CBSE Class 11 Chemistry Structure of Atom Worksheet Set A

Read and download free pdf of CBSE Class 11 Chemistry Structure of Atom Worksheet Set A. Download printable Chemistry Class 11 Worksheets in pdf format, CBSE Class 11 Chemistry Chapter 2 Structure of Atom Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Chemistry Class 11 Assignments and practice them daily to get better marks in tests and exams for Class 11. Free chapter wise worksheets with answers have been designed by Class 11 teachers as per latest examination pattern

Chapter 2 Structure of Atom Chemistry Worksheet for Class 11

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Class 11 Chemistry Chapter 2 Structure of Atom Worksheet Pdf

Question. The number of protons, neutrons and electrons in 17571Lu, respectively, are
(a) 71, 104 and 71
(b) 104, 71 and 71
(c) 71, 71 and 104
(d) 175, 104 and 71
Answer. A

Question. Be2+is isoelectronic with which of the following ions?
(a) H+
(b) Li+
(c) Na+
(d) Mg2+
Answer. B

Question. Isoelectronic species are
(a) CO, CN, NO+, C22–
(b) CO, CN, NO, C2–
(c) CO+, CN+, NO, C2
(d) CO, CN, NO, C2
Answer. A

Question. The ion that is isoelectronic with CO is
(a) CN
(b) N2+
(c) O2–
(d) N2– 
Answer. A

Question. Which one of the following is not isoelectronic with O2–?
(a) Tl+
(b) Na+
(c) N3–
(d) F
Answer. A

Question. Which of the following series of transitions in the spectrum of hydrogen atom falls in visible region?
(a) Brackett series
(b) Lyman series
(c) Balmer series
(d) Paschen series
Answer. C

Question. Calculate the energy in joule corresponding to light of wavelength 45 nm.
(Planck’s constant, h = 6.63 × 10–34J s, speed of light,
c = 3 × 108 m s–1)
(a) 6.67 × 1015
(b) 6.67 × 1011
(c) 4.42 × 10–15
(d) 4.42 × 10–18
 Answer. D

Question. The value of Planck’s constant is 6.63 × 10–34Js. The speed of light is 3 × 1017nm s–1. Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 × 1015 s–1?
(a) 50
(b) 75
(c) 10
(d) 25
Answer. A

Question. The value of Planck’s constant is 6.63 × 10–34J s.The velocity of light is 3.0 × 108 m s–1. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8 × 1015s–1 ?
(a) 2 × 10–25
(b) 5 × 10–18
(c) 4 × 101
(d) 3 × 107 
Answer. A

Question. For given energy, E = 3.03 × 10–19joules corresponding wavelength is
(h = 6.626 × 10–34J sec, c = 3 × 108 m/sec)
(a) 65.6 nm
(b) 6.56 nm
(c) 3.4 nm
(d) 656 nm 
Answer. B

Question. What will be the longest wavelength line in Balmer series of spectrum?
(a) 546 nm
(b) 656 nm
(c) 566 nm
(d) 556 nm
Answer. C

Question. According to the Bohr theory, which of the following transitions in the hydrogen atom will give rise to the least energetic photon?
(a) n = 6 to n = 1
(b) n = 5 to n = 4
(c) n = 6 to n = 5
(d) n = 5 to n = 3
Answer. D

Question. The energy of second Bohr orbit of the hydrogen atom is –328 kJ mol–1; hence the energy of fourth Bohr orbit would be
(a) – 41 kJ mol–1
(b) –82 kJ mol–1
(c) –164 kJ mol–1
(d) –1312 kJ mol–1 
Answer. B

Question. The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be
(Given ionization energy of H = 2.18 × 10–18J atom–1 and h = 6.626 × 10–34J s)
(a) 1.54 × 1015 s–1
(b) 1.03 × 1015 s–1
(c) 3.08 × 1015 s–1
(d) 2.00 × 1015 s–1
Answer. B

Question. In hydrogen atom, energy of first excited state is–3.4 eV. Then find out K.E. of same orbit of hydrogen atom.
(a) +3.4 eV
(b) +6.8 eV
(c) –13.6 eV
(d) +13.6 eV
Answer. C

Question. Who modified Bohr’s theory by introducing elliptical orbits for electron path?
(a) Rutherford
(b) Thomson
(c) Hund
(d) Sommerfeld 
Answer. B

Question. The Bohr orbit radius for the hydrogen atom (n = 1) is approximately 0.530 Å. The radius for the first excited state (n = 2) orbit is (in Å)
(a) 4.77
(b) 1.06
(c) 0.13
(d) 2.12
Answer. C

Question. In a Bohr’s model of an atom, when an electron jumps from n = 1 to n = 3, how much energy will be emitted or absorbed?
(a) 2.389 × 10–12ergs
(b) 0.239 × 10–10 ergs
(c) 2.15 × 10–11 ergs
(d) 0.1936 × 10–10 ergs
Answer. A

Question. The radius of hydrogen atom in the ground state is 0.53 Å. The radius of Li2+ion (atomic number = 3) in a similar state is
(a) 0.53 Å
(b) 1.06 Å
(c) 0.17 Å
(d) 0.265 Å 
Answer. D

Question. The spectrum of He is expected to be similar to that
(a) H
(b) Li+
(c) Na
(d) He
Answer. D

Question. If r is the radius of the first orbit, the radius of nth orbit of H-atom is given by
(a) rn2
(b) rn
(c) r/n
(d) r2n2
Answer. D 

Question. In hydrogen atom, the de Broglie wavelength of an electron in the second Bohr orbit is
(a) 211.6 pm
(b) 211.6 p pm
(c) 52.9 p pm
(d) 105.8 pm 
Answer. B

Question. A 0.66 kg ball is moving with a speed of 100 m/s.
The associated wavelength will be (h = 6.6 × 10–34 J s)
(a) 6.6 × 10–32 m
(b) 6.6 × 10–34 m
(c) 1.0 × 10–35 m
(d) 1.0 × 10–32
Answer. C

Question. The measurement of the electron position is associated with an uncertainty in momentum,which is equal to 1 × 10–18 g cm s–1. The uncertainty in electron velocity is (mass of an electron is 9 × 10–28 g
(a) 1 × 105 cm s–1
(b) 1 × 1011 cm s–1
(c) 1 × 109 cm s–1
(d) 1 × 106 cm s–1 
Answer. C

Question. Given : The mass of electron is 9.11 × 10–31 kg, Planck constant is 6.626 × 10–34 J s, the uncertainty involved in the measurement of velocity within a distance of 0.1 Å is
(a) 5.79 × 105 m s–1
(b) 5.79 × 106 m s–1
(c) 5.79 × 107 m s–1
(d) 5.79 × 108 m s–1
Answer. B

Question. The uncertainty in momentum of an electron is 1 × 10–5 kg m/s. The uncertainty in its position will be
(h = 6.62 × 10–34 kg m2/s)
(a) 5.27 × 10–30 m
(b) 1.05 × 10–26 m
(c) 1.05 × 10–28 m
(d) 5.25 × 10–28
Answer. A

Question. The de Broglie wavelength of a particle with mass 1 g and velocity 100 m/s is
(a) 6.63 × 10–35 m
(b) 6.63 × 10–34 m
(c) 6.63 × 10–33 m
(d) 6.65 × 10–35 m
Answer. C

Question. The position of both, an electron and a helium atom is known within 1.0 nm. Further the momentum of the electron is known within 5.0 × 10–26 kg m s–1.
The minimum uncertainty in the measurement of the momentum of the helium atom is
(a) 8.0 × 10–26 kg m s–1
(b) 80 kg m s–1
(c) 50 kg m s–1
(d) 5.0 × 10–26 kg m s–1
Answer. D

Question. Uncertainty in position of an electron (Mass = 9.1 × 10–28 g) moving with a velocity of 3 × 104 cm/s accurate upto 0.001% will be (Use h/(4p) in uncertainty expression where h = 6.626 × 10–27 erg second)
(a) 5.76 cm
(b) 7.68 cm
(c) 1.93 cm
(d) 3.84 cm 
Answer. C

Question. Which of the following statements do not form a part of Bohr’s model of hydrogen atom?
(a) Energy of the electrons in the orbits are quantized.
(b) The electron in the orbit nearest the nucleus has the lowest energy.
(c) Electrons revolve in different orbits around the nucleus.
(d) The position and velocity of the electrons in the orbit cannot be determined simultaneously.
Answer. D

Question. 4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is
(a) 5f > 6p > 4d > 5p
(b) 5f > 6p > 5p > 4d
(c) 6p > 5f > 5p > 4d
(d) 6p > 5f > 4d > 5p
Answer. B

Question. Orbital having 3 angular nodes and 3 total nodes is
(a) 5p
(b) 3d
(c) 4f
(d) 6d
Answer. C

Question. Which one is the wrong statement?
(a) The uncertainty principle is ΔE × Δt ≥ h/4π
(b) Half filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry and more balanced arrangement.
(c) The energy of 2s-orbital is less than the energy of 2p-orbital in case of hydrogen like atoms.
(d) de-Broglie’s wavelength is given by λ = h/mv,where m = mass of the particle, v = group velocity of the particle.
Answer. C

Question. How many electrons can fit in the orbital for which n = 3 and l = 1?
(a) 2
(b) 6
(c) 10
(d) 14
Answer. A

Question. Which of the following pairs of d-orbitals will have electron density along the axes?
(a) dz2, dxz
(b) dxz, dyz
(c) dz2, dx2 – y2
(d) dxy, dx2 – y2
Answer. C

Question. Two electrons occupying the same orbital are distinguished by
(a) azimuthal quantum number
(b) spin quantum number
(c) principal quantum number
(d) magnetic quantum number. 
Answer. B

Question. Which is the correct order of increasing energy of the listed orbitals in the atom of titanium?
(At. no. Z = 22)
(a) 4s 3s 3p 3d
(b) 3s 3p 3d 4s
(c) 3s 3p 4s 3d
(d) 3s 4s 3p 3d 
Answer. C

Question. The number of d-electrons in Fe2+ (Z = 26) is not equal to the number of electrons in which one of the following?
(a) d-electrons in Fe (Z = 26)
(b) p-electrons in Ne (Z = 10)
(c) s-electrons in Mg (Z = 12)
(d) p-electrons in Cl (Z = 17) (2015, Cancelled)
Answer. D

Question. The angular momentum of electron in ‘d’ orbital is equal to
(a) 2 √3h
 (b) 0 h
(c) √6 h
(d) √2 h
Answer. C

Question. What is the maximum number of orbitals that can be identified with the following quantum numbers?
n = 3, l = 1, ml = 0
(a) 1
(b) 2
(c) 3
(d) 4
Answer. A

Question. What is the maximum numbers of electrons that can be associated with the following set of quantum numbers?
n = 3, l = 1 and m = –1
(a) 4
(b) 2
(c) 10
(d) 6
Answer. B

Question. The outer electronic configuration of Gd (At. No. 64) is
(a) 4f 55d46s1
(b) 4f 75d16s2
(c) 4f 35d56s2
(d) 4f 45d56s1
Answer. B

Question. Maximum number of electrons in a subshell with l = 3 and n = 4 is
(a) 14
(b) 16
(c) 10
(d) 12 
Answer. A

Question. The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is
(a) 5, 1, 1, +1/2
(b) 6, 0, 0, +1/2
(c) 5, 0, 0, +1/2
(d) 5, 1, 0, +1/2
Answer. C

Question. The total number of atomic orbitals in fourth energy level of an atom is
(a) 8
(b) 16
(c) 32
(d) 4
Answer. B

Question. If n = 6, the correct sequence for filling of electrons will be
(a) ns → (n – 2)f → (n – 1)d → np
(b) ns → (n – 1)d → (n – 2)f → np
(c) ns → (n – 2)f → np → (n – 1)d
(d) ns → np → (n – 1)d → (n – 2)f 
Answer. A

Question. Maximum number of electrons in a subshell of an atom is determined by the following
(a) 2l + 1
(b) 4l – 2
(c) 2n2
(d) 4l + 2 
Answer. D

Question. Which of the following is not permissible arrangement of electrons in an atom?
(a) n = 5, l = 3, m = 0, s = +1/2
(b) n = 3, l = 2, m = –3, s = –1/2
(c) n = 3, l = 2, m = –2, s = –1/2
(d) n = 4, l = 0, m = 0, s = –1/2 
Answer. B

Question. Consider the following sets of quantum numbers:
      n    l    m    s
(i) 3    0   0   +1/2
(ii) 2   2   1   +1/2
(iii) 4  3  –2   –1/2
(iv) 1  0  –1   –1/2
(v) 3   2   3   +1/2
Which of the following sets of quantum number is not possible?
(a) (i), (ii), (iii) and (iv)
(b) (ii), (iv) and (v)
(c) (i) and (iii)
(d) (ii), (iii) and (iv) 
Answer. B

Question. The orientation of an atomic orbital is governed by
(a) principal quantum number
(b) azimuthal quantum number
(c) spin quantum number
(d) magnetic quantum number.
Answer. D

Question. The following quantum numbers are possible for how many orbitals?
n = 3, l = 2, m = +2
(a) 1
(b) 2
(c) 3
(d) 4 
Answer. A

Question. For which of the following sets of four quantum numbers, an electron will have the highest energy?
      n  l    m        s
(a) 3  2    1    +1/2
(b) 4  2 – 1    +1/2
(c) 4  1    0   –1/2
(d) 5  0    0   –1/2
Answer. B

Question. Electronic configuration of calcium atom can be written as
(a) [Ne]4p2
(b) [Ar]4s2
(c) [Ne]4s2
(d) [Kr]4p2
 Answer. B

Question. In a given atom no two electrons can have the same values for all the four quantum numbers. This is called
(a) Hund’s Rule
(b) Aufbau principle
(c) Uncertainty principle
(d) Pauli’s Exclusion principle.
Answer. D

Question. For azimuthal quantum number l = 3, the maximum number of electrons will be
(a) 2
(b) 6
(c) 0
(d) 14
Answer. D

Question. The order of filling of electrons in the orbitals of an atom will be
(a) 3d, 4s, 4p, 4d, 5s
(b) 4s, 3d, 4p, 5s, 4d
(c) 5s, 4p, 3d, 4d, 5s
(d) 3d, 4p, 4s, 4d, 5s
Answer. B

Question. The electronic configuration of Cu (atomic number 29) is
(a) 1s2 2s22p6 3s23p6 4s23d9
(b) 1s2 2s22p6 3s23p63d10 4s1
(c) 1s2 2s22p6 3s23p6 4s24p6 5s25p1
(d) 1s2 2s22p6 3s23p6 4s24p63d3 
Answer. B

Question. The total number of electrons that can be accommodated in all the orbitals having principal quantum number 2 and azimuthal quantum number 1 are
(a) 2
(b) 4
(c) 6
(d) 8 
Answer. C

Question. An ion has 18 electrons in the outermost shell, it is
(a) Cu+
(b) Th4+
(c) Cs+
(d) K+ 
Answer. A

Question. Number of unpaired electrons in N2+ is/are
(a) 2
(b) 0
(c) 1
(d) 3 
Answer. C

Question. The maximum number of electrons in a subshell is given by the expression
(a) 4l – 2
(b) 4l + 2
(c) 2l + 2
(d) 2n2
Answer. B

Question. The number of spherical nodes in 3p orbitals are/is
(a) one
(b) three
(c) none
(d) two
Answer. A

 
I. Choose The Best Answer
 
1. Packet of energy is called -
(a) Electron          (b) Photon         (c) Position         (d) Proton
 
2.The principal quantum number of an atom is related to the
(a) size of the orbital     (b) spin angular momentum      (c) orbital angular momentum
(d) orientation of the orbital in Space
 
3.What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition n = 4 to n = 2 in the He+ spectrum?
(a) n = 4 to n =1    (b) n = 3 to n = 2     (c) n = 3 to n = 1      (d) n = 2 to n = 1
 
4.An electron is moving in Bohr's orbit. Its de Broglie wavelength is λ. What is the circumference of the forth orbit?
(a) 2/λ                   (b) 2λ                       (c) 3λ                     (d) 3/λ
 
5. For principle quantum number, n = 4, the total number of orbitals having 1 = 3 is
(a) 3                      (b) 7                        (c) 5                       (d) 9
 
 
II. Fill In the Blanks
 
1. Bohr’s theory is based on ________ of radiation.
2. The maximum number of electrons in Fe3+ (At. No. 26) is ________.
3. Li2+ and He+ ions have spectrum similar to ________ atom.
4.The space or three-dimensional region round the nucleus where there is maximum probability of finding an electron of specific energy is called an __________.
5. When there are two electrons in the same orbital they have ____ spins.
 
 
III. Assertion and Reasoning Questions:
 
Directions: (Questions 1 to 4).
 
A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion.
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion.
C. If Assertion is true statement but Reason is false.
D. If both Assertion and Reason are false statements.
 
1. Assertion: Number of orbitals in 3rd shell is 9.
    Reason: Number of orbitals for a particular value of n = n2.
 
2. Assertion: Two nodal planes are present in 3dxy.
    Reason: Number of nodal planes = l
 
3. Assertion: The energy of an electron is largely determined by its principal quantum number.
    Reason: The principal quantum number is a measure of the most probable distance of finding the electrons around the nucleus.
 
4. Assertion: An orbital cannot have more than two electrons, moreover, if an orbital has two electrons they must have opposite spins.
    Reason: No two electrons in an atom can have same set of all the four quantum numbers.
 
 
IV. Two Marks, Three Marks and Five Marks Questions:
 
1. Calculate the energy of each of the photons which
i) correspond to light of frequency 3x 1015 Hz
ii) have wavelength of 0.50 A0
2. Calculate the energy and radius of the first orbit of He+ ion.
3. Calculate the wavelength of the photon that is emitted when an electron in Bohr’s orbit n=2 returns to the orbit n=1 in the hydrogen atom.
4. Calculate the de Broglie wavelength of a bullet of mass 2.2 x 10-3 Kg fired with a velocity of 300 m/s.
5. Calculate the speed of an electron if its de Broglie wavelength is twice its displacement in one second.
6. Calculate the uncertainty in the velocity of a cricket ball if the mass is 200 g. Uncertainty in the position is 1pm.
7. An electron beam from an accelerator is with kinetic energy 1.6 x 10-17J. What is its de Broglie wavelength?
8. A photon of wavelength 4 × 10–7 m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate
(i) the energy of the photon (eV)
(ii) the kinetic energy of the emission, and
(iii) The velocity of the photoelectron (1 eV= 1.6020 × 10–19J).
9. Show that the wavelength related to a 250g object moving with a speed of 100 m/s is too short to be observed.
10. i. State Heisenberg’s uncertainty principle.
ii. A table tennis ball has mass 10g and a speed of 90m/s. If speed can be measured with an accuracy of 4% what will be the uncertainty in the speed and position?
11. Two particles A and B are in motion. If the momentum of A is half of that of B and if the wavelength of A is 4.5 x 102 nm, what is the wavelength of B?
12. What is meant by “Energy of an electron in a hydrogen atom is quantized”
13. i. Explain the dual nature of light.
ii. When would the wavelength associated with an electron be equal to the wavelength associated with a proton?
14. Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800Ao.Calculate the threshold frequency and work function of the metal.
15. Why is the electronic energy of hydrogen negative?

 

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Chapter 2 Structure of Atom CBSE Class 11 Chemistry Worksheet

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