NCERT Solutions Class 5 Mathematics Chapter 6 Be my multiply have been provided below and is also available in Pdf for free download. The NCERT solutions for Class 5 Mathematics have been prepared as per the latest syllabus, NCERT books and examination pattern suggested in Class 5 by CBSE, NCERT and KVS. Questions given in NCERT book for Class 5 Mathematics are an important part of exams for Class 5 Mathematics and if answered properly can help you to get higher marks. Refer to more Chapter-wise answers for NCERT Class 5 Mathematics and also download more latest study material for all subjects. Chapter 6 Be my multiply is an important topic in Class 5, please refer to answers provided below to help you score better in exams
Chapter 6 Be my multiply Class 5 Mathematics NCERT Solutions
Class 5 Mathematics students should refer to the following NCERT questions with answers for Chapter 6 Be my multiply in Class 5. These NCERT Solutions with answers for Class 5 Mathematics will come in exams and help you to score good marks
Chapter 6 Be my multiply NCERT Solutions Class 5 Mathematics
1. The hungry cat is trying to catch Kunjan the mouse. Kunjan is now on the 14th step and it can jump 2 steps at a time. The cat is on the third step. She can jump 3 steps at a time. If the mouse reaches 28 it can hide in the hole. Find out whether the mouse can get away safely!
(a) The steps on which the mouse jumps.
(b) The steps on which the cat jumps.
(c) The steps on which both the cat and the mouse jump.
(d) Can the mouse get away?
Ans. (a)The steps on which the mouse jumps are 16, 18, 20, 22, 24, 26 and 28.
(b) The steps on which the cat jumps are 3,6,9, 12, 15, 18, 21, 24, 27.
(c) The steps on which both the cat and the mouse jump are 18 and 24.
(d) The mouse can get away safely as they do not come together at the steps 18 and 24.
2. If the cat starts from the 5th step and jumps five steps at a time and the mouse starts from the 8th step and jumps four steps at a time, can the mouse get away?
Ans. In this case: (a) The steps on which the mouse jumps are 8, 12, 16, 20, 24 and 28
(b) The steps on which the cat jumps are 5, 10, 15, 20 and 25.
(c) The step on which both of the cat and mouse jump is 20.
(d) Since their 4th jump is on step 20 together so the mouse will not get away safely.
3. Who is Monto waiting for?
Monto cat is waiting for somebody. Do you know for whom he is waiting?
There is a trick to find out.
Mark with a red dot all the numbers which can be divided by 2. Mark a yellow dot on the numbers which can be divided by 3 and a blue dot on the numbers which can be divided by 4. Which are the boxes which have dots of all three colours? What are the letters on top of those boxes? Write those letters below in order.
Ans. Let us mark the coloured dots are desired on the above number:
Red dot will appear on the numbers: 2, 4, 6,8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46,48, 50, 52, 54, 56, 58 and 60.
Yellow dot will appear on the numbers: 3,6, 9, 12, 15, 18, 21, 24, 27, 30,33, 36, 39, 42, 45, 48, 51, 54, 57 and 60.
Blue dot will appear on the numbers: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56 and 60.
All the three coloured dots will appear on the boxes: 122, 24, 36, 48 and 60.
The respective letters on the top of these boxes are: M, O, U, S and E.
Writing these letters in order: MOUSE.
4. To play this game, everyone stands in a circle. One player calls out ‘one’.
The next player says ‘two’ and so on. A player who has to call out 3 or a number which can be divided by 3 has to say ‘Meow’ instead of the number.
One who forgets to say ‘Meow’ is out of the game. The last player left is the winner.
(a) Which numbers did you replace with ‘Meow’?
Ans. The number which will be replaced with ‘Meow’ are:
3,6, 9, 12, 15, 18, 21, 24, 27, 30…
(b) Now, which numbers did you replace with ‘Meow’?
Ans. The numbers which will be replaced with ‘Meow’ are:
4, 8, 12, 16, 20, 24, 28, 32…
(c) Write any ten multiple of 5.
Ans. Ten multiple of 5 are: 5, 10, 15, 220, 25, 30, 35, 40, 45 and 50.
5. Tamarind seeds Sunita took some tamarind (imli) seeds. She made groups of five with them, and found that one seed was left over. She tried making groups of six and groups of four. Each time one seed was left over. What is the smallest number of seeds that Sunita had?
Ans. We know that the smallest number divisible by 5,6 and 4 is their smallest common multiple. Therefore, the required number be 1 more than this smaller common multiple.
The smallest common multiple of 5,6 and 4 =60
Therefore, the required number =60+1=61
Hence, the smallest number of seeds Sunita had 61.
6. There are 18 bangles on the rod. Meena trying to group them. She can put them in groups of 2, 3,6, 9 and 18 – without any bangle being left.
(a) How many bangles will she have if she makes groups of 1 bangle each?
Now, complete the table, for different numbers of bangles. For each number see what different groups can be made.
Ans. Meena will have 18 groups of 1 bangle each. The complete table is on the given here:
7. Complete the multiplication chart given here:
Ans.
8. Look at the green boxes in the chart. These show how we can get 12 by multiplying different numbers. 12 = 4 × 3, so 12 is a multiple of both 4 and 3. 12 is also a multiple of 6 and 2, as well
(b) What are the factors of 36? as 12 and 1. We say 1, 2, 3, 4, 6, 12 are factors of 12.
(a) What are the factors of 10?
Can you do this from the chart?
(c) Find out all the factors of 36 from the multiplication chart.
(d) What is the biggest number for which you can find the factors from this chart?
(e) What can you do for number bigger than chart?
Ans. (a) The factors of 10 are 1, 2, 5, 10.
Yes, we can find these factors from the above chart.
(b) The factors of 36 are 1, 2,3,4, 6, 9, 12, 18, 36.
(c) From the multiplication chart, we find that
36=3 12, 36=4 x 9, 36=6 6, 36=9 x 4
∴ 3,4,6, 9, 12 are factors of 36 as found from the above chart.
(d) The biggest number for which we can find the factors from this chart is 144.
(e) We can find the factors of bigger number just by reducing to smaller numbers by division and then using and then using the above chart.
9. There is a garden in Anu’s house. In the middle of the garden there is a path. They decided to tile the path using tiles of length 2 feet, 3 feet and 5 feet. The mason tiled the first row with 2 feet tiles, the second row with 3 feet tiles and the third row with 5 feet tiles. The mason has not cut any of the tiles.
Then what is the shortest length of the path?
Ans. The shortest length of the path is the smallest common multiple of 2,3 and 5.
The shortest length of the path=30 feet
10. Manoj has made a new house. He wants to lay tiles on the floor. The size of the room is 9 feet x 12 feet. In the market, there are three kinds of square tiles: 1 foot × 1 foot, 2 feet x 2 feet and 3 feet x 3 feet. Which size of tile should he buy for his room, so that he can lay it without cutting?
Ans. Since, the tile of size 2 feet x 2 feet cannot be laid down on the width side of the room’s without cutting so this type of the tile should not be purchased. He can buy tiles of size 1 foot x 1 foot or 3 feet x 3 feet as these can be laid down without cutting on the floor.
11. Rani, Geetha and Naseema live near each other. The distance from their houses to the road is 90 feet. They decided to tile the path to the road. They all bought tiles of different designs and length. Rani bought the shortest tile,
Geetha bought the middle sized one and Naseema bought the longest one. If they could tile the path without cutting any of the tiles, what is the size of the tiles each has bought? Suggest 3 different solutions. Explain how you get this answer.
Ans. Let us write down the factors of 90
90=1x90, 90=2x45, 90=3x30
90=5x18, 90=6x15, 90=9x10
Since, we have to lay down the tiles on the path of 90 feet without cutting so any of the size indicated by the factors will do.
Therefore, the possible solution to tile the path using tiles of length.
1 foot, 2 feet, 3 feet; 2 feet, 3 feet, 5 feet; 3feet, 5 feet, 6 feet etc.
Question. If 8 times a certain number is 32, and 6 times the same number is 24, how would you find 86 times that number?
(a) 320 + 24
(b) 32 + 24
(c) 32 x 24
(d) 320 + 240
Answer : A
Question. Ram has a total of 108 tapes and CD's in his collection. He has 3 times as many tapes as CD's. How many more tapes does he have than CD's?
(a) 72
(b) 54
(c) 36
(d) 27
Answer : B
Question. 40 students of a class are put into groups of 5 for an activity. Each GROUP needs a 2-metre long piece of rope.
What will be the total length of rope needed for the whole class?
(a) 10 metres
(b) 16 metres
(c) 42 metres
(d) 80 metres
Answer : B
Question. You start from 45 on this number line, and jump back 3 steps, 2 steps, 3 steps, 2 steps and so on. In how many jumps will you reach 0?
(a) 5
(b) 18
(c) 45
(d) 225
Answer : B
Question. 24 can be expressed as the product of two numbers in 4 different ways: 24 x 1, 12 x 2 , 8 x 3 and 4 x 6. In how many different ways can 42 be expressed as a product of two numbers?
(a) 3
(b) 4
(c) 5
(d) 6
Answer : B
Question. Abbas went for drama class every Thursday during his summer holidays which started on 15th April, Sunday and ended on 30th June.
How many drama classes did he go for?
(a) 15
(b) 11
(c) 10
(d) 6
Answer : B
Question. There were 48 students in a drawing class. The classroom had large tables, and 8 children sat at each table. The children on each table were given 3 crayon boxes to share. In all, how many crayon boxes were given out for sharing?
(a) 18
(b) 24
(c) 99
(d) 144
Answer : A
Question. Seema sees this poster in a shop:
If she buys 4 packs of Goodie biscuits, how much does she have to pay?
(a) Rs. 13
(b) Rs. 24
(c) Rs. 26
(d) Can't say
Answer : D
Question. Twice of a certain number is 58. Four times that number will be?
(a) 4 x 58
(b) 58+4
(c) 58 x 2
(d) 8 x 58
Answer : C
NCERT Solutions Class 5 Mathematics Chapter 1 The Fish Tale |
NCERT Solutions Class 5 Mathematics Chapter 2 Shapes and Angles |
NCERT Solutions Class 5 Mathematics Chapter 3 How Many Squares |
NCERT Solutions Class 5 Mathematics Chapter 4 Parts and Wholes |
NCERT Solutions Class 5 Mathematics Chapter 5 Does it look the same |
NCERT Solutions Class 5 Mathematics Chapter 6 Be my multiply |
NCERT Solutions Class 5 Mathematics Chapter 7 Can you see the pattern |
NCERT Solutions Class 5 Mathematics Chapter 8 Mapping Your Way |
NCERT Solutions Class 5 Mathematics Chapter 9 Boxes And Sketches |
NCERT Solutions Class 5 Mathematics Chapter 10 Tenths And Hundredths |
NCERT Solutions Class 5 Mathematics Chapter 11 Area and its Boundary |
NCERT Solutions Class 5 Mathematics Chapter 12 Smart Charts |
NCERT Solutions Class 5 Mathematics Chapter 13 Ways of Multiply and Divide |
NCERT Solutions Class 5 Mathematics Chapter 14 How Big How Heavy |
NCERT Solutions Class 5 Mathematics Chapter 6 Be my multiply
The above provided NCERT Solutions Class 5 Mathematics Chapter 6 Be my multiply is available on our website www.studiestoday.com for free download in Pdf. You can read the solutions to all questions given in your Class 5 Mathematics textbook online or you can easily download them in pdf. The answers to each question in Chapter 6 Be my multiply of Mathematics Class 5 has been designed based on the latest syllabus released for the current year. We have also provided detailed explanations for all difficult topics in Chapter 6 Be my multiply Class 5 chapter of Mathematics so that it can be easier for students to understand all answers. These solutions of Chapter 6 Be my multiply NCERT Questions given in your textbook for Class 5 Mathematics have been designed to help students understand the difficult topics of Mathematics in an easy manner. These will also help to build a strong foundation in the Mathematics. There is a combination of theoretical and practical questions relating to all chapters in Mathematics to check the overall learning of the students of Class 5.
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