CBSE Class 11 Chemistry States of Matter Worksheet Set A

Read and download free pdf of CBSE Class 11 Chemistry States of Matter Worksheet Set A. Download printable Chemistry Class 11 Worksheets in pdf format, CBSE Class 11 Chemistry Chapter 5 States of Matter Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Chemistry Class 11 Assignments and practice them daily to get better marks in tests and exams for Class 11. Free chapter wise worksheets with answers have been designed by Class 11 teachers as per latest examination pattern

Chapter 5 States of Matter Chemistry Worksheet for Class 11

Class 11 Chemistry students should refer to the following printable worksheet in Pdf in Class 11. This test paper with questions and solutions for Class 11 Chemistry will be very useful for tests and exams and help you to score better marks

Class 11 Chemistry Chapter 5 States of Matter Worksheet Pdf

Question. Select one correct statement. In the gas equation,PV = nRT
(a) n is the number of molecules of a gas
(b) V denotes volume of one mole of the gas
(c) n moles of the gas have a volume V
(d) P is the pressure of the gas when only one mole of gas is present. 
Answer. C

Question. At constant temperature, in a given mass of an ideal gas
(a) the ratio of pressure and volume always remains constant
(b) volume always remains constant
(c) pressure always remains constant
(d) the product of pressure and volume always remains constant. 
Answer. D

Question. If P, V, M, T and R are pressure, volume, molar mass, temperature and gas constant respectively, then for an ideal gas, the density is given by
(a) RT/PM
(b) P/RT
(c) M/V
(d) PM.RT
Answer. D

Question. By what factor does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is doubled?
(a) 2.0
(b) 2.8
(c) 4.0
(d) 1.4 
Answer. D

Question. The temperature of a gas is raised from 27°C to 927°C. The root mean square speed of the gas
(a) remains same
(b) gets √92727 times
(c) gets halved
(d) gets doubled. 
Answer. D

Question. The ratio among most probable velocity, mean velocity and root mean square velocity is given by
(a) 1 : √2 : √3
(b) 1: 2 : 3
(c) √2 :√3 : √8 / π
(d) √2 : √8 / π : √3
Answer. D

Question. The root mean square velocity at STP for the gases H2, N2, O2 and HBr are in the order
(a) H2 < N2 < O2 < HBr
(b) HBr < O2 < N2 < H2
(c) H2 < N2 = O2 < HBr
(d) HBr < O2 < H2 < N2
Answer. B

Question. Root mean square velocity of a gas molecule is proportional to
(a) m1/2
(b) m0
(c) m–1/2
(d) m
Answer. C

Question. The energy absorbed by each molecule (A2) of a substance is 4.4 × 10–19 J and bond energy per molecule is 4.0 × 10–19 J. The kinetic energy of the molecule per atom will be
(a) 2.2 × 10–19 J
(b) 2.0 × 10–19 J
(c) 4.0 × 10–20 J
(d) 2.0 × 10–20
Answer. D

Question. If a gas expands at constant temperature, it indicates that
(a) kinetic energy of molecules remains the same
(b) number of the molecules of gas increases
(c) kinetic energy of molecules decreases
(d) pressure of the gas increases. 
Answer. A

Question. Average molar kinetic energy of CO and N2 at same temperature is
(a) KE1 = KE2
(b) KE1 > KE2
(c) KE< KE2
(d) can’t say anything. Both volumes are not given.
Answer. A

Question. The average kinetic energy of an ideal gas, per molecule in S.I. units, at 25°C will be
(a) 6.17 × 10–20 J
(b) 7.16 × 10–20 J
(c) 61.7 × 10–20 J
(d) 6.17 × 10–20
Answer. D

Question. At STP, 0.50 mol H2 gas and 1.0 mol He gas
(a) have equal average kinetic energies
(b) have equal molecular speeds
(c) occupy equal volumes
(d) have equal effusion rates.
Answer. A

Question. A closed flask contains water in all its three states solid, liquid and vapour at 0°C. In this situation, the average kinetic energy of water molecules will be
(a) the greatest in all the three states
(b) the greatest in vapour state
(c) the greatest in the liquid state
(d) the greatest in the solid state.
Answer. B

Question. Which is not true in case of an ideal gas?
(a) It cannot be converted into a liquid.
(b) There is no interaction between the molecules.
(c) All molecules of the gas move with same speed.
(d) At a given temperature, PV is proportional to the amount of the gas.
Answer. C

Question. A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is
(a) Z < 1 and repulsive forces are dominant
(b) Z > 1 and attractive forces are dominant
(c) Z > 1 and repulsive forces are dominant
(d) Z < 1 and attractive forces are dominant.
Answer. D

Question. A gas such as carbon monoxide would be most likely to obey the ideal gas law at
(a) low temperatures and high pressures
(b) high temperatures and high pressures
(c) low temperatures and low pressures
(d) high temperatures and low pressures. 
Answer. D

Question. Maximum deviation from ideal gas is expected from
(a) CH4(g)
(b) NH3(g)
(c) H2(g)
(d) N2(g)
Answer. B

Question. van der Waals’ real gas, acts as an ideal gas, at which conditions?
(a) High temperature, low pressure
(b) Low temperature, high pressure
(c) High temperature, high pressure
(d) Low temperature, low pressure
Answer. A

Question. When is deviation more in the behaviour of a gas from the ideal gas equation PV = nRT?
(a) At high temperature and low pressure
(b) At low temperature and high pressure
(c) At high temperature and high pressure
(d) At low temperature and low pressure 
Answer. B

Question. A gas is said to behave like an ideal gas when the relation PV/T = constant. When do you expect a real gas to behave like an ideal gas?
(a) When the temperature is low.
(b) When both the temperature and pressure are low.
(c) When both the temperature and pressure are high.
(d) When the temperature is high and pressure is low. 
Answer. D

Question. In van der Waals’ equation of state for a non-ideal gas, the term that accounts for intermolecular forces is
(a) (V – b)
(b) (RT)–1
(c) (P + a /V2)
(d) RT
Answer. C

Question. Given van der Waals’ constant for NH3, H2, O2 and CO2 are respectively 4.17, 0.244, 1.36 and 3.59, which one of the following gases is most easily liquefied?
(a) NH3
(b) H2
(c) O2
(d) CO2
Answer. A

Question. An ideal gas, obeying kinetic theory of gases cannot be liquefied, because
(a) it solidifies before becoming a liquid
(b) forces acting between its molecules are negligible
(c) its critical temperature is above 0°C
(d) its molecules are relatively small in size. 
Answer. B

Question. The beans are cooked earlier in pressure cooker because
(a) boiling point increases with increasing pressure
(b) boiling point decreases with increasing pressure
(c) extra pressure of pressure cooker softens the beans
(d) internal energy is not lost while cooking in pressure cooker.
Answer. A

 
 
Very Short Answer
 
Question. Who proposed the force of attraction? 
Answer. The force of attraction was proposed by the Fritz London.
 
Question. What are intermolecular forces? 
Answer. Intermolecular forces are the forces are the forces of the attraction and repulsion between interacting particles.
 
Question. What is isochore? 
Answer. Each line of the graph is called isochore.
 
Question. What is the other name for the attractive intermolecular? 
Answer. Attractive intermolecular forces are also known as van der Waals forces.
 
Question. What is thermodynamic scale?
Answer. Kelvin scale is also called thermodynamic scale.
 

Short Answer

Question. What do you mean by the thermal energy? 
Answer. Thermal energy is the energy of a body arising from the motion of its atoms or molecules. The atoms or molecules of a hotter object have greater kinetic energy than those of a colder one, in the form of vibrational, rotational, or, in the case of a gas, translational motion.

Question. What do you mean by the term dipole-induced dipole forces? 
Answer. A dipole-induced dipole attraction is a weak attraction that results when a polar molecule induces a dipole in an atom or in a nonpolar molecule by disturbing the arrangement of electrons in the nonpolar species, for example: hydrogen chloride (HCl): the positive end of a polar molecule will attract the negative end of the other molecule and influence its position. Polar molecules have a net attraction between them.

Question. Define thermal interaction? 
Answer. Thermal interaction, or heat energy transfer, to take place, two bodies must be in contact whether this be the particles of air in contact with your skin to make you feel warm or cold, or the thermal interaction that takes place when an ice cube is dropped into a bowl of warm water.

Question. What is absolute zero?
Answer. Absolute zero is the lowest possible temperature where nothing could be colder and no heat energy remains in a substance. International agreement, absolute zero is defined as precisely; 0 K on the Kelvin scale, which is a thermodynamic (absolute) temperature scale; and –273.15 degrees celsius on the celsius scale.

Question. What do you mean by the Gay Lussac’s Law?
Answer. Gay Lussac’s Law states that at constant volume, pressure of a fixed amount of a gas varies directly with the temperature.
Mathematically p ∝ T
= P / T = constant = k3
Pressure and temperature at constant volume are directly proportional.

 

Long Answer

Question. Explain the Avogadro Law? 
Answer. 
Avogadro's law states that investigates the relationship between the amount of gas (n) and volume (v). In the industrial synthesis of methanol, knowing the temperature and pressure makes it easier for experts to calculate molar amounts that permit good estimation of stoichiometric relationships in the system. Avogadro's laws mathematical formula as: V ∝ n or V/n = k. Where V is the volume of the gas, “n” is the amount of the gas (number of moles of the gas) and k is a constant for a given pressure and temperature. The number of the molecules in one mole of a gas has been determined to be 6.022 * 1023 and is known as the Avogadro constant. The law is approximately valid for real gases at sufficiently low pressures and high temperatures. The important features for the Avogadro’s law are:
1. The molar volume of all ideal gases at 0°C and 1 atom pressure is 22.4 liter.
2. If pressure and temperature of a gas are constant, when the amount of gas increases, the volume increases.
3. If pressure and temperature of a gas are constant, when the amount of gas decreases, the volume decreases.
For example: the molecular weight of oxygen is 32.00, so that one gram-mole of oxygen has a mass of 32.00 grams and contains 6.02214076 × 1023 molecules.

Question. Difference between London forces and dipole-dipole forces? 
Answer. 1. London forces are attractive forces between all kinds of molecules including polar, non-polar, ions, and noble gasses whereas dipole-dipole forces are attractive forces between molecules with permanent dipole movements.
2. London forces have higher bond strength whereas dipole-dipole forces have weaker bond strength.
3. London forces occur when a positively charged nucleus of an atom attracts the electron cloud of another atom whereas dipole-dipole forces occur when there is an unequal sharing of electrons between two atoms.
4. London forces instantaneous dipoles must exist whereas dipole-dipole forces have weaker bond strength.
5. London forces are the attraction between two non-polar molecules whereas dipole-dipole forces are the attraction between two polar molecules.

Question. Explain about Charles’ Law? 
Answer. 
Charles law states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature. As the volume goes up, the temperature also goes up, and vice-versa. The volume of a fixed mass of a gas decreases on cooling it and increases by increasing the temperature. For one degree rise in temperature, the volume of the gas increases by its original volume at 0˚C. The temperature in Kelvin can be calculated via Tk = TC + 273.15. A plot of the temperature in Kelvin. Charles' law predicts that volume will be zero at 0 K. 0 K is the absolutely lowest temperature possible, and is called absolute zero. Charles' Law gives the relationship between volume and temperature if pressure and amount of gas are held constant. If the volume of a container is increased, the temperature increases. If the amount of gas in a container is increased, the volume increases.
Mathematically, the direct relationship of Charles's Law can be represented by the following equation:
VT=k
V / T = constant = k2.

Question. Explain the Boyle’s Law? 
Answer. Boyle's law also known as Mariotte's law and the Boyle-Mariotte law, it is a law about ideal gases. The volume of a constant mass of ideal gas at a constant temperature is inversely proportional to the pressure applied on it. This empirical relation, formulated by the physicist Robert Boyle in 1662. Boyle's Law states that the pressure (P) of a gas is inversely proportional to the volume (V). This law is valid as long as the temperature and the amount of gas are constant. Any units will work here: PV=k (constant). The constant k will depend on the number of moles and the temperature.
For example: When the plunger on a sealed syringe is pushed, the pressure increases and the volume decreases. The pressure decreases dramatically as they are raised, increasing the volume of gases in their blood and swim bladder. Boyle's law is important because it tells us about the behaviour of gasses. It explains, with certainty, that the pressure and volume of gas are inversely proportional to one another. So, if we push on gas, its volume becomes smaller and the pressure becomes higher. Boyle's Law is used to predict the result of introducing a change in volume and pressure only, and only to the initial state of a fixed quantity of gas.

Question. Explain the gaseous state and its physical properties?
Answer. Gas is one of the four fundamental states of matter the others being solid, liquid, and plasma. A pure gas may be made up of individual atoms, elemental molecules made from one type of atom or compound molecules made from a variety of atoms. Gas is a state of matter that has no fixed shape and no fixed volume. Gases have lower density than other states of matter, such as solids and liquids. There is a great deal of empty space between particles, which have a lot of kinetic energy. There is a great deal of empty space between particles, which have a lot of kinetic energy. The particles move very fast and collide into one another, causing them to diffuse, or spread out, until they are evenly distributed throughout the volume of the container. The gaseous state is characterized by the following physical properties:
1. Gases are highly compressible.
2. Gases exert pressure equally in all the directions.
3. Gasses have much lower density than the solids and liquids.
4. Gasses mix evenly and completely in all proportions without any mechanical aid.
5. The volume and the shape of the gasses are not fixed.
6. In gasses particles are very loosely packed.
7. Gasses are highly compressible.


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Chapter 5 States of Matter CBSE Class 11 Chemistry Worksheet

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