c) 27 m
(d) 36 m

Answer: A

Question. A body released from the top of a tower falls through half the height of the tower in 2 s. In what time shall the body fall through the height of the tower ?
(a) 4 s
(b) 3.26 s
(c) 3.48 s
(d) 2.828 s

Answer: D

Question. The two ends of a train moving with constant acceleration pass a certain point with velocities u and v. The velocity with which the middle point of the train passes the same point is
(a) (u + v)/2
(b) (u² + v²)/2
(c) √(u² + vu² ) / 2
(d) √u² + v²

Answer: C

Question. A body moves in a straight line along Y-axis. Its distance y (in metre) from the origin is given by y = 8t – 3t². The average speed in the time interval from t = 0 second to t = 1 second is
(a) – 4 ms^–1
(b) zero
(c) 5 ms^–1
(d) 6 ms^–1

Answer: C

Question. The acceleration due to gravity on planet A is nine times the acceleration due to gravity on planet B. A man jumps to a height 2m on the surface of A. What is height of jump by same person on planet B?
(a) 2/3 m
(b) 2/9 m
(c) 18 m
(d) 6 m

Answer: C

Question. In the given figure the distance PQ is constant. SQ is a vertical line passing through point R. A particle is kept at R and the plane PR is such that angle θ can be varied such that R lies on line SQ. The time taken by particle to come down varies, as the θ increases 

(a) decreases continuously
(b) increases
(c) increases then decreases
(d) decreases then increases

Answer: D

Question. The displacement x of a particle varies with time t as x = ae^-αt + be^βt, where a, b, α and β are positive constants.
The velocity of the particle will
(a) be independent of a and β
(b) drop to zero when α = β
(c) go on decreasing with time
(d) go on increasing with time

Answer: D

Question. If you were to throw a ball vertically upward with an initial velocity of 50 m/s, approximately how long would it take for the ball to return to your hand? Assume air resistance is negligible.
(a) 2.5 s
(b) 5.0 s
(c) 7.5 s
(d) 10 s

Answer: D

Question. A rubber ball is dropped from a height of 5 metre on a plane where the acceleration due to gravity is same as that onto the surface of the earth. On bouncing, it rises to a height of 1.8 m. On bouncing, the ball loses its velocity by a factor of
(a) 3/5
(b) 9/25
(c) 2/5
(d) 16/25

Answer: C

Question. The motion of a particle is described by the equation u = at.
The distance travelled by particle in first 4 sec is
(a) 4a
(b) 12a
(c) 6a
(d) 8a

Answer: D

Question. Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t₁. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time t₂.
The time taken by her to walk up on the moving escalator will be:
(a) t₁t₂/t₁-t₂
(b) t₁t₂/t₁+t₂
(c) t₁ – t₂
(d) t₁+t₂/2

Answer: B

Question. A boy moving with a velocity of 20 km h^–1 along a straight line joining two stationary objects. According to him both objects
(a) move in the same direction with the same speed of 20 km h^–1
(b) move in different direction with the same speed of 20 km h^–1
(c) move towards him
(d) remain stationary

Answer: A

Question. A graph of acceleration versus time of a particle starting from rest at t = 0 is as shown in Fig. The speed of the particle at t = 14 second is 

(a) 2 ms^–1
(b) 34 ms^–1
(c) 20 ms^–1
(d) 42 ms^–1

Answer: B

Click on link below to download CBSE Class 11 Motion in Straight Line Worksheet A.