CBSE Class 11 Chemistry HOTs States of Matter

Please refer to CBSE Class 11 Chemistry HOTs States of Matter. Download HOTS questions and answers for Class 11 Chemistry. Read CBSE Class 11 Chemistry HOTs for Chapter 05 States of Matter below and download in pdf. High Order Thinking Skills questions come in exams for Chemistry in Class 11 and if prepared properly can help you to score more marks. You can refer to more chapter wise Class 11 Chemistry HOTS Questions with solutions and also get latest topic wise important study material as per NCERT book for Class 11 Chemistry and all other subjects for free on Studiestoday designed as per latest CBSE, NCERT and KVS syllabus and pattern for Class 11

Chapter 05 States of Matter Class 11 Chemistry HOTS

Class 11 Chemistry students should refer to the following high order thinking skills questions with answers for Chapter 05 States of Matter in Class 11. These HOTS questions with answers for Class 11 Chemistry will come in exams and help you to score good marks

HOTS Questions Chapter 05 States of Matter Class 11 Chemistry with Answers

Question. A container contains 1 mole of a gas at 1 atm pressure and 27 °C, while its volume is 24.6 litres.
If its pressure is 10 atm and temperature 327°C, then new volume is
(a) 2.56 litres
(b) 3.15 litres
(c) 4.92 litres
(d) 5.44 litres
Answer : C

Question. Equal weights of methane and hydrogen are mixed in an empty container at 25ºC. The fraction of the total pressure exerted by hydrogen is :
(a) 1/2
(b) 8/9
(c) 9/1
(d) 17/16
Answer : B

Question. A spherical balloon of 21 cm diameter is to be filled up with hydrogen at N.T.P. from a cylinder containing the gas at 20 atmospheres at 27ºC. If the cylinder can hold 2.82 litres of water, calculate the number of balloons that can be filled up.
(a) 9
(b) 8
(c) 12
(d) 10
Answer : D

Question. One mole of gas A and three moles of a gas B are placed in flask of volume 100 litres at 27°C. Calculate the total partial pressure of the gases in the mixture.
(a) 1.0 atm.
(b) 0.9 atm
(c) 0.985 atm
(d) 10.850 atm.
Answer : C

Question. 14 g of N2 and 36 g of ozone are at the same pressure and temperature. Their volumes will be related as
(a) 2VN2 = 3VO3
(b) 3VN2 = 2VO3
(c) 3VN2 = 4VO3
(d) 4VN2 = 3VO3
Answer : B

Question. The pressure (P) and volume (V) isotherm of avan der Waals’ gas, at the temperature at which it undergoes gas to liquid transition, is correctly represented by

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Answer : B

Question. 16 g of oxygen and 3 g of hydrogen are mixed and kept at 760 mm of Hg pressure and 0°C. The total volume occupied by the mixture will be nearly
(a) 22.4 litres
(b) 33.6 litres
(c) 448 litres
(d) 44800 mL
Answer : D

Question. 600 c.c. of a gas at a pressure of 750 mm of Hg is compressed to 500 c.c. Taking the temperature to remain constant, the increase in pressure, is
(a) 150 mm of Hg
(b) 250 mm of Hg
(c) 350 mm of Hg
(d) 450 mm of Hg
Answer : A

Question. X mL of H2 gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical conditions is :
(a) 10 seconds : He
(b) 20 seconds : O2
(c) 25 seconds : CO
(d) 55 seconds : CO2
Answer : B

Question. Oxygen is present in 1 litre flask at a pressure of 7.6 × 10–10 mm of Hg. Calculate the number of oxygen molecules in the flask at 0ºC.
(a) 2.8 ×108
(b) 2.7 × 1010
(c) 0.27×1010
(d) 3.0 ×109
Answer : B

Question. The root mean square speeds at STP for the gases H2, N2, O2 and HBr are in the order :
(a) H< N2.< O2 < HBr
(b) HBr < O2 < N2 < H2
(c) H2 < N2 = O< HBr
(d) HBr < O2 < H2 < N2.
Answer : B

Question. A given volume of ozonised oxygen (containing 60% oxygen by volume) required 220 sec to effuse while an equal volume of oxygen took 200 sec only under identical conditions. If density of O2 is 1.6 g/L then find density of O3.
(a) 1.936 g/L
(b) 2.16 g/L
(c) 3.28 g/L
(d) 2.24 g/L
Answer : D

Question. A container of volume 2.24 L can withstand a maximum pressure of 2 atm at 298 K before exploding. The maximum amount of nitrogen (in g) that can be safely put in this container at this temperature is closest to
(a) 2.8
(b) 5.6
(c) 1.4
(d) 4.2
Answer : D

Question. At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen (N2) at 4 bar. The molar mass of gaseous molecule is :
(a) 28 g mol–1
(b) 56 g mol–1
(c) 112 g mol–1
(d) 224 g mol–1
Answer : C

Question. Two flasks A and B of equal volumes maintained at temperatures 300K and 600K contain equal mass of H2 and CH4 respectively. The ratio of total translational kinetic energy of gas in flask A to that in flask B is
(a) unity
(b) 2
(c) 4
(c) 0.25
Answer : C

Question. Calculate the total pressure in a 10.0 L cylinder which contains 0.4 g helium, 1.6 g oxygen and 1.4 g nitrogen at 27 °C.
(a) 0.492 atm
(b) 49.2 atm
(c) 4.52 atm
(d) 0.0492 atm
Answer : A

Question. I, II, and III are three isotherms, respectively, at T1, T2 and T3. Temperature will be in order

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(a) T1 = T2 = T3
(b) T1 < T2 < T3
(c) T1 > T2 > T3
(d) T1 > T2 = T3
Answer : C

Question. The root mean square speed of hydrogen in √5 times than that of nitrogen. If T is the temperature of the gas, then :
(a) TH2 = TN2
(b) TH2 > TN2
(c) TH2 < TN2
(d) TH2 = √TN2
Answer : C

Question. For one mole of a van der Waals gas, the compressibility factor Z(= PV/RT) at a fixed volume will certainly decrease if [Given: “a”, “b” are standard parameters for van der Waals gas]
(a) “b” increases and “a” decreases at constant temperature
(b) “b” decreases and “a” increases at constant temperature
(c) temperature increases at constant “a” and “b” values
(d) “b” increases at constant “‘a” and temperature
Answer : B

Question. A mixture of Ne and Ar kept in a closed vessel at 250 K has a total K.E. = 3kJ. The total mass of Ne and Ar is 30 g. Find mass % of Ne in gaseous mixture at 250 K.
(a) 61.63
(b) 38.37
(c) 50%
(d) 28.3
Answer : D

Numeric Value Answer

Question. A gas diffuse1/5 times as fast as hydrogen. If its molecular weight is 10y. What will be the value of y?
Answer : 5

Question. The root mean square speed of 4g of helium gas is 450 m/s. What is the value of total kinetic energy (J) of this sample?
Answer : 405

Question. At 400 K, the root mean square (rms) speed of a gas X (molecular weight = 40) is equal to the most probable speed of gas Y at 60 K. The molecular weight of the gas Y is
Answer : 4

Question. If an ideal gas at 100 K is heated to 109 K in a rigid container, the pressure increases by X%.
What is the value of X?
Answer : 9

Question. The rate of diffusion of methane at a given temperature is twice that of a gas X. If the molecular weight of X is 8y then what will be the value of y?
Answer : 8

Question. One mole of a gas changed from its initial state (15L, 2 atm) to final state (4L, 10 atm) reversibly. If this change can be represented by a straight line in P – V curve maximum temperature (approximate), the gas attained is x × 102K. Then find the value of x.
Answer : 7

Question. At 300 K, the average kinetic energy of a deuterium molecule is n times than that of a hydrogen molecule. Find the value of n.
Answer : 1

Question. A flask has 10 gas particles, out of which four particles are moving at 7 ms–1 and the remaining are moving at the same speed of ‘X’ ms–1. If the r.m.s. of the gas is 5 ms–1, what is the value of X?
Answer : 3

Question. A flask containing air at 107°C and 722 mm of Hg is cooled to 100 K and 760 mm of Hg. If density in the initial condition 1 g/cm3, then what is the final density (g/cm3)?
Answer : 4

Question. If the ratio of critical temperature to critical pressure for a real gas is mb/R, then what is the integer value of m?
Answer : 8

HOTS for Chapter 05 States of Matter Chemistry Class 11

Expert teachers of studiestoday have referred to NCERT book for Class 11 Chemistry to develop the Chemistry Class 11 HOTS. If you download HOTS with answers for the above chapter you will get higher and better marks in Class 11 test and exams in the current year as you will be able to have stronger understanding of all concepts. High Order Thinking Skills questions practice of Chemistry and its study material will help students to have stronger understanding of all concepts and also make them expert on all critical topics. You can easily download and save all HOTS for Class 11 Chemistry also from www.studiestoday.com without paying anything in Pdf format. After solving the questions given in the HOTS which have been developed as per latest course books also refer to the NCERT solutions for Class 11 Chemistry designed by our teachers. We have also provided lot of MCQ questions for Class 11 Chemistry in the HOTS so that you can solve questions relating to all topics given in each chapter. After solving these you should also refer to Class 11 Chemistry MCQ Test for the same chapter

Where can I download latest CBSE HOTS for Class 11 Chemistry Chapter 05 States of Matter

You can download the CBSE HOTS for Class 11 Chemistry Chapter 05 States of Matter for latest session from StudiesToday.com

Are the Class 11 Chemistry Chapter 05 States of Matter HOTS available for the latest session

Yes, the HOTS issued by CBSE for Class 11 Chemistry Chapter 05 States of Matter have been made available here for latest academic session

What does HOTS stand for in Class 11 Chemistry Chapter 05 States of Matter

HOTS stands for "Higher Order Thinking Skills" in Chapter 05 States of Matter Class 11 Chemistry. It refers to questions that require critical thinking, analysis, and application of knowledge

How can I improve my HOTS in Class 11 Chemistry Chapter 05 States of Matter

Regular revision of HOTS given on studiestoday for Class 11 subject Chemistry Chapter 05 States of Matter can help you to score better marks in exams

Are HOTS questions important for Chapter 05 States of Matter Class 11 Chemistry exams

Yes, HOTS questions are important for Chapter 05 States of Matter Class 11 Chemistry exams as it helps to assess your ability to think critically, apply concepts, and display understanding of the subject.