CBSE Class 10 Mathematics Statistics VBQs

CBSE Class 10 Mathematics Statistics VBQs read and download in pdf. Value Based Questions come in exams for Mathematics in Class 10 and are easy to learn and helpful in scoring good marks. You can refer to more chapter wise VBQs for Class 10 Mathematics and also get latest topic wise very useful study material as per latest NCERT book for Class 10 Mathematics and all other subjects for free on Studiestoday designed as per latest Class 10 CBSE, NCERT and KVS syllabus and examination pattern

VBQ for Class 10 Mathematics Chapter 14 Statistics

Class 10 Mathematics students should refer to the following value based questions with answers for Chapter 14 Statistics in Class 10. These VBQ questions with answers for Class 10 Mathematics will come in exams and help you to score good marks

Chapter 14 Statistics VBQ Questions Class 10 Mathematics with Answers

Question. If the sum of frequencies is 24, then the value of x in the observation: x, 5,6,1,2, will be
(a) 4
(b) 6
(c) 8
(d) 10
Answer : D

Question. Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, and 80 were wrongly read as 40, 20, and 50 respectively. The correct mean is
(a) 48
(b) 49
(c) 50
(d) 60
Answer : C

Question. Consider the following frequency distribution:

""CBSE-Class-10-Mathematics-Statistics

The upper limit of the median class is
(a) 17
(b) 17.5
(c) 18
(d) 18.5
Answer : B

Question. Mode is the
(a) middle most frequent value
(b) least frequent value
(c) maximum frequent value
(d) none of these
Answer : C

Question. The algebraic sum of the deviations of a frequency distribution from its mean is always,
(a) greater than zero
(b) less than zero
(c) zero
(d) a non-zero number
Answer : C

Question. The empirical relationship between the three measures of central tendency is
(a) 3 Median = Mode + 2 Mean
(b) 2 Median = Mode + 2 Mean
(c) 3 Median = Mode + Mean
(d) 3 Median = Mode – 2 Mean
Answer : A

Question. Mode and mean of a data are 12k and 15A. Median of the data is
(a) 12k
(b) 14k
(c) 15k
(d) 16k
Answer : C

Question. While computing mean of grouped data, we assume that the frequencies are
(a) evenly distributed over all the class
(b) centered at the class marks of the class
(c) centered the upper limits of the class
(d) centered the lower limits of the class
Answer : B

Question. If the mean of frequency distribution is 7.5 and Σfi xi = 120 + 3k, Σfi = 30, then k is equal to:
(a) 40
(b) 35
(c) 50
(d) 45
Answer : B

Question. The wickets taken by a bowler in 10 cricket matches are as follows 2, 6, 4, 5, 0, 2, 1, 3, 2, 3. Find the mode of the data.
(a) 2
(b) 4
(c) 3
(d) 1
Answer : A

 

Assertion and Reason Questions

DIRECTION: In the following questions (Q16-20), a statement of assertion (A) is followed by a statement of reason (R). Mark the correct choice as:
(a) if both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).
(b) if both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A).
(c) if Assertion (A) is true but reason (R) is false.
(d) if Assertion (A) is false but reason (R) is true.

Question. Statement A (Assertion): The mode of the call received on 7 consecutive day 11,13,13,17,19,23,25 is 13.
Statement R (Reason): Mode is the value that appears most frequent;
Answer : A

Question. Statement A (Assertion): If the median of the given data 26, 29, 42, 53, x, x + 2, 70, 75, 82, 93, is 65 then the value of x is 64.
Statement R(Reason): When the number of observations (n) is odd the median is the value of the (n+1/2) th observation.
Answer : A

Question. Statement A (Assertion) If mean & median of an asymmetrical distribution are 58 & 61 respectively, then Mode =67.
Statement R(Reason): For an asymmetrical distribution Mode =3 Median −2 Mean.
Answer : A

Question. Statement A (Assertion): The runs scored by a batsman in 5 ODIs are 31, 97,112, 63, and 12. The standard deviation is 25.79.
Statement R(Reason) : mean = total sum of number in data sets. / Total number in data sets.
Answer : B

Question. Statement A (Assertion)Median of 51, 70, 65, 82, 60, 68, 62, 95, 55, 64, 58, 75, 80, 85, and 90 is 68.
Statement R(Reason): When n observations are arranged in an ascending order and n is odd, then median=value of 1/2(n+1) th observation.
Answer : A

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VBQs for Chapter 14 Statistics Class 10 Mathematics

We hope students liked the above VBQs for Chapter 14 Statistics designed as per the latest syllabus for Class 10 Mathematics released by CBSE. Students of Class 10 should download the Value Based Questions and Answers in Pdf format and practice the questions and solutions given in above Class 10 Mathematics VBQs Questions on daily basis. All latest VBQs with answers have been developed for Mathematics by referring to the most important and regularly asked topics which the students should learn and practice to get better score in school tests and examinations. Expert teachers of studiestoday have referred to NCERT book for Class 10 Mathematics to develop the Mathematics Class 10 VBQs. After solving the questions given in the VBQs which have been developed as per latest course books also refer to the NCERT solutions for Class 10 Mathematics designed by our teachers. We have also provided a lot of other VBQs for Class 10 Mathematics which you can use to further make yourself better in Mathematics.

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