CBSE Class 11 Stoichiometry and Stoichiometric Calculations Worksheet A

Read and download free pdf of CBSE Class 11 Stoichiometry and Stoichiometric Calculations Worksheet A. Download printable Chemistry Class 11 Worksheets in pdf format, CBSE Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Chemistry Class 11 Assignments and practice them daily to get better marks in tests and exams for Class 11. Free chapter wise worksheets with answers have been designed by Class 11 teachers as per latest examination pattern

Chapter 1 Some Basic Concepts of Chemistry Chemistry Worksheet for Class 11

Class 11 Chemistry students should refer to the following printable worksheet in Pdf in Class 11. This test paper with questions and solutions for Class 11 Chemistry will be very useful for tests and exams and help you to score better marks

Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry Worksheet Pdf

Question. What is the concentration of nitrate ions if equal volumes of 0.1 M AgNO3 and 0.1 M NaCl are mixed together?
a. 0.1 M
b. 0.2 M
c. 0.05 M
d. 0.25 M
Answer : C

Question. 74.5 g of a metallic chloride contain 35.5 g of chlorine.
The equivalent weight of the metal is:
a. 19.5
b. 35.5
c. 39.0
d. 78.0
Answer : C

Question. The atomic weights of two elements A and B are 40 and 80 respectively. If x g of A contains y atoms, how many atoms are present in 2x g of B?
a. y/2
b. y/4
c. y
d. 2y
Answer : C

Question. Which of the following is the best example of law of conservation of mass?
a. 12 g of carbon combines with 32 g of oxygen to form 44 g of CO2
b. When 12 g of carbon is heated in a vacuum there is no change in mass
c. A sample of air increases in volume when heated at constant pressure but its mass remains unaltered
d. The weight of a piece of platinum is the same before and after heating in air
Answer : A

Question. n g of substance X reacts with m g of substance Y to form p g of substance R and q g of substance S. This reaction can be represented as, X + Y = R + S.The relation which can be established in the amounts of the reactants and the products will be
a. n  –m = p –q
b. n + m = p + q
c. n = m
d. p = q
Answer : B

Question. Sulphur forms the chlorides S2Cl2 and SCl2 .The equivalent mass of sulphur in SCl2 is:
a. 8 g/mole
b. 16 g/mole
c. 64.8 g/mole
d. 32 g/mole
Answer : B

Question. 1.520 g of the hydroxide of a metal on ignition gave 0.995 gm of oxide. The equivalent weight of metal is:
a. 1.520
b. 0.995
c. 19.00
d. 9.00
Answer : D

Question. Caffeine has a molecular weight of 194. If it contains 28.9% by mass of nitrogen, number of atoms of nitrogen in one molecule of caffeine is:
a. 4
b. 6
c. 2
d. 3
Answer : A

Question. One litre of a gas at STP weight 1.16 g it can possible be:
a. C2H2
b. CO
c. O2
d. CH4
Answer : A

Question. 1.25 g of a solid dibasic acid is completely neutralised by 25 ml of 0.25 molar Ba(OH)2 solutions. Molecular mass of the acid is:
a. 100
b. 150
c. 120
d. 200
Answer : D

Question. A gaseous mixture contains CH4 and C2H6 in equimolecular proportion. The weight of 2.24 litres of this mixture at NTP is:
a. 4.6 g
b. 1.6 g
c. 2.3 g
d. 23 g
Answer : C

Question. The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal is:
a. 23.9
b. 27.3
c. 36.3
d. 48.3
Answer : A

Question. What should be the equivalent weight of phosphorous acid, if P = 31; O = 16; H = 1?
a. 82
b. 41
c. 20.5
d. None of these
Answer : B

Question. The weight of a molecule of the compound C60H122 is:
a. 1.4x10–21 g
b. 1.09x10–21 g
c. 5.025x1023 g
d. 16.023x1023 g
Answer : A

Question. Equivalent weight of a bivalent metal is 37.2. The molecular weight of its chloride is:
a. 412.2
b. 216
c. 145.4
d. 108.2
Answer : C

Question. 250 ml of a sodium carbonate solution contains 2.65 grams of Na2CO3 . If 10 ml of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of Na2CO3 = 106) ?
a. 0.1 M
b. 0.001 M
c. 0.01 M
d. 10–4M
Answer : B

Question. The prefix zepto stands for:
a. 109
b. 10–12
c. 10–15
d. 10–21
Answer : D

Question. The number of significant figures in 60.0001 is:
a. 5
b. 6
c. 3
d. 2
Answer : B

Question. Volume of a gas at STP is 1.12x10–7 cc. Calculate the number of molecules in it:
a. 3.01x1020
b. 3.01x1012
c. 3.01x1023
d. 3.01x1024
Answer : B

Question. The number of molecules in 4.25 g of ammonia are:
a. 0.5x1023
b. 1.5x1023
c. 3.5x1023
d. 1.8x1032
Answer : B

Question. Which one of the following pairs of gases contains the same number of molecules?
a. 16 g of O2 and 14 g of N2
b. 8 g of O2 and 22 g of CO2
c. 28 g of N2 and 22 g of CO2
d. 32 g of O2 and 32 g of N2
Answer : A

Question. Molarity of liquid HCl with density equal to 1.17g/cc is:
a. 36.5
b. 18.25
c. 32.05
d. 4.65
Answer : C

Question. A sample of phosphorus trichloride (PCl3) contains 1.4 moles of the substance. How many atoms are there in the sample?
a. 4
b. 5.6
c. 8.431x1023
d. 3.372x1024
Answer : C

Question. The percentage of oxygen in NaOH is:
a. 40
b. 60
c. 8
d. 10
Answer : A

Question. The number of water molecules in 1 litre of water is:
a. 18
b. 18x1000
c. NA
d. 55.55NA
Answer : D

Question. b. Which of the following is Loschmidt number?
a. 6 x 1023
b. 2.69 x 1019
c. 3 x 1023
d. None of these
Answer : B

Question. The total number of gm-molecules of SO2Cl2 in 13.5g of sulphuryl chloride is:
a. 0.1
b. 0.2
c. 0.3
d. 0.4
Answer : A

Question. The number of moles of oxygen in 1 L of air containing 21% oxygen by volume, in standard conditions, is:
a. 0.186 mol
b. 0.21 mol
c. 2.10 mol
d. 0.0093 mol
Answer : D

Question. The number of oxygen atoms in 4.4 g of CO2 is approx:
a. 1.2x1023
b. 6x1022
c. 6x1023
d. 12x1023
Answer : A

Question. 19.7 kg of gold was recovered from a smuggler. How many atoms of gold were recovered? (Au =197)
a. 100
b. 6.02x1023
c. 6.02x1024
d. 6.02x1025
Answer : D

Question. In which of the following pairs of compounds the ratio of C, H and O is same?
a. Acetic acid and methyl alcohol
b. Glucose and acetic acid
c. Fructose and sucrose
d. All of these
Answer : B

Question. How much of NaOH is required to neutralise 1500 cm3 of 0.1 NHCl (Na = 23)?
a. 40 g
b. 4 g
c. 6 g
d. 60 g
Answer : C

Question. The percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (atomic weight=78.4). Then minimum molecular weight of peroxidase anhydrous enzyme is:
a. 1.568x104
b. 1.568x103
c. 15.68
d. 3.136x104
Answer : A

Question. What is the % of H2 Oin Fe(CNS)3. 3H3O ?
a. 45
b. 30
c. 19
d. 25
Answer : C

Question. In order to prepare one litre normal solution of KMnO4, how many grams of KMnO4 are required if the solution is used in acidic medium for oxidation?
a. 158 g
b. 31.6 g
c. 790 g
d. 62 g
Answer : B

Question. 2.76 g of silver carbonate on being strongly heated yield a residue weighing:
a. 2.16 g
b. 2.48 g
c. 2.64 g
d. 2.32 g
Answer : A

Question. Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (At. wt. of Fe = 56) present in one molecule of haemoglobin is:
a. 6
b. 1
c. 4
d. 2
Answer : C

Question. The percentage of P2O5 in diammonium hydrogen phosphate (NH4)2HPO4 is:
a. 23.48
b. 46.96
c. 53.78
d. 71.00
Answer : C

Question. The percentage of nitrogen in urea is about:
a. 46
b. 85
c. 18
d. 28
Answer : A

Question. The empirical formula of a compound is H2O. 0.0835 moles of the compound contains 1.0 g of hydrogen.
Molecular formula of the compound is:
a. C2H12O6
b. C3H10O5
c. C4H8O8
d. C3H6O3
Answer : A

Question. In the preceeding question, the amount of Na2CO3 present in the solution is:
a. 2.650 g
b. 1.060 g
c. 0.530 g
d. 0.265 g
Answer : C

Question. How many g of a dibasic acid (Mol. wt. = 200) should be present in 100 ml of its aqueous solution to give decinormal strength?
a. 1 g
b. 2 g
c. 10 g
d. 20 g
Answer : A

Question. The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27oC. Which of the following is correct for 100 moles of mixture?
a. Moles of NO2 in mixture are 33.48
b. Moles of N2O4 in mixture are 66.52
c. Weight of NO2 in mixture is 1540 g
d. Weight of N2O4 in mixture is 1540 g
Answer : B,D

Question. 100 g CaCO3 reacts with 1litre 1 N HCl. On completion of reaction how much weight of CO2 will be obtain?
a. 5.5 g
b. 11 g
c. 22 g
d. 33 g
Answer : C

Question. 0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be:
a. 32
b. 64
c. 128
d. 256
Answer : C

Question. A mixture of sand and iodine can be separated by:
a. Crystallisation
b. Sublimation
c. Distillation
d. Fractional distillation
Answer : B

Question. In which of the following number, all zeroes are significant?
a. 4,00004
b. 0.0060
c. 20.000
d. 0.800
Answer : A, B, C

Question. The mass of BaCO3 produced when excess CO2 is bubbled through a solution of 0.205 mol Ba(OH)2 is?
a. 81 g
b. 40.5 g
c. 20.25 g
d.162 g
Answer : B

Question. What is the normality of a 1 M solution of H3PO4 ?
a. 0.5 N
b. 1.0 N
c. 2.0 N
d. 3.0 N
Answer : D

Question. Select the correct statements:
a. At STP, volume occupied by one mole liquid water is 22.4 litre
b. Volume occupied by 1g H2 gas at STP is equal to volume occupied by 2 g He at STP
c. 1 g of CH4 real gas occupies 1.4 litre volume at STP
d. SO2Cl2 reacts with H2O to give mixture of H2SO4 , HCl. Aqueous solution of 1 mole SO2Cl2 will be neutralized by 2 mole of Ca(OH)2
Answer : A, B, D

Question. How many grams of caustic potash required to completely neutralise 12.6 gm HNO3 ?
a. 22.4 KOH
b. 1.01 KOH
c. 6.02 KOH
d. 11.2 KOH
Answer : D

Question. The maximum amount of BaSO4 precipitated on mixing equal volumes of BaCl2 (0.5 M) with H2SO4 (1M) will correspond to:
a. 0.5 M
b. 1.0 M
c. 1.5 M
d. 2.0 M
Answer : A

Question. M is the molecular weight of KMnO4 . The equivalent weight of KMnO4 when it is converted into K2MnO4 is?
a. M
b. M/3
c. M/5
d. M/7
Answer : A

Question. The equivalent weight of phosphoric acid (H3PO4) in the reaction NaOH+H3PO4 → NaH2PO4 +H2 O is:
a. 25
b. 49
c. 59
d. 98
Answer : D

Question. Volume of 0.6 M NaOH required to neutraliz 30 cm3 of 0.4 M HCl is:
a. 30 cm3
b. 20 cm3
c. 50 cm3
d. 45 cm3
Answer : B

Question. Which of the statements are true? Where Mw is the molecular weight of the respective compounds:
a. The equivalent weight of Ca3 (PO4)2 is Mw/6.
b. The equivalent weight of Na3 PO4 - 12H2O is Mw/3
c. The equivalent weight of K2SO4 is Mw/2
d. The equivalent weight of potash alum K2SO4Al2(SO4)3 - 24H2O is Mw/8
Answer : ALL

Question. On electrical decomposition of 150 ml dry and pure O2 ,10% of O2 gets changed to O, then the volume of gaseous mixture after reaction and volume of remaining gas left after passing in turpentine oil will be:
a. 145 ml
b. 149 ml
c. 128 ml
d. 125 ml
Answer : A

Question. A solution of M ml M/10 FeSOwas titrated with KMnO4 solution in acidic medium. The amount of KMnO4 used will be:
a. 5 ml of 0.1 M
b. 10 ml of 1.1 M
c. 10 ml of 0.5 M
d. 10 ml of 0.02 M
Answer : D

Question. Which of the following statements are true?
a. One gram atom of carbon contains Avogadro’s number of atoms
b. One mole oxygen gas contains Avogardro’s number of molecules
c. One mole of the hydrogen molecules contains Avogardro’s number of atoms
d. One mole of electrons stands for 6.023×1023 electrons
Answer : A, C

Question. Two bulbs A and B contain 16g O2 and 16g O3, respectively.
Which of the statements are true?
a. Both bulbs contain same number of atoms
b. Both bulbs contain different number of atoms
c. Both bulbs contain same number of molecules
d. Bulb A contains NA/2 molecules while bulb B contains
NA/3 molecules. (NA = Avogadro’s number).
Answer : A, D

Question. 2 moles of CaCO3 present in 1 litre aqueous solution has a density equal to 1.2 g/cc equal to:
a. 2 M solution of CaCO3
b. 4 N solution of CaCO3
c. Solution with mole fraction of CaCO3 is 0.0347
d. Solution which contains 55.5 moles of water
Answer : ALL

Question. A bulb contains 1.6 g of O2. It contains.
a. 0.05 mol of O2
b. 3.011×1022 molecules of O2
c. 1.12 L of O2 at STP
d. 1.22 L of O2 at SATP
Answer : ALL

Assertion and Reason

Note: Read the Assertion (A) and Reason (R) carefully to mark the correct option out of the options given below:
a. If both assertion and reason are true and the reason is the correct explanation of the assertion.
b. If both assertion and reason are true but reason is not the correct explanation of the assertion.
c. If assertion is true but reason is false.
d. If the assertion and reason both are false.
e. If assertion is false but reason is true.

Question. Assertion: One mole of SO2 contains double the number of molecules present in one mole of O2.
Reason: Molecular weight of SO2 is double to that of O2.
Answer : E

Question. Assertion: Atoms can neither be created nor destroyed.
Reason: Under similar condition of temperature and pressure, equal volume of gases does not contain equal number of atoms.
Answer : 

Question. Assertion: Molecular weight of oxygen is 16.
Reason: Atomic weight of oxygen is 16.
Answer : E

Question. Assertion: As mole is the basic chemical unit, the concentration of the dissolved solute is usually specified in terms of number of moles of solute.
Reason: The total number of molecules of reactants involved in a balanced chemical equation is known as molecularity of the reaction.
Answer : B

Question. Assertion: 22.4 L of N2 at NTP and 5.6 L O2 at NTP contain equal number of molecules.
Reason: Under similar conditions of temperature and pressure all gases contain equal number of molecules.
Answer : D

Question. Assertion: One atomic mass unit (amu) is mass of an atom equal to exactly one-twelfth the mass of a carbon-12 atom.
Reason: Carbon-12 isotope was selected as standard.
Answer : A

Question. Assertion: Volume of a gas is inversely proportional to the number of moles of a gas.
Reason: The ratio by volume of gaseous reactants and products is in agreement with their mole ratio.
Answer : E

Question. Assertion: Equivalent weight of Cu in CuO is 63.6 and in Cu2O31.8.
Reason: Equivalent weight of an element
= Atomic weight of the element / Valency of the element
Answer : E

Question. Assertion: 1 amu equals to 1.66x10–24 g.
Reason: 1.66×10–24g equals to (1/12)th of mass of C12 atom.
Answer : A

Question. Assertion: Atomicity of oxygen is 2.
Reason: 1 mole of an element contains 6.023×1023 atoms.
Answer : B

Comprehension Based

Paragraph –I

An aqueous solution of NaOH having density 1.1 kg / dmcontains 0.02 mole fraction of NaOH.

Question. The molality and molarity of NaOH solution respectively are:
a. 0.986, 1.134
b. 1.134, 1.193
c. 1.134, 1.02
d. 1.034, 1.134
Answer : B

Question. The % by weight of NaOH solution is:
a. 4.34
b. 2.17
c. 5.28
d. 8.34
Answer : A

Question. The strength of NaOH solution is:
a. 30.44
b. 45.36
c. 39.44
d. 47.7
Answer : D

Question. The pH of NaOH solution is:
a. 13.9939
b. 0.0061
c. 12.0218
d. 14
Answer : D

Question. Volume of water required to prepare 1 litre 0.5 M solution of NaOH from V mL solution of NaOH: [V < 1000 mL]
a. 336 mL
b. 118 mL
c. 653 mL
d. 580 mL
Answer : D

Question. Number of molecules of NaOH present in its 10 mL solution is:
a. 6.023x1023
b. 5.94x1025
c. 6.023x1020
d. 7.18x1025
Answer : D

Question. The 10 mL NaOH solution is completely neutralized by 0.1 M H2SO4 . The volume of H2SO4 needed is:
a. 98.6 mL

b. 49.3 mL
c. 24.7 mL
d. 59.65 mL

Answer : D

1. What is stoichiometry?

 2. How much potassium chlorate should be heated to produce 2.24L of oxygen at NTP?

 3. Write an expression for molarity and molality of a solution.

4. Calculate the weight of lime (CaO) obtained by heating 2000kg of 95% pure lime stone (CaCO3)

5. The substance which gets used up in any reaction is called --------------

6. What is 1molal solution?

7. 4 litres of water are added to 2L of 6 molar HCl solutions.

What is the molarity of resulting solution?

8. What volume of 10M HCl and 3M HCl should be mixed to obtain 1L of 6M HCl solution? 

Click on link below to download CBSE Class 11 Stoichiometry and Stoichiometric Calculations Worksheet A.

Chapter 1 Some Basic Concepts of Chemistry CBSE Class 11 Chemistry Worksheet

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