Read and download free pdf of CBSE Class 9 Science Force and Laws of Motion Worksheet Set C. Download printable Science Class 9 Worksheets in pdf format, CBSE Class 9 Science Chapter 9 Force and Laws of Motion Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Science Class 9 Assignments and practice them daily to get better marks in tests and exams for Class 9. Free chapter wise worksheets with answers have been designed by Class 9 teachers as per latest examination pattern
Chapter 9 Force and Laws of Motion Science Worksheet for Class 9
Class 9 Science students should refer to the following printable worksheet in Pdf in Class 9. This test paper with questions and solutions for Class 9 Science will be very useful for tests and exams and help you to score better marks
Class 9 Science Chapter 9 Force and Laws of Motion Worksheet Pdf
Question. What can you say about the motion of an object whose distance - time graph is a straight line parallel to the time axis?
Answer : If distance time graph is a straight line parallel to the time axis, the body is at rest.
Question. What is the quantity which is measured by the area occupied below the velocity -time graph?
Answer : The area below velocity-time graph gives the distance covered by the object.
Question. What does the odometer of an automobile measure?
Answer : The odometer of an automobile measures the distance covered by an automobile.
Question. A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Answer :
Given, Side of the square field= 10m
Therefore, perimeter = 10 m x 4 = 40 m
Farmer moves along the boundary in 40s.
Displacement after 2 m 20 s = 2 x 60 s + 20 s = 140 s =?
Since in 40 s farmer moves 40 m
Therefore, in 1s distance covered by farmer = 40 / 40 m = 1m
Therefore, in 140s distance covered by farmer = 1 × 140 m = 140 mNow, number of rotation to cover 140 along the boundary= Total Distance /
Perimeter
= 140 m / 40 m = 3.5 round
Thus, after 3.5 round farmer will at point C of the field.
Thus, after 2 min 20 seconds the displacement of farmer will be equal to 14.14 m north east from intial position.
Question. Distinguish between speed and velocity.
Answer :
| Speed | Velocity |
| Speed is the distance travelled by an object in a given interval of time. | Velocity is the displacement of an object in a given interval of time. |
Speed = distance / time | Velocity = displacement / time |
| Speed is scalar quantity i.e. it has only magnitude. | Velocity is vector quantity i.e. it has both magnitude as well as direction. |
Question. During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, that is, 3 × 108 m s−1.
Answer :
Speed= 3 × 108 m s−1
Time= 5 min = 5 x 60 = 300 secs. Distance= Speed x Time
Distance= 3 × 108 m s−1 x 300 secs. = 9 x 1010 m
Question. A bus decreases its speed from 80 km h−1 to 60 km h−1 in 5 s. Find the acceleration of the bus.
Answer :
Question. State which of the following situations are possible and give an example for each of these:
(a) an object with a constant acceleration but with zero velocity.
(b) an object moving in a certain direction with an acceleration in the perpendicular direction.
Answer :
(a) Possible
When a ball is thrown up at maximum height, it has zero velocity, although it will have constant acceleration due to gravity, which is equal to 9.8 m/s2.
(b) Possible
When a car is moving in a circular track, its acceleration is perpendicular to its direction.
Question. An artificial satellite is moving in a circular orbit of radius 42250 km.
Calculate its speed if it takes 24 hours to revolve around the earth.
Answer :
Radius of the circular orbit, r= 42250 km
Time taken to revolve around the earth, t= 24 h
Speed of a circular moving object, v= (2π r)/t
=[2× (22/7)×42250 × 1000] / (24 × 60 × 60)
=(2×22×42250×1000) / (7 ×24 × 60 × 60) m s-1
=3073.74 m s -1
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CBSE Class 9 Science Chapter 9 Force and Laws of Motion Worksheet
The above practice worksheet for Chapter 9 Force and Laws of Motion has been designed as per the current syllabus for Class 9 Science released by CBSE. Students studying in Class 9 can easily download in Pdf format and practice the questions and answers given in the above practice worksheet for Class 9 Science on a daily basis. All the latest practice worksheets with solutions have been developed for Science by referring to the most important and regularly asked topics that the students should learn and practice to get better scores in their examinations. Studiestoday is the best portal for Printable Worksheets for Class 9 Science students to get all the latest study material free of cost.
Worksheet for Science CBSE Class 9 Chapter 9 Force and Laws of Motion
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Chapter 9 Force and Laws of Motion worksheet Science CBSE Class 9
All practice paper sheet given above for Class 9 Science have been made as per the latest syllabus and books issued for the current academic year. The students of Class 9 can be assured that the answers have been also provided by our teachers for all test paper of Science so that you are able to solve the problems and then compare your answers with the solutions provided by us. We have also provided a lot of MCQ questions for Class 9 Science in the worksheet so that you can solve questions relating to all topics given in each chapter. All study material for Class 9 Science students have been given on studiestoday.
Chapter 9 Force and Laws of Motion CBSE Class 9 Science Worksheet
Regular printable worksheet practice helps to gain more practice in solving questions to obtain a more comprehensive understanding of Chapter 9 Force and Laws of Motion concepts. Practice worksheets play an important role in developing an understanding of Chapter 9 Force and Laws of Motion in CBSE Class 9. Students can download and save or print all the printable worksheets, assignments, and practice sheets of the above chapter in Class 9 Science in Pdf format from studiestoday. You can print or read them online on your computer or mobile or any other device. After solving these you should also refer to Class 9 Science MCQ Test for the same chapter.
Worksheet for CBSE Science Class 9 Chapter 9 Force and Laws of Motion
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