Refer to BITSAT Chemistry Organic Chemistry Some Basic Principles and Techniques MCQs Set A provided below available for download in Pdf. The MCQ Questions for Full Syllabus Chemistry with answers are aligned as per the latest syllabus and exam pattern suggested by BITSAT, NCERT and KVS. Organic Chemistry Some Basic Principles and Techniques Full Syllabus MCQ are an important part of exams for Full Syllabus Chemistry and if practiced properly can help you to improve your understanding and get higher marks. Refer to more Chapter-wise MCQs for BITSAT Full Syllabus Chemistry and also download more latest study material for all subjects
MCQ for Full Syllabus Chemistry Organic Chemistry Some Basic Principles and Techniques
Full Syllabus Chemistry students should refer to the following multiple-choice questions with answers for Organic Chemistry Some Basic Principles and Techniques in Full Syllabus.
Organic Chemistry Some Basic Principles and Techniques MCQ Questions Full Syllabus Chemistry with Answers
Question: A compound of molecular formula of C7H16 shows optical isomerism, compound will be
a) 2, 3-Dimethylpentane
b) 2,2-Dimethylbutane
c) 3-Methylhexane
d) None of the above
Answer: 2, 3-Dimethylpentane
Question: Which of the following does not contain Plane of symmetry?
a) Trans-1,3 dichloro cyclohexane
b) Trans-1,2 dichloro cyclohexane
c) Cis-1,2 dichloro cyclohexane
d) Trans-1,3 cyclopentane
Answer: Cis-1,2 dichloro cyclohexane
Question: The correct statement about the compounds A, B, and C
(A)
(B)
(C)
a) A and B are identical
b) A and B are diastereomers
c) A and C are enantiomers
d) A and B are enantiomers
Answer: A and B are enantiomers
Question: Which of the following compounds has all the four types (1°, 2°, 3° and 4°) of carbon atoms?
a) 2, 3, 4-Trimethylpentane
b) neo-Pentane
c) 2, 2, 4-Trimethylpentane
d) None of the three
Answer: 2, 2, 4-Trimethylpentane
Question: Which of the following has two stereoisomers?
a) None of these
b) Only I
c) Only III
d) I and III
Answer: Only I
Question: The anthracene is purified by
a) Crystallisation
b) Filtration
c) Distillation
d) Sublimation
Answer: Sublimation
Question: Which of the following compounds has wrong IUPAC name?
a)
b)
c)
d)
Answer:
Question: Consider the following carbocations
The correct sequence for the stability of these is
a) II < I < III < IV
b) II < III < I < IV
c) III < I < II < IV
d) IV < III < I < II
Answer: II < I < III < IV
Question: Arrangement of (CH3)3 C –, (CH3)2 CH –, CH3 CH2 – when attached to benzyl or an unsaturated group in increasing order of inductive effect is
a) (CH3)3C – < (CH3)2 CH – < CH3 CH2–
b) CH3CH2– < (CH3)2CH – < (CH3)3C –
c) (CH3)2CH – <(CH3)3C – < CH3CH2–
d) (CH3)3C – < CH3CH2 – < (CH3)2CH –
Answer: CH3CH2– < (CH3)2CH – < (CH3)3C –
Question: The most stable carbanion among the following is
a)
b)
c)
d)
Answer:
Question: Among the following four structures I to IV,
it is true that
a) Only I and II are chiral compounds
b) Only III is a chiral compound
c) Only II and IV are chiral compounds
d) All four are chiral compounds
Answer: Only I and II are chiral compounds
Question: The number of enantiomers of the compound
CH3CHBrCHBrCOOH is
a) 0
b) 1
c) 3
d) 4
Answer: 4
Question: he following two compounds are
are
a) Enantiomers
b) Diastereomers
c) Identical
d) Epimers
Answer: Diastereomers
Question: In paper chromatography
a) Mobile phase is liquid and stationary phase is solid
b) Mobile phase is solid and stationary phase is liquid
c) Both phases are liquids
d) Both phases are solids
Answer: Both phases are liquids
Question: In which case the will attack at the meta position
a) I, II, III
b) II, IV
c) II and III only
d) II only
Answer: I, II, III
Question: Which of the following compound is not chiral?
a) DCH2CH2CH2Cl
b) CH3CHDCH2Cl
c) CH3CHClCH2D
d) CH3CH2CHDCl
Answer: DCH2CH2CH2Cl
Question:
exhibit which type of isomerism?
a) Position
b) Functional
c) Demotropism
d) Position isomerism
Answer: Functional
Question: The correct nucleophilicity order is
a)
b)
c)
d)
Answer:
Question: In the anion HCOO– the two carbon-oxygen bonds are found to be of equal length. what is the reason for it ?
a) The C = O bond is weaker than the C — O bond
b) The anion HCOO– has two resonating structures
c) The anion is obtained by removal of a proton from the acid molecule
d) Electronic orbitals of carbon atom are hybridised
Answer: The anion HCOO– has two resonating structures
Question: The number of geometrical isomers of CH3CHCH – CH = CH – CHCHCl is
a) 2
b) 4
c) 6
d) 8
Answer: 8
MCQs for Organic Chemistry Some Basic Principles and Techniques Chemistry Full Syllabus
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