CBSE Class 7 Mathematics Fractions And Decimals Worksheet Set E

Read and download free pdf of CBSE Class 7 Mathematics Fractions And Decimals Worksheet Set E. Students and teachers of Class 7 Mathematics can get free printable Worksheets for Class 7 Mathematics Chapter 2 Fractions and Decimals in PDF format prepared as per the latest syllabus and examination pattern in your schools. Class 7 students should practice questions and answers given here for Mathematics in Class 7 which will help them to improve your knowledge of all important chapters and its topics. Students should also download free pdf of Class 7 Mathematics Worksheets prepared by school teachers as per the latest NCERT, CBSE, KVS books and syllabus issued this academic year and solve important problems with solutions on daily basis to get more score in school exams and tests

Worksheet for Class 7 Mathematics Chapter 2 Fractions and Decimals

Class 7 Mathematics students should refer to the following printable worksheet in Pdf for Chapter 2 Fractions and Decimals in Class 7. This test paper with questions and answers for Class 7 will be very useful for exams and help you to score good marks

Class 7 Mathematics Worksheet for Chapter 2 Fractions and Decimals

 

CBSE Class 7 Maths Worksheet - Fractions and Decimals (4)

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CLASS – VII
SUBJECT – MATHS
TOPIC – FRACTION (DIVISION)

 

Question. Which of the following is a reducible fraction?
a) (105/112)
b) (104/121)
C) (77/72)
d) (46/63)

Answer : A

Question. [(3/10)+(8/15)] = ?
a) (11/10)
b) (11/15)
c) (5/6)
d) none of these

Answer : C

Question. Which of the following is a vulgar fraction?
a) (3/10)
b) (13/10)
c) (10/3)
d) none of these

Answer : C

Question. Which of the following statement is true?
a) (9/16) = (13/24)
b) (9/16) < (13/4)
c) (9/16) > (13/24)
d) none of these

Answer : A

Question. Which of the following is an improper fraction?
a) (7/10)
b) (7/9)
c) (9/7)
d) none of these

Answer : C

Question. [3(1/4)] – [2(1/3)] =?
a) [1(1/12)]
b) (1/12)
c) [1 (1/11)]
d) (11/12)

Answer : D

Question. (2/3), (4/6), (6/9), (8/12) are
a) Like fractions
b) irreducible fraction
c) equivalent fraction
d) None of these

Answer : A

Question. Reciprocal of [1(3/4)]
a) [1(4/3)]
b) [4(1/3)]
c) [3(1/4)]
d) none of these

Answer : D

Write down the reciprocal of :

Question. 7
Answer : Reciprocal of 7 is (1/7) [∵ ((7/1) × (1/7)) = 1]

Question. (1/12)
Answer : Reciprocal of (1/12) is (12/1) [∵ ((1/12) × (12/1)) = 1]
= 12

Question. (5/8)
Answer : Reciprocal of (5/8) is (8/5) [∵ ((5/8) × (8/5)) = 1]

Question. [12(3/5)]
Answer : Convert mixed fraction into improper fraction,
= (63/5)
Reciprocal of (63/5) is (5/63) [∵ ((63/5) × (5/63)) = 1]

Simplify :

Question. (4/7) ÷ (9/14)
Answer : We have,
= (4/7) ÷ (9/14)
= (4/7) × (14/9)
(Because reciprocal of (9/14) is (14/9)
= (4 × 14) / (7 × 9)
= (4 × 2) / (1×9)
= (8/9)

Question. (7/10) ÷ (3/5)
Answer : We have,
= (7/10) ÷ (3/5)
= (7/10) × (5/3)
(Because reciprocal of (3/5) is (5/3)
= (7 × 5) / (10 × 3)
= (7 × 1) / (2 × 3)
= (7/6)
= [1(1/6)]

Divide:

Question. (11/24) by (7/8)
Answer : The above question can be written as,
= (11/24) ÷ (7/8)
We have,
= (11/24) × (8/7)
(Because reciprocal of (7/8) is (8/7)
= (11 × 8) / (24 × 7)
= (11 × 1) / (3 × 9)
= (11/21)

Question. [6(7/8)] by (11/16)
Answer : The above question can be written as,
= [6(7/8)] ÷ (11/16)
Convert mixed fraction into improper fraction,
= [6(7/8)] = (55/8)
We have,
= (55/8) × (16/11)
(Because reciprocal of (11/16) is (16/11)
= (55 × 16) / (8 × 11)
= (5 × 2) / (1 × 1)
= 10

Short Answer Type Questions :

Question. By selling oranges at the rate of ₹ [6(3/4)] per orange, a man gets ₹ 378. How many oranges does he sell?
Answer : From the question,
Cost for 1 orange = ₹ [6(3/4)] = (27/4)
Man gets = ₹ 378
Then we have,
= (378/1) ÷ (27/4)
= (378/1) × (4/27)
(Because reciprocal of (27/4) is (4/27)
= (378 × 4) / (1 × 27)
= (42×4) / (1×3)
= (14×4) / (1×1)
= 56
Hence, the man sold 56 orange.

Question. A rope of length [13(1/2)] m has been divided into 9 pieces of the same length. What is the length of each piece?
Answer : From the question,
Rope length = [13(1/2)] m = (27/2)
Number of equal pieces divided into = 9
Then we have,
= (27/2) ÷ (9/1)
= (27/2) × (1/9)
(Because reciprocal of (9/1) is (1/9)
= (27 × 1) / (2 × 9)
= (3×1) / (2×1)
= (3 / 2)
= [1(1/2)] m
Hence, the length of 9 pieces of rope is [1(1/2)] m

Question. Vikas can cover a distance of [20(2/3)] km in [7(3/4)] hours on foot. How many km per hour does he walk?
Answer : From the question,
Distance covered by vikas in [7(3/4)] hours on foot = [20(2/3)] km = (62/3)
Distance covered by vikas in 1 hour = (62/3) ÷ (31/4)
Then we have,
= (62/3) × (4/31)
(Because reciprocal of (31/4) is (4/31)
= (62 × 4) / (3 × 31)
= (2×4) / (3×1)
= (8) / (3)
= [2(2/3) km
Hence, Distance covered by vikas in 1 hour is [2(2/3) km

Question. 18 boxes of nails weigh equally and their total weight is [49(1/2)] kg. How much does each box weigh?
Answer : From the question,
Total weight of boxes= [49(1/2)] kg = (99/2)
Number of boxes = 18
Then we have,
= (99/2) ÷ (18/1)
= (99/2) × (1/18)
(Because reciprocal of (18/1) is (1/18)
= (99 × 1) / (2 × 18)
= (11×1) / (2×2)
= (11 / 4)
= [2(3/4)] kg
Hence, the weight of each box is [2(3/4)] kg

Question. Mangos are sold at ₹ [43(1/2)] per kg. What is the weight of mangoes available for ₹ [326(1/4)]?
Answer : From the question,
Mangos are sold at = ₹ [43(1/2)]+ = (87/2)
The weight of mangos available for = ₹ [26(1/4)] = (1305/4)
Then we have,
= (1305/4) ÷ (87/2)
= (1305/4) × (2/87)
(Because reciprocal of (87/2) is (2/87)
= (1305 × 2) / (4 × 87)
= (435×1) / (2×29)
= [7(1/2)] kg
Hence, the weight of mangos available for (1305/4) is [7(1/2)] kg 

Please click the below link to access CBSE Class 7 Maths Worksheet - Fractions and Decimals (4)

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