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Worksheet for Class 10 Mathematics Chapter 5 Arithmetic Progression
Class 10 Mathematics students should refer to the following printable worksheet in Pdf for Chapter 5 Arithmetic Progression in Class 10. This test paper with questions and answers for Class 10 will be very useful for exams and help you to score good marks
Class 10 Mathematics Worksheet for Chapter 5 Arithmetic Progression
Arithmetic Progression MCQ Questions with Answers Class 10
Answer : 3
Question. In an AP, if d = – 4, n = 7, an = 4, then a is
(a) 6
(b) 7
(c) 20
(d) 28
Answer : D
Question. The nth term of the AP: a, 3a, 5a, ... is
(a) na
(b) (2n – 1)a
(c) (2n + 1)a
(d) 2na
Answer : B
Question. The first term of an AP is p and the common difference is q, then its 10th term is
(a) q + 9p
(b) p – 9q
(c) p + 9q
(d) 2p + 9p
Answer : C
Question. If 4/5, a, 2 are three consecutive terms of an AP, then the value of a is
(a) 5/2
(b) 2/7
(c) 5/7
(d) 7/5
Answer : A
Answer the following:
Question. Write first four terms of the AP, whose first term and the common difference are given as follows: a = 10, d = 10
Answer : 10, 20, 30, 40
(2) Find the 10th term of the AP: 2, 7, 12, ...
Answer : 47
Question. In the given AP, find the missing terms: ......., 13, ......., 3.
Answer : 18, 8
Question. Find the 6th term from the end of the AP: 17, 14, 11, ..., –40.
Answer : –25
Question. Which term of the AP: 21, 18, 15, ... is zero?
Answer : 8
Question. Write the next term of the AP: √8, √18, √32 , ...........
Answer : √50 or 5√2
Question. Find a, b, and c such that the numbers a, 7, b, 23, c are in AP.
Answer : a = –1, b = 15, c = 31
Question. Find the 9th term from the end (towards the first term) of the AP: 5, 9, 13, ..., 185.
Answer : Reversing the given AP, we get
185, 181, 174, ..., 9, 5
Ninth term a9 = a + (9 – 1)d
= 185 + 8 × (– 4)
= 185 – 32
= 153
Question. For what value of k will k + 9, 2k – 1 and 2k + 7 are the consecutive terms of an AP?
Answer : Given that k + 9, 2k – 1 and 2k + 7 are in AP
Then,
(2k – 1) – (k + 9) = (2k + 7) – (2k – 1)
⇒ k – 10 = 8
⇒ k = 18
Question. For what value of k will the consecutive terms 2k + 1, 3k + 3 and 5k – 1 form an AP?
Answer : Given that 2k + 1, 3k + 3 and 5k – 1 are in AP.
So, (3k + 3) – (2k + 1) = (5k – 1) – (3k + 3)
⇒ k + 2 = 2k – 4
⇒ 2k – k = 2 + 4
⇒ k = 6
Question. Find the eleventh term from the last term of the AP: 27, 23, 19, ..., –65.
Answer : a11 = –25
Question. If the first three terms of an AP are b, c and 2b, then find the ratio of b and c.
Answer : b, c and 2b are in AP
⇒ c = 3b/2
∴ b : c = 2 : 3
Question. Find the value of x so that –6, x, 8 are in AP.
Answer : 1
Question. Find the 11th term of the AP: –27, –22, –17, –12, ... .
Answer : 23
Question. The nth term of an AP is (7 – 4n), then what is its common difference?
Answer : an = 7 – 4n
⇒ a1 = 7 – 4 × 1 = 3
⇒ a2 = 7 – 4 × 2 = 7 – 8 = –1
a3 = 7 – 4 × 3 = 7 – 12 = –5
Now, a2 – a1 = –1 – 3 = –4
a3 – a2 = –5 – (–1)
= –5 + 1 = –4
So, the common difference of AP is –4.
Question. Find the common difference of the AP whose first term is 12 and fifth term is 0.
Answer : A5 = a1 + 4d = 0
12 + 4d = 0
d = –3
Assertion Reasoning Questions Arithmetic Progression
Directions:
(a) If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
(b) If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
(c) If Assertion is correct but Reason is incorrect.
(d) If Assertion is incorrect but Reason is correct.
Question. Assertion : If Sn is the sum of the first n terms of an A.P., then its nth term an is given by an = Sn – Sn – 1 .
Reason : The 10th term of the A.P. 5, 8, 11, 14, ………………. is 35.
Answer : C
Question. Assertion: arithmetic mean between 5 and 90 is 47.5
Reason: arithmetic mean between two given number a,b is (a+b)/2
Answer : A
Question. Assertion: the value of n, if a = 10, d = 5, an = 95.
Reason: the formula of general term an is an= a+(n-1)d.
Answer : A
Question. Assertion: The constant difference between any two terms of an AP is commonly known as common difference
Reason: the common difference of 2,4,6,8 this A.P. sequence is 2
Answer : A
Question. Assertion : Let the positive numbers a, b, c be in A.P., then 1/bc, 1/ac, 1/ab are also in A.P.
Reason : If each term of an A.P. is divided by abc, then the resulting sequence is also in A.P.
Answer : A
CASE STUDY QUESTIONS
Q1. Your elder brother wants to buy a car and plans to take loan from a bank for his car. He repays his total loan of Rs 1,18,000 by paying every month starting with the first instalment of Rs 1000. If he increases the instalment by Rs 100 every month , answer the following:
Question. Find the amount paid by him in 30th installment.
Answer : 3900
Question. Find the amount paid by him in the 30 installments.
Answer : 73500
Question. If total instalments are 40 then amount paid in the last installment?
Answer : 490
Q2. In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
Question. Find terms of AP formed in above situation
Answer : 10, 16 , 22……..
Question. What is the total distance the competitor has to run?
Answer : Total distance 370
Question. Find distance cover after 4 potato drop In the bucket?
Answer : 152 m
Very Short Answer Type Questions
Question. Check whether – 150 is a term of the AP : 11, 8, 5, 2 . . .
Answer : No
Question. A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200 for the first day, ₹ 250 for the second day, ₹ 300 for the third day, etc., the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days?
Answer : Rs 27750
Question. Find the 31st term of an AP whose 11th term is 38 and the 16th term is 73.
Answer : 178
Question. Find the 20th term from the last term of the AP : 3, 8, 13, . . ., 253
Answer : 20th term from the last term is 158
Question. In a flower bed, there are 23 rose plants in the first row, 21 in the second, 19 in the third, and so on.
There are 5 rose plants in the last row. How many rows are there in the flower bed?
Answer : 10 rows
Question. For the AP : 1/3, 5/3, 9/3, 13/3,....... write the first term a and the common difference d.
Answer : a = 1/3, d= 4/3
Question. The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Answer : 1
Question. 200 logs are stacked in following manner . 20 logs in the bottom row , 19 in the next row 18 in the row next to it and so on . how many rows are the 200 logs placed and how many logs are in the top row ?
Answer : total rows 16 and 5 logs placed in top row
Question. Ramkali saves Rs 5 in the first week, of a year and increased her weekly savings by Rs 1.75. If in the nth week her weekly savings became Rs 20.75, find n.
Answer : 10
Question. The digits of a positive number of three digits are in A.P. and their sum is 15. The number obtained by reversing the digits is 594 less than the original number. Find the number.
Answer : 852
Question. The sum of the third and seventh terms of an A.P. is 40 and the sum of its sixth and 14th terms is 70. Find the sum of the first ten terms of the A.P.
Answer : 215
Question. If sum of first n terms of an AP is 4n – n2 What is the first term What is the sum first two terms ?
Find 10th term , 3rd term and nth term .
Answer : S1 = 3 S2 = 4 a10= -15 a3 = -1 and nth term = 5-2n
Please click the link below to download CBSE Class 10 Mathematics Arithmetic Progression Worksheet Set B
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Worksheet for CBSE Mathematics Class 10 Chapter 5 Arithmetic Progression
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