Read and download free pdf of CBSE Class 11 Chemistry Thermodynamics Worksheet Set A. Download printable Chemistry Class 11 Worksheets in pdf format, CBSE Class 11 Chemistry Chapter 6 Thermodynamics Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Chemistry Class 11 Assignments and practice them daily to get better marks in tests and exams for Class 11. Free chapter wise worksheets with answers have been designed by Class 11 teachers as per latest examination pattern
Chapter 6 Thermodynamics Chemistry Worksheet for Class 11
Class 11 Chemistry students should refer to the following printable worksheet in Pdf in Class 11. This test paper with questions and solutions for Class 11 Chemistry will be very useful for tests and exams and help you to score better marks
Class 11 Chemistry Chapter 6 Thermodynamics Worksheet Pdf
Question. Which of the following are not state functions?
(I) q + w (II) q
(III) w (IV) H – TS
(a) (I), (II) and (III)
(b) (II) and (III)
(c) (I) and (IV)
(d) (II), (III) and (IV)
Answer. B
Question. In a closed insulated container a liquid is stirred with a paddle to increase the temperature, which of the following is true?
(a) ΔE = W ≠ 0, q = 0
(b) ΔE = W = q ≠ 0
(c) ΔE = 0, W = q ≠ 0
(d) W = 0, ΔE = q ≠ 0
Answer. A
Question. Which of the following is the correct equation?
(a) ΔU = ΔW + ΔQ
(b) ΔU = ΔQ – W
(c) ΔW = ΔU + ΔQ
(d) None of these
Answer. B
Question. The correct option for free expansion of an ideal gas under adiabatic condition is
(a) q = 0, ΔT = 0 and w = 0
(b) q = 0, ΔT < 0 and w > 0
(c) q < 0, ΔT = 0 and w = 0
(d) q > 0, ΔT > 0 and w > 0
Answer. A
Question. Under isothermal conditions, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]
(a) 30 J
(b) –30 J
(c) 5 kJ
(d) 25 J
Answer. B
Question. An ideal gas expands isothermally from 10–3 m3 to 10–2 m3 at 300 K against a constant pressure of 105 N m–2. The work done on the gas is
(a) +270 kJ
(b) –900 J
(c) +900 kJ
(d) –900 kJ
Answer. B
Question. A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 atm from an initial volume of 2.50 L to a final volume of 4.50 L. The change in internal energy DU of the gas in joules will be
(a) –500 J
(b) –505 J
(c) +505 J
(d) 1136.25 J
Answer. B
Question. Equal volumes of two monatomic gases, A and B at same temperature and pressure are mixed. The ratio of specific heats (CP/CV) of the mixture will be
(a) 0.83
(b) 1.50
(c) 3.3
(d) 1.67
Answer. D
Question. Which of the following is correct option for free expansion of an ideal gas under adiabatic condition?
(a) q = 0, ΔT ≠ 0, w = 0
(b) q ≠ 0, ΔT = 0, w = 0
(c) q = 0, ΔT = 0, w = 0
(d) q = 0, ΔT < 0, w ≠ 0
Answer. C
Question. Three moles of an ideal gas expanded spontaneously into vacuum. The work done will be
(a) infinite
(b) 3 Joules
(c) 9 Joules
(d) zero.
Answer. D
Question. Assume each reaction is carried out in an open container. For which reaction will ΔH = ΔE?
(a) 2CO(g) + O2(g) → 2CO2(g)
(b) H2(g) + Br2(g) → 2HBr(g)
(c) C(s) + 2H2O(g) → 2H2(g) + CO2(g)
(d) PCl5(g) → PCl3(g) + Cl2(g)
Answer. B
Question. The work done during the expansion of a gas from a volume of 4 dm3 to 6 dm3 against a constant external pressure of 3 atm is (1 L atm = 101.32 J)
(a) – 6 J
(b) – 608 J
(c) + 304 J
(d) – 304 J
Answer. B
Question. For the reaction, C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) at constant temperature, ΔH – ΔE is
(a) + RT
(b) –3RT
(c) +3RT
(d) –RT
Answer. B
Question. The molar heat capacity of water at constant pressure, C , is 75 J K–1 mol–1. When 1.0 kJ of heat is supplied to 100 g of water which is free to expand, the increase in temperature of water is
(a) 1.2 K
(b) 2.4 K
(c) 4.8 K
(d) 6.6 K
Answer. B
Question. When 1 mol of gas is heated at constant volume temperature is raised from 298 to 308 K. Heat supplied to the gas is 500 J. Then which statement is correct?
(a) q = w = 500 J, ΔE = 0
(b) q = ΔE = 500 J, w = 0
(c) q = w = 500 J, ΔE = 0
(d) ΔE = 0, q = w = –500 J
Answer. B
Question. For the reaction,
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l) which one is true?
(a) ΔH = ΔE – RT
(b) ΔH = ΔE + RT
(c) ΔH = ΔE + 2RT
(d) ΔH = ΔE – 2RT
Answer. A
Question. In an endothermic reaction, the value of ΔH is
(a) negative
(b) positive
(c) zero
(d) constant.
Answer. B
Question. One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litres. The DE for this process is (R = 2 cal mol–1 K–1)
(a) 1381.1 cal
(b) zero
(c) 163.7 cal
(d) 9 L atm
Answer. B
Question. During isothermal expansion of an ideal gas, its
(a) internal energy increases
(b) enthalpy decreases
(c) enthalpy remains unaffected
(d) enthalpy reduces to zero.
Answer. C
Question. For the reactionm, N2 + 3H2 ⇔ 2NH3, ΔH = ?
(a) ΔE + 2RT
(b) ΔE – 2RT
(c) ΔH = RT
(d) ΔE – RT
Answer. B
Question. If ΔH is the change in enthalpy and ΔE, the change in internal energy accompanying a gaseous reaction, then
(a) ΔH is always greater than ΔE
(b) ΔH < ΔE only if the number of moles of the products is greater than the number of moles of the reactants
(c) ΔH is always less than ΔE
(d) ΔH < ΔE only if the number of moles of products is less than the number of moles of the reactants.
Answer. D
Question. Standard enthalpy of vaporisation DvapH° for water at 100°C is 40.66 kJ mol–1. The internal energy of vaporisation of water at 100°C (in kJ mol–1) is
(a) +37.56
(b) – 43.76
(c) + 43.76
(d) + 40.66
(Assume water vapour to behave like an ideal gas)
Answer. A
Question. Consider the following processes :
ΔH (kJ/mol)
1/2A → B +150
3B → 2C + D –125
E + A → 2D +350
For B + D → E + 2C, ΔH will be
(a) 525 kJ/mol
(b) –175 kJ/mol
(c) –325 kJ/mol
(d) 325 kJ/mol
Answer. B
Question. The following two reactions are known
Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g); ΔH = –26.8 kJ
FeO(s) + CO(g) → Fe(s) + CO2(g); ΔH = – 16.5 kJ
The value of ΔH for the following reaction
Fe2O3(s) + CO(g) → 2FeO(s) + CO2(g) is
(a) + 10.3 kJ
(b) – 43.3 kJ
(c) – 10.3 kJ
(d) + 6.2 kJ
Answer. D
Question. For which one of the following equations is ΔH°reaction equal to ΔH°f for the product?
(a) N2(g) + O3(g) → N2O3(g)
(b) CH4(g) + 2Cl2(g) → CH2Cl2(l) + 2HCl(g)
(c) Xe(g) + 2F2(g) → XeF4(g)
(d) 2CO(g) + O2(g) → 2CO2(g)
Answer. C
Question. Heat of combustion DH for C(s), H2(g) and CH4(g) are –94, –68 and –213 kcal/mol, then DH for C(s) + 2H2(g) → CH4(g) is
(a) –17 kcal
(b) –111 kcal
(c) –170 kcal
(d) –85 kcal
Answer. A
Question. Change in enthalpy for reaction,2H2O2(l) → 2H2O(l) + O2(g) if heat of formation of H2O2(l) and H2O(l) are –188 and –286 kJ/mol respectively, is
(a) –196 kJ/mol
(b) +196 kJ/mol
(c) +948 kJ/mol
(d) –948 kJ/mole
Answer. A
Question. Enthalpy of CH4 + 1/2 O2 → CH3OH is negative. If enthalpy of combustion of CH4 and CH3OH are x and y respectively, then which relation is correct?
(a) x > y
(b) x < y
(c) x = y
(d) x ≥ y
Answer. A
Question. In the reaction : S + 3/2O2 → SO3 + 2x kcal and SO2 + 1/2 O2 → SO3 + y kcal, the heat of formation of SO2 is
(a) (2x + y)
(b) (x – y)
(c) (x + y)
(d) (2x – y)
Answer. D
Question. If enthalpies of formation for C2H4(g), CO2(g) and H2O(l) at 25°C and 1 atm pressure are 52, – 394 and – 286 kJ/mol respectively, then enthalpy of combustion of C2H4(g) will be
(a) + 141.2 kJ/mol
(b) + 1412 kJ/mol
(c) – 141.2 kJ/mol
(d) – 1412 kJ/mol
Answer. D
Question. The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5 : 1. DH for the formation of XY is –200 kJ mol–1. The bond dissociation energy of X2 will be
(a) 200 kJ mol–1
(b) 100 kJ mol–1
(c) 800 kJ mol–1
(d) 400 kJ mol–1
Answer. C
Question. The heat of combustion of carbon to CO2 is –393.5 kJ/mol. The heat released upon formation of 35.2 g of CO2 from carbon and oxygen gas is
(a) + 315 kJ
(b) – 630 kJ
(c) – 3.15 kJ
(d) – 315 kJ
Answer. None
Question. When 5 litres of a gas mixture of methane and propane is perfectly combusted at 0°C and 1 atmosphere, 16 litres of oxygen at the same temperature and pressure is consumed. The amount of heat released from this combustion in kJ (ΔHcomb (CH4) = 890 kJ mol–1,ΔHcomb. (C3H8) = 2220 kJ mol–1) is
(a) 38
(b) 317
(c) 477
(d) 32
Answer. B
Short Answer
Question. What are reversible processes?
Answer. A process or change is said to be reversible, if a change is brought out in such a way that the process could at any moment, be reversed by an infinitesimal change. A reversible process precedes infinitely slowly by a series of the equilibrium states such that system and the surroundings are always in near equilibrium with each other.
Question. What do you mean by the term the state of the system?
Answer. Thermodynamic state of a system is its condition at a specific time, which is fully identified by values of a suitable set of parameters known as state variables or state parameters or thermodynamic variables. A thermodynamic system is not simply a physical system.
Question. What is the first law of thermodynamics?
Answer. The first law of thermodynamics is also known as Law of Conservation of Energy, it states that energy can neither be created nor destroyed, energy can only be transferred or changed from one form to another, for example: humans can convert the chemical energy in food, like this ice cream cone, into kinetic energy by riding a bicycle.
Question. How extensive properties are different form the intensive properties?
Answer. 1. Intensive properties are physical properties that do not depend on the amount of matter whereas extensive properties are physical properties that depend on the amount of matter.
2. Intensive properties are independent of the amount of matter whereas extensive properties depend on the amount of matter.
Question. What is the difference between delta H and delta U?
Answer. Delta H is the change in enthalpy which is equal to change in U +P*change in V whereas the delta U is the change in internal energy of the system.
ΔH is the change in enthalpy .Since H=U+PV. SO, ΔH=ΔU+ PΔV + VΔP.
So, ΔH=dQ + VΔP. Also, ΔH= Cp Δ T.Cp = heat capacity at constant pressure.
Long Answer
Question. State the differences between reversible and irreversible process?
Answer. 1. Reversible process is a slow process going through a series of smaller stages with each stage maintaining equilibrium between the system and surroundings whereas irreversible process is the process of the system attains final state from the initial state with a measurable speed. During the transformation there is no equilibrium maintained between the system and surroundings.
2. A reversible process can be brought back to the initial state without making an change in the adjacent surroundings whereas an irreversible process cannot be brought back to its initial state without making a change in the surroundings.
3. A reversible process can be made to proceed in forward or backward direction whereas an irreversible process can take place in only one direction.
4. A reversible process work done in a greater than the corresponding work done in irreversible process whereas in irreversible process work done is always lower than the same kind of work done in a reversible process.
5. A reversible process can be reserved whereas irreversible process cannot be reserved.
6. Reversible process infinite changes occur in the system whereas irreversible process finite changes occur in the system.
Question. Explain about system and types of system?
Answer. A system in thermodynamics refers to that part of the universe in which observations are made and remaining universe constitutes the surroundings. System and surrounding together constitute the universe. The system according to the movements of the matter and energy in or out of the system. There are three types of the system:
1. Open system: An open system is a system that has external interactions. An open system is contrasted with the concept of an isolated system which exchanges neither energy, nor matter, nor information with its environment.
An open system is also known as a flow system. Organisations as open system have several characteristics or attributes such as boundary, inputs, throughputs or transformation process, outputs, feedback and environments. These attributes have to exist in any open organisations.
2. Closed system: A closed system can exchange energy as heat or work but not matter, with its surroundings. It allows heat to be transferred from the stove to the water. Heat is also transferred to the surroundings. Steam is not allowed to escape.
3. Isolated system: An isolated system is a thermodynamic system that cannot exchange either energy or matter outside the boundaries of the system. The system may be so distant from another system that it cannot interact with them.
The system may be enclosed such that neither energy nor mass may enter or exit.
Question. Write short note on standard enthalpy of reactions?
Answer. Standard enthalpy of reaction is the change in the enthalpy of a chemical reaction that occurs at a constant pressure. It is a thermodynamic unit of measurement useful for calculating the amount of energy per mole either released or produced in a reaction. It is also known as heat of reaction. The standard enthalpy change of a reaction is the enthalpy change which occurs when equation quantities of materials react under standard conditions, and with everything in its standard state. The change in enthalpy does not depend upon the particular pathway of a reaction, but only upon the overall energy level of the products and reactants; enthalpy is a state function, and as such, it is additive. In order to calculate the standard enthalpy of a reaction, we can sum up the standard enthalpies of formation of the reactants and subtract this from the sum of the standard enthalpies of formation of the products.
Question. Explain about heat capacity?
Answer. Heat capacity of a system is defined as the amount of heat required to raise the temperature of the system through 1°C. Molar heat capacity of a substance is defined as the amount of heat required to raise the temperature of 1 mole of a substance through 1° C. Heat capacity is an extensive property. The corresponding intensive property is the specific heat capacity. Dividing the heat capacity by the amount of substance in moles yields its molar heat capacity. The volumetric heat capacity measures the heat capacity per volume. Heat capacity is often referred to as thermal mass in architecture and civil engineering to refer to the heat capacity of a building. The unit of specific heat is J/kg.K. Cp = heat capacity at constant pressure. Cv = heat capacity at constant volume. Constant volume indicates that there is no change in volume. Therefore the only change in the system is internal energy of the system, due to the addition of heat. The heat capacity is the slope of the plot of internal energy U with temperature T. At very high temperatures many, many energy levels are populated and so the rate of increase becomes constant as the temperature increases and so the heat capacity becomes constant, i.e. it levels out to a maximum value.
Question. What are the enthalpy changes during phase transformations?
Answer. Enthalpy changes during phase transitions, is the enthalpy of fusion is the enthalpy change accompanying the transformation of one mole of a solid substance into its liquid state at its melting point. It is also known as molar enthalpy of fusion. The molar enthalpy of fusion (Δ fus H) of ice is +6 KJ mol-1. All phase changes are accompanied by changes in the energy of a system. The energy required to melt 1 mol of a substance is its enthalpy of fusion (ΔH fus). The energy change required to vaporize 1 mol of a substance is the enthalpy of vaporization (ΔH vap). The direct conversion of a solid to a gas is sublimation. It does not represent enthalpy change during phase transformation. While enthalpy of fusion, vaporization and sublimation represents enthalpy change during transformation from solid to liquid, liquid to gas and solid to gas respectively. The magnitude of the enthalpy change depends upon on the strength of the intermolecular interactions on the substances undergoing the phase transformation.
Chapter 6 Thermodynamics CBSE Class 11 Chemistry Worksheet
The above practice worksheet for Chapter 6 Thermodynamics has been designed as per the current syllabus for Class 11 Chemistry released by CBSE. Students studying in Class 11 can easily download in Pdf format and practice the questions and answers given in the above practice worksheet for Class 11 Chemistry on a daily basis. All the latest practice worksheets with solutions have been developed for Chemistry by referring to the most important and regularly asked topics that the students should learn and practice to get better scores in their examinations. Studiestoday is the best portal for Printable Worksheets for Class 11 Chemistry students to get all the latest study material free of cost. Teachers of studiestoday have referred to the NCERT book for Class 11 Chemistry to develop the Chemistry Class 11 worksheet. After solving the questions given in the practice sheet which have been developed as per the latest course books also refer to the NCERT solutions for Class 11 Chemistry designed by our teachers. After solving these you should also refer to Class 11 Chemistry MCQ Test for the same chapter. We have also provided a lot of other Worksheets for Class 11 Chemistry which you can use to further make yourself better in Chemistry.
You can download the CBSE Practice worksheets for Class 11 Chemistry Chapter 6 Thermodynamics for the latest session from StudiesToday.com
Yes, the Practice worksheets issued for Chapter 6 Thermodynamics Class 11 Chemistry have been made available here for the latest academic session
There is no charge for the Practice worksheets for Class 11 CBSE Chemistry Chapter 6 Thermodynamics you can download everything free
Regular revision of practice worksheets given on studiestoday for Class 11 subject Chemistry Chapter 6 Thermodynamics can help you to score better marks in exams
Yes, studiestoday.com provides all the latest Class 11 Chemistry Chapter 6 Thermodynamics test practice sheets with answers based on the latest books for the current academic session