CBSE Class 12 Physics Semiconductor Materials Device And Simple Worksheet

Access the latest CBSE Class 12 Physics Semiconductor Materials Device And Simple Worksheet. We have provided free printable Class 12 Physics worksheets in PDF format, specifically designed for Chapter 14 Semiconductor Electronics Materials Devices and Simple Circuits. These practice sets are prepared by expert teachers following the 2025-26 syllabus and exam patterns issued by CBSE, NCERT, and KVS.

Chapter 14 Semiconductor Electronics Materials Devices and Simple Circuits Physics Practice Worksheet for Class 12

Students should use these Class 12 Physics chapter-wise worksheets for daily practice to improve their conceptual understanding. This detailed test papers include important questions and solutions for Chapter 14 Semiconductor Electronics Materials Devices and Simple Circuits, to help you prepare for school tests and final examination. Regular practice of these Class 12 Physics questions will help improve your problem-solving speed and exam accuracy for the 2026 session.

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Semiconductor : materials ,devices and simple circuits
 
Section A Conceptual and application type questions
 

Question. In the following circuit, the output Y for all possible inputs A and B is expressed by the truth table. 
cbse-class-12-physics-semiconductor-materials-device-and-simple-worksheet

Answer: C

Question. What is the voltage gain in a common emitter amplifier, where input resistance is 3 Ω and load resistance 24 Ω, β = 0.6 ?
(a) 8 . 4
(b) 4 . 8
(c) 2 . 4
(d) 480

Answer: B

Question. In a common emitter transistor amplifier β = 60, Ro = 5000 Ω and internal resistance of a transistor is 500 Ω. The voltage amplification of amplifier will be
(a) 500
(b) 460
(c) 600
(d) 560

Answer: C

Question. The band gap in germanium and silicon in ev respectively is
(a) 1.1, 0
(b) 0, 1.1
(c) 1.1, 0.7
(d) 0.7, 1.1

Answer: D

Question. A transistor has three impurity regions. All the three regions have different doping levels. In order of increasing doping level, the regions are
(a) emitter, base and collector
(b) collector, base and emitter
(c) base, emitter and collector
(d) base, collector and emitter

Answer: D

Question. In a common base amplifier the phase difference between the input signal voltage and the output voltage is
(a) 0
(b) π/4
(c) π/2
(d) π

Answer: A

Question. The following circut represents
cbse-class-12-physics-semiconductor-materials-device-and-simple-worksheet
(a) OR gate
(b) XOR gate
(c) AND gate
(d) NAND gate

Answer: B

Question. The electrical conductivity of a semiconductor increases when electromagnetic radiation of wavelength shorter than 2480 nm is incident on it. The band gap (in eV) for the semiconductor is
(a) 0.9
(b) 0.7
(c) 0.5
(d) 1.1

Answer: C

Question. The diagram of a logic circuit is given below. The output F of the circuit is represented by 
cbse-class-12-physics-semiconductor-materials-device-and-simple-worksheet
(a) W . (X + Y)
(b) W . (X . Y)
(c) W + (X . Y)
(d) W + (X + Y)

Answer: C

Question. In the half wave rectifier circuit operating from 50 Hz mains frequency, the fundamental frequency in the ripple would be
(a) 25 Hz
(b) 50 Hz
(c) 70.7 Hz
(d) 100 Hz

Answer: B

Question. A transistor is operated in common emitter configuration at VC = 2V such that a change in the base current from 100 mA to 300 mA produces a change in the collector current from 10mA to 20 mA. The current gain is
(a) 50
(b) 75
(c) 100
(d) 25

Answer: A

Question. In a p-n junction having depletion layer of thickness 10–6 m the potential across it is 0.1 V. The electric field is
(a) 107 V/m
(b) 10–6 V/m
(c) 105 V/m
(d) 10–5 V/m

Answer: C

Question. In the diagram, the input is across the terminals A and C and the output is across B and D. Then the output is
(a) zero
(b) same as the input
(c) full wave rectifier
(d) half wave rectifier

Answer: C

Question. A half-wave rectifier is being used to rectify an alternating voltage of frequency 50 Hz. The number of pulses of rectified current obtained in one second is
(a) 50
(b) 25
(c) 100
(d) 2000

Answer: B

Question. What is the conductivity of a semiconductor if electron density = 5 × 1012/cm3 and hole density = 8 × 1013/cm3e = 2.3 m2 V–1 s–1, μh = 0.01 m2V–1 s–1)
(a) 5.634
(b) 1.968
(c) 3.421
(d) 8.964.

Answer: B

Question. The cause of the potential barrier in a p-n diode is
(a) depletion of positive charges near the junction
(b) concentration of positive charges near the junction
(c) depletion of negative charges near the junction
(d) concentration of positive and negative charges near the junction

Answer: D

Question. The ratio of electron and hole currents in a semiconductor is 7/4 and the ratio of drift velocities of electrons and holes is 5/4, then the ratio of concentrations of electrons and holes will be
(a) 5/7
(b) 7/5
(c) 25/49
(d) 49/25

Answer: B

Question. If A is the atomic mass number of an element, N is the Avogadro number and a is the lattice parameter, then the density of the element, if it has bcc crystal structure, is
(a) A/Na3
(b) 2A/Na3
(c) √3A/Na3
(d) 2√2A/Na3

Answer: B

Question. The current gain in transistor in common base mode is 0.99. To change the emitter current by 5 mA, the necessary change in collector will be
(a) 0.196 mA
(b) 2.45 mA
(c) 4.95 mA
(d) 5.1 mA

Answer: C

Question. In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by 0.5 μA. The reverse bias resistance of the diode is
(a) 2 × 105 Ω
(b) 2 × 106 Ω
(c) 200 Ω
(d) 2 Ω.

Answer: B

Question. The output of the given circuit in figure given below,
(a) would be zero at all times
(b) would be like a half wave rectifier with positive cycles in output
(c) would be like a half wave rectifier with negative cycles in output
(d) would be like that of a full wave rectifier

Answer: C

Question. In the circuit shown in figure given below, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is 
cbse-class-12-physics-semiconductor-materials-device-and-simple-worksheet
(a) 1.3 V
(b) 2.3 V
(c) 0
(d) 0.5 V

Answer: B

Question. The transistor are usually made of
(a) metal oxides with high temperature coefficient of resistivity
(b) metals with high temperature coefficient of resistivity
(c) metals with low temperature coefficient of resistivity
(d) semiconducting materials having low temperature coefficient of resistivity

Answer: A

Question. The truth table given below is for 
cbse-class-12-physics-semiconductor-materials-device-and-simple-worksheet
(a) NOR
(b) AND
(c) XOR
(d) NAND

Answer: D

Question. In a full wave rectifier circuit operating from 50 Hz mains frequency, the fundamental frequency in the ripple would be
(a) 25 Hz
(b) 50 Hz
(c) 70.7 Hz
(d) 100 Hz

Answer: D

Question. The manifestation of band structure in solids is due to
(a) Bohr’s correspondence principle
(b) Pauli’s exclusion principle
(c) Heisenberg’s uncertainty principle
(d) Boltzmann’s law

Answer: B

Question. The frequency response curve of RC coupled amplifier is shown in figure. The band with of the amplifier will be (35 ex 2)
(a) f3 – f2
(b) f4 – f1
(c) f4 – f2/2
(d) f3 – f1

Answer: B

Question. A diode having potential difference 0.5 V across its junction which does not depend on current, is connected in series with resistance of 20Ω across source. If 0.1 A current passes through resistance then what is the voltage of the source?
(a) 1.5 V
(b) 2.0 V
(c) 2.5 V
(d) 5 V

Answer: C

Question. The difference in the variation of resistance with temperature in a metal and a semiconductor arises essentially due to the difference in the
(a) crystal structure
(b) variation of the number of charge carriers with temperature
(c) type of bonding
(d) variation of scattering mechanism with temperature

Answer: B

Question. Carbon, Silicon and Germanium atoms have four valence electrons each. Their valence and conduction bands are separated by energy band gaps represented by (Eg)C, (Eg)Si and (Eg)Ge respectively. Which one of the following relationship is true in their case?
(a) (Eg)C > (Eg)Si
(b) (Eg)C < (Eg)Si
(c) (Eg)C = (Eg)Si
(d) (Eg)C < (Eg)Ge

Answer: A

 
1 State one difference between
i) a diode and a zener diode
ii) solar cell and photodiode
iii) LED and photodiode
 
2 What is the efficiency of a i) half wave rectifier ii) full wave rectifier?
 
3 The current in the forward bias is known to be more (mA) than the current in the reverse bias (μA). What is the reason then to operate the photodiodes in reverse bias?
 
4 Why are Si and GaAs are preferred materials for solar cells?
 
5 Draw energy band diagram for
i) copper
ii) pure germanium
iii) diamond
iv) silicon doped with phosphorous
v) silicon doped with aluminium
 
6 State two differences between the circuits of a i) half wave rectifier ii) full wave rectifier?. 
 
7 Mention the uses of light emitting diode (LED)
 
8 Mention the advantages of light emitting diode (LED) over conventional lighting sources
 
9 What happens to the depletion layer and internal potential barrier of a pn junction diode  during i) forward bias ii) reverse bias ?
 
10 The figure adjoining shows the V-I characteristics of a semiconductor diode.(i) Identify the semiconductor diode used.
(ii) Draw the circuit diagram to obtain the given characteristic of this device.
(iii) Briefly explain how this diode can be used as a voltage regulator.
CBSE Class 12 Physics Semiconductor Materials Device And Simple Worksheet 1
 
11 Explain the working of solar cell with a neat circuit diagram 
 
12 With a neat circuit diagram explain the working of photo diode .
 
13 State the differences between N - type and P- type semiconductors 
 
14 State the differences between intrinsic and extrinsic semiconductors
 
15 What is doping of intrinsic semiconductor? Mention the characteristics of dopant atoms.
 
16 With a neat circuit diagram and input and output wave forms , explain the working of a half wave rectifier .
 
17 With a neat circuit diagram and input and output wave forms, explain the working of a full wave rectifier
 
Section B Numerical problems
 
1 A p-n photodiode is fabricated from a semiconductor with band gap of 2.8 eV. Can it detect a wavelength of 6000 nm?,
 
2 The circuit shown in the figure contains two diodes each with a forward resistance of 50 Ω and infinite backward resistance. Calculate the current in the 100 Ω resistance.
CBSE Class 12 Physics Semiconductor Materials Device And Simple Worksheet 2
 
3 Suppose a pure Si crystal has 5 × 1028 atoms m–3. It is doped by 1ppm concentration of penta valent As. Calculate the number of electrons and holes. Given that ni =1.5 × 1016 m–3.
 
4 Calculate the resistance of the diode at (a) ID = 15 mA and (b) VD = –10 V.

CBSE Class 12 Physics Semiconductor Materials Device And Simple Worksheet 3

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Chapter 14 Semiconductor Electronics Materials Devices and Simple Circuits CBSE Class 12 Physics Worksheet

Students can use the Chapter 14 Semiconductor Electronics Materials Devices and Simple Circuits practice sheet provided above to prepare for their upcoming school tests. This solved questions and answers follow the latest CBSE syllabus for Class 12 Physics. You can easily download the PDF format and solve these questions every day to improve your marks. Our expert teachers have made these from the most important topics that are always asked in your exams to help you get more marks in exams.

NCERT Based Questions and Solutions for Chapter 14 Semiconductor Electronics Materials Devices and Simple Circuits

Our expert team has used the official NCERT book for Class 12 Physics to create this practice material for students. After solving the questions our teachers have also suggested to study the NCERT solutions  which will help you to understand the best way to solve problems in Physics. You can get all this study material for free on studiestoday.com.

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