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Worksheet for Class 7 Mathematics Chapter 13 Exponents and Powers
Class 7 Mathematics students should refer to the following printable worksheet in Pdf for Chapter 13 Exponents and Powers in Class 7. This test paper with questions and answers for Class 7 will be very useful for exams and help you to score good marks
Class 7 Mathematics Worksheet for Chapter 13 Exponents and Powers
Question. Evaluate: (16/81)3/4
(A) 9/2
(B) 2/9
(C) 8/27
(D) 27/8
Answer : C
Question. What is the value of (512)-2/9?
(A) 1/2
(B) 2
(C) 4
(D) 1/4
Answer : D
Question. Simplify (32)-2/5 + (125)-2/3.
(A) 4/25
(B) 25/4
(C) 2/5
(D) 5/2
Answer : B
Question. If xY = yx, find the value of (x/y)x/y
(A) Xx/Y
(B) Xx/Y - 1
(C) Xy/x
(D) Xy/x - 1
Answer : B
Question. Evaluate (5)0.25 X (125)0.25/( 256)010 x (256)0.15 .
(A) √5/2
(B) 5/4
(C) 25/2
(D) 25/16
Answer : B
Question. What is the value of (67.542)2 - (32.458)2 / 75.458 - 40.374 ?.
(A) 1
(B) 10
(C) 100
(D) -10
Answer : C
Question. Which of the following values are equal?
I. 14 II. 4°
Ill. 04 IV. 41
(A) I and II
(B) II and Ill
(C) I and Ill
(D) I and IV
Answer : A
Question. Find the sum of the powers of the prime factors in 108 x 192.
(A) 5
(B) 7
(C) 8
(D) 12
Answer : D
Question. What is the value of (3°- 4°) X 5-3?
(A) 25
(B) 0
(C) -25
(D) -125
Answer : B
Question. What is the solution of 33x-5 = 1/9X ?
(A) 5/2
(B) 5
(C) 1
(D) 7/3
Answer : C
Question. Find the value of [(- 3)( -2)](-3)
(A) 729
(B) 32
(C) 64
(D) -729
Answer : A
Question. Compute (64)-1/6 x (216)-1/3 x (81)1/4 / (512)-1/3 x (16)1/4 x (9)-1/2
(A) 3
(B) 6
(C) 1
(D) -6
Answer : A
Question. Find the value of 33√2 X 73√6 X 53√18.
(A) 545
(B) 500
(C) 630
(D) 360
Answer : C
Question. Find the value of (-3)0 - (- 3)3 - (- 3)-1 +(-3)4 -(-3)-2.
(A) 109(2/9)
(B) 102(2/9)
(C) 109
(D) 110
Answer : A
Question. Evaluate
(A) 3(173/440)
(B) 3(17/44)
(C) 3(137/322)
(D) 3(21/440)
Answer : A
Question. What is the simplified form of
Answer : B
Question. If 3n = 729, find the value of 33n + 1.
(A) 321
(B) 310
(C) 319
(D) 315
Answer : C
Question. If 27x + 1 = 9x + 3 = 3Y, find the respective values of 'x' and y
(A) 3 and 12
(B) 12 and 3
(C) 6 and 6
(D) 4 and 9
Answer : A
Question. Find (0.000064) 514 x (0.04)514.
(A) 210.1010
(B) 210.10-10
(C) 2-10.1010
(D) 2-10 10-10
Answer : B
Question. Find the value of 1/1+x +1/1+xm
(A) 0
(B) xm
(C) 1
(D) x-m
Answer : C
Question. Give the simplified form of 3a 4a-2 25a+1 / 9a-12a+15a-2
(A) 3a-2 . 2a-5 . 5a+4
(B) 2a-s . 3a+2 . 5a+4
(C) 2a+5 . 3-a+2. 5a+4
(D) 2a-5 . 3-a+2 . 5a+4
Answer : B
Question. Which is greater of 212 and 38?
(A) 38
(B) 212
(C) Both are equal.
(D) Cannot be compared.
Answer : A
Question. What is the simplified form of (Xa+b)3 . (Xb+c)3 . (Xc+a)3/(Xa . Xb . Xc) ?
(A) 0
(B) 1
(C) Xa+b+c
(D) X
Answer : B
Question. By what number should we multiply 4-3 so that the product may be equal to 64?
(A) 45
(B) 212
(C) 26
(D) 1
Answer : B
Question. What is the number to be multiplied by (-7)-1 so as to get 10-1 as the product?
(A) -7/10
(B) 7/10
(C) 9/10
(D) -3/10
Answer : A
Question. What is the value of (6-1- 8-1) + (2-1- 3-1)-1?
(A) 25
(B) 30
(C) 35
(D) 40
Answer : B
Question. If (25)x = (125)Y, find X : y.
(A) 1 : 1
(B) 2 : 3
(C) 3 : 2
(D) 1 : 3
Answer : C
Question. What is the standard form of 6020000000000000?
(A) 6.02 X 1015
(B) 6.02 X 1013
(C) 602 X 1013
(D) 602 X 10-15
Answer : A
Question. What is the usual form of 1.0001 x 1 09?
(A) 100010000
(B) 1000100000
(C) 10001000000000
(D) 10001000000
Answer : B
Question. The size of a plant cell is 0.0000127 5 m .
Express this size in standard form.
(A) 1.25 X 108 m
(B) 1.275 x 105 m
(C) 1.275 x 10-8 m
(D) 1.275 x 10-5 m
Answer : D
Question. Evaluate {(3/4)-1 (1/4)-1}-1
(A) 3/16
(B) -3/8
(C) 16/3
(D) -8/3
Answer : B
Question. A box has 5 books, each 20 mm thick and 5 cards each 0.016 mm thick. What is the total thickness?
(A) 1.0008 x 104 mm
(B) 1.008 x 103 mm
(C) 1.0008 x 102 mm
(D) 1.0008 x 105 mm
Answer : C
Question. The size of a red blood cell is 0.000007 m.
The size of a plant cell is 0.0000127 5 m.
Compare them.
(A) 2
(B) 4
(C) 5
(D) -5
Answer : A
Question. By what number should (-8)-1 be divided to get 10-1?
(A) 4/5
(B) -5/4
(C) -4/5
(D) 5/4
Answer : B
Mark tick against the correct answer in each of the following:
1. (6-1– 8-1)-1 =?
(a) (-1/2) (b)-2 (c) (1/24) (d) 24
Solution:- (D) 24
We know that, = (6)-1= (1/6)1 … [∵ (a/b)-n
= (b/a) n] = (8)-1
= (1/8)1 … [∵ (a/b)-n
= (b/a) n] Now subtract,
= {(1/6) – (1/8)}-1
= {(4-3)/24}-1 … [LCM of 6 and 8 is 24]
= {1/24}-1
= {24/1} = 24
2. (5-1 × 3 -1)-1
(a)(1/15) (b)(-1/15) (c) 15 (d)-15
Solution:- (c)15
We know that,
= (5)-1= (1 /5)1 … [∵ (a/b)-n
= (b/a) n] = (3)-1
= (1/3)1 … [∵ (a/b)-n
= (b/a) n] Now multiply,
= {(1/5) × (1/3)}-1
= {(1×1)/ (5×3)}-1
= {1/15}-1
= {15/1}
= 15
3. (2-1 – 4-1)2 (a) 4 (b)-4 (c) (1/16) (d) (-1/16)
Solution:- (c) (1/16)
We know that, = (2)-1
= (1/2)1 … [∵ (a/b)-n
= (b/a) n]
= (4)-1
= (1/4)1 … [∵ (a/b)-n
= (b/a) n]
Now subtract,
= {(1/2) – (1/4)} 2
= {(2-1)/4}2 … [LCM of 2 and 4 is 4]
= {1/4}2
= {12/42}
= {1/16}
4. (1/2)-2 + (1/3)-2 + (1/4)-2 =?
(a)(61/144) (b) 29 (c) (144/61) (d) none of these
Solution:- (b) 29
We know that,
= (1/2)-2= (2/1)2 … [∵ (a/b)-n = (b/a) n]
= (1/3)-2
= (3/1)2 … [∵ (a/b)-n = (b/a) n]
= (1/4)-2 = (4/1)2 … [∵ (a/b)-n
= (b/a) n] Now add,
= (2)2+ (3)2+ (4)2
= 4 + 9 + 16
= 29
5.{6-1+(3/2)-1}-1
(a)(2/3) (b)(5/6) (c)(6/5) (d) None of these
Solution:- (c)(6/5)
We know that, = (6)-1
= (1/6) … [∵ (a/b)-n
= (b/a) n]
= (3/2)-1
= (2/3) … [∵ (a/b)-n
= (b/a) n] Now add,
= {(1/6) + (2/3)}-1
= {(1+4)/ 6}-1 … [LCM of 6 and 3 is 6]
= {5/6}-1
= {6/5}
6. (-1/2)-6 =?
(a)-64 (b) 64 (c) (1/64) (d) (-1/64)
Solution:- (b) 64
We know that,
= (-1/2)-6
= (-2/1)6 … [∵ (a/b)-n= (b/a) n]
= (-2)6 = 64
7. {(3/4)-1 – (1/4)-1}-1=?
(a)(3/8) (b)(-3/8) (c)(8/3) (d)(-8/3)
Solution:- (b)(-3/8) We know that,
= (3/4)-1
= (4/3)1 … [∵ (a/b)-n = (b/a) n]
= (1/4)-1
= (4/1)1 … [∵ (a/b)-n = (b/a) n]
Now subtract,
= {(4/3) – (4/1)} -1
= {(4-12)/3}-1 … [LCM of 3 and 1 is 3]
= {-8/3}-1 = {-3/8}
8. [{(-1/2)2}-2]-1=?
(a) (1/16) (b)16 (c)(-1/16) d)-16
Solution:- (a) [{(-1/2)2}-2]-1
= [{(-12/22)}-2]-1
= [{1/4}-2]-1
= [{4} 2]-1
= [16]-1
= [1/16]
9. (5/6)0 =?
(a) 5/6 (b) 0 (c)1 (d)none of these
Solution:- (c) (5/6)0
=1 By definition,
we have a0= 1 for every integer.
10. (2/3)-5=?
(a)(32/243) (b)(243/32) (c)(-32/243) (d)(-243/32)
Solution:- (b) (2/3)-5
= (3/2)5
= (35/25)
= (243/32)
Please click the below link to access CBSE Class 7 Maths Worksheet - Exponents & Powers (3)
CBSE Class 7 Mathematics Integers Worksheet Set A |
CBSE Class 7 Mathematics Integers Worksheet Set D |
CBSE Class 7 Mathematics Integers Worksheet Set G |
CBSE Class 7 Mathematics Practical Geometry Worksheet |
CBSE Class 7 Mathematics Symmetry Worksheet Set A |
CBSE Class 7 Mathematics Symmetry Worksheet Set B |
Worksheet for CBSE Mathematics Class 7 Chapter 13 Exponents and Powers
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