CBSE Class 6 Mathematics Integers Chapter Notes

Download CBSE Class 6 Mathematics Integers Chapter Notes in PDF format. All Revision notes for Class 6 Mathematics have been designed as per the latest syllabus and updated chapters given in your textbook for Mathematics in Class 6. Our teachers have designed these concept notes for the benefit of Class 6 students. You should use these chapter wise notes for revision on daily basis. These study notes can also be used for learning each chapter and its important and difficult topics or revision just before your exams to help you get better scores in upcoming examinations, You can also use Printable notes for Class 6 Mathematics for faster revision of difficult topics and get higher rank. After reading these notes also refer to MCQ questions for Class 6 Mathematics given on studiestoday

Revision Notes for Class 6 Mathematics Chapter 6 Integers

Class 6 Mathematics students should refer to the following concepts and notes for Chapter 6 Integers in Class 6. These exam notes for Class 6 Mathematics will be very useful for upcoming class tests and examinations and help you to score good marks

Chapter 6 Integers Notes Class 6 Mathematics

 

CBSE Class 6 English Practice Passages. Learning the important concepts is very important for every student to get better marks in examinations. The concepts should be clear which will help in faster learning. The attached concepts made as per NCERT and CBSE pattern will help the student to understand the chapter and score better marks in the examinations.

Integers

Positive numbers, 0 and negative numbers together called integers.

Example : –3, –2, 0, 4, 16

Integers on number line

class_6_maths_concept_023

Note i) 0 is greater than all negative integers but it is lesser than all positive integers.

ii) 1 is the smallest positive integer.

iii) –1 is the largest negative integer.

Operations on integers

We are going to learn the following operations on integers.

i) Addition ii) Subtraction iii) Multiplication and iv) Division

Addition of two integers

Rules to add two integers

Rule 1: If a and b are positive integers, then add a and b and put + sign to the result.
Rule 2: If a is positive integer and b is negative integer, and subtract the smaller one from bigger one and put the sign of bigger number to the result
Rule 3: If a is a negative integer and b is positive integer, then also subtract the smaller one from bigger one and put the sign of bigger number to the result.
Rule 4: If a and b are negative integers, then add ‘a’ and ‘b’ and put ‘–’ sign to the result.

Example 1: Find the value of 8 + 3

Solution: Both 8 and 3 are positive integers.
\ 8 + 3 = 11 (using rule 1)

Example 2: Find the value of 8 + (–13)

Solution: 8 is positive integer and –13 is negative integer. Also 13 > 8
\ Following rule 2, 8 + (–13) = – [13 – 8] = – 5

Example 3: Find the value of (–8) + 3
Solution: –8 is negative integer and 3 is positive integer by rule 3, (–8) + 3 = – (8 – 3) = –5

Example 4: Find the value of (–8) + (–3)

Solution: (–8) and (–3) are negative integers. By rule 4
(–8) + (–3) = –(8 + 3) = –11
Addition of three or more integers
Hint: This can be done by method of grouping. Group first two integers the next two integers and so on.

Example 5: Find the value of (–5) + (–6) + (+7)

Solution: (–5) + (–6) + 7 = {(–5) + (–6)} + 7 (Group first two integers)
= (– 11) + 7 {Using Rule 4}
= –4 {Using Rule 3}

Example 6: Find the value of (–5) + (–4) + (–3) + (–2) + (–1)

Solution: (–5) + (–4) + (–3) + (–2) + (–1)

= {(–5) + (–4)} + {(–3) + (–2)} + (–1) (Group first two and next two integers)

= {(–9) + (–5)} + (–1) (Use rule 4 and then group first two integers)

= (–14) + (–1) (Using rule 4)

= –15 (Using rule 4)

Example 7: Find the value of (–25) + (13) + (–49)

Solution: (–25) + (13) + (–49) = {(–25) + (13)} + (–49) (By grouping)

= (–12) + (–49) (Using rule 2)

= –61 (Use rule 4)

Example 8: Find the value of 1000 + (–999) + (–1)

Solution: 1000 + (–999) + (–1) = {1000 + (–999)} + (–1) (By grouping)

= 1 + (–1) (Using rule 2)

= 0 (Using rule 2)

Subtraction of two integers

Rules to subtract two integers.

Rule 1: If a and b are positive integers, then to get a – b, subtract the smaller number from bigger number and put the sign of bigger number to the result.
Rule 2: If a is positive integer and b is negative integer, then to obtain a – b, a and b and put + sign to the result
Rule 3: If a is negative integer and b is positive integer, then to obtain a – b, add a and b and put – sign to the result.
Rule 4: If a and b are negative integer, then to obtain a – b, subtract the smaller number from bigger number and put (i) ‘+’ sign if b is bigger. (ii) ‘–’ sign if a is bigger.

Example 9: Find the value of 8 – 3.

Solution: 8 – 3 = 5 (Using rule 1)

Example 10: Find the value of 8 – (13) 

Solution: 8 and 13 are positive integer and 13 > 8

∴ 8 – 13 = – (13 – 8) = – 5                                  (Use rule 1)

Example 11: Find the value of 8 – (–3)

Solution: 8 – (–3) = + (8 + 3) = + 11                    (Use rule 2)

Example 12: Find the value of (–8) – (3)

Solution: (–8) – (3) = –(8 + 3) = –11                   (Use rule 3)

Example 13: Find the value of (–8) – (–13)

Solution: (–8) – (– 13) = + (13 – 8) = 5                (Rule 4 : 13 – 8 = 5) (13 > 8)  (–8) – (–3) = + 5

Example 14: Find the value of (–8) – (–3)

Solution: (–8) – (–3) = – (8 – 3) = –5                    (Rule 4 : 8 – 3 = 5) (8 > 3)  (–8) – (–3) = – 5

Subtraction of two (or) more integers

Method : Grouping first two integers only.

Example 15: Find the value of (–5) – (6) – (7)

Solution: (–5) – (–6) – (7) = {(–5) – (–6)} – 7 (Grouping first two terms)

= 1 – 7                   (Using rule 4)

= –6                     (Using rule 2)

Example 16: Find the value of (–5) – (–4) – (–3) – (–2) – (–1)

Solution: (–5) – (–4) – (–3) – (–2) – (–1) = {(–5) – (–4)} – (–3) – (–2) – (–1) {Grouping first two}

= [(–1) – (–3)] – (–2) – (–1)                               {Using rule 4}

= [(+2) – (–2)] – (–1)                                      {Using rule 4}

= 4 – (–1)                                                       {Using rule 2}

= 5                                                             {Using rule 2}

Example 17: Find the value of 100 – 1 – 99

Solution: 100 – 1 – 99 = (100 –1) – 99 {Grouping first two}

= 99 – 99

= 0

Properties of addition and subtraction of integers

1. Closure property : If a and b are integers, then (i) a + b is also an integer (ii) a – b is also an integer.

Hence, closure property holds for both addition and subtraction of integers.

2. Associative Property : If a, b, and c are integers, then

i) a + (b + c) = (a + b) + c

ii) a – (b – c) (a – b) – c

Hence associative property holds for addition but not for subtraction.

3. Commutative property : If a and b are integers, then

i) a + b = b + a

ii) a – b b – a

Hence commutative property holds for addition but not for subtraction.

4. Inverse : If a is an integer, then

(i) a + (–a) = 0

(ii) a – a = 0

    ‘–a’ is called additive inverse of a (or) negative of ‘a’

5. Role of Zero : If a is an integer, then

(i) a + 0 = 0 + a = a

(ii) a – 0 = a but 0 – a a [as 0 – a = –a]

Multiplication of integers

i) Positive × Positive = Positive

ii) Positive × Negative = Negative

iii) Negative × Positive = Negative

iv) Negative × Negative = Positive

v) If there are odd number of negative integers in multiplication, then the result will be negative integer.

vi) If there are even number of negative integers in multiplication, then the result will be in positive integer.

Example 18: Find the value of (–8) × 5

CBSE Class 6 Integers Chapter Concepts_1

Division of two integers: Rules to remember

i) Positive Positive = Positive

ii) Negative Positive = Negative

iii) Positive Negative = Negative

iv) Negative Negative = Positive

Example 23: Find the value of 140 ÷ (–20)

Solution: 140/-20 = 14/-2 = -7

Example 24: Find the value of (–140) ÷ (–20)

Solution: 140/-20 = 14/2 = 7

Example 25: The value of (–100) ÷ 20

Solution: -100/20 = -10/2 = -5

Properties of Multiplication and Division of integers

1. Closure property : If a and b are integers, then

i) a × b is an integer

ii) a ÷ b need not be an integer

Example-26

2 × 3 = 6

2 ÷ 3 = 2/3 is a fraction

∴ Closure property is true for multiplication but not for division

2. Commutative property : If a and b are integers, then

i) a × b = b × a

ii) a ÷ b ≠ b ÷ a

Hence commutative property holds for multiplication but not for division.

3. Assosciative property : If a, b and c are integers, then

i) (a × b) × c = a × (b × c)

ii) (a ÷ b) ÷ c a ≠ (b ÷ c)

Hence multiplication integers is associative but not for division of integers.

4. Role of 1 : If a is an integer, then

i) a × 1 = 1 × a = a                    [Here a is called multiplicative identity]

ii) a/1 = a but 1/a ≠ a

5. Inverse : If a is an integer, then

i) a * 1/a = 1/a *a =1                 [1/a is called multiplicative inverse of a]

ii) a/a = 1 ; i.e. a ÷ a = 1

6. Distributive property of multiplication over addition :

If a, b, c are integers, then a × (b + c) = a × b + a × c

Example :

CBSE Class 6 Integers Chapter Concepts_2

 

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CBSE Class 6 Mathematics Chapter 6 Integers Notes

We hope you liked the above notes for topic Chapter 6 Integers which has been designed as per the latest syllabus for Class 6 Mathematics released by CBSE. Students of Class 6 should download and practice the above notes for Class 6 Mathematics regularly. All revision notes have been designed for Mathematics by referring to the most important topics which the students should learn to get better marks in examinations. Studiestoday is the best website for Class 6 students to download all latest study material.

Notes for Mathematics CBSE Class 6 Chapter 6 Integers

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Chapter 6 Integers Notes for Mathematics CBSE Class 6

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Chapter 6 Integers CBSE Class 6 Mathematics Notes

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Notes for CBSE Mathematics Class 6 Chapter 6 Integers

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