NCERT Exemplar Solutions Class 9 Science Gravitation

Multiple Choice Questions (MCQs)..........................

 

Question 1:  Two objects of different masses falling freely near the surface of moon would
(a) have same velocities at any instant
(b) have different accelerations
(c) experience forces of same magnitude
(d) undergo a change in their inertia

Answer 1:  (a) have same velocities at any instant.

Objects of various masses falling freely near the moon's surface will have the same velocities at any given time due to the same gravity acceleration.

 

Question 2: The value of acceleration due to gravity
(a) is same on equator and poles
(b) is least on poles
(c) is least on equator
(d) increases from pole to equator

Answer 2:   (c) is least on equator.

Owing to the rotation of the planet, it is lowest at the equator and highest at the poles i.e., it is given by

 NCERT Exemplar Solutions Class 9 Science Gravitation

g’=g-co2 R sin0
At poles 0 = 0,

So g maximum
At equator 0 = 90°,

So g maximum

 

Question 3:  The gravitational force between two objects is F. If masses of both objects are halved without changing distance between them, then the gravitational force would become

(a) F/4

(b) F/2

(c) F

(d) 2 F

Answer 3:  (a) F/4.

We know that, according to force of gravitation

NCERT Exemplar Solutions Class 9 Science Gravitation

 

Question 4:  A boy is whirling a stone tied with a string in an horizontal circular path. If the string breaks, the stone
(a) will continue to move in the circular path
(b) will move along a straight line towards the centre of the circular path
(c) will move along a straight line tangential to the circular path
(d) will move along a straight line perpendicular to the circular path away from the boy

Answer 4:  (c) will move along a straight line tangential to the circular path.

The direction of velocity at a point in circular motion is always along the tangent at that point. If the string snaps, the stone's centripetal force is zeroed, and it moves in a straight line tangential to the circular direction.

 NCERT Exemplar Solutions Class 9 Science Gravitation

where vA, vB, vC, vD are the velocities point A, B, C, D in circular path.

 

Question 5:  An object is put one by one in three liquids having different densities. The object floats with 1 2 3 , and 9 11 7 parts of their volumes outside the liquid surface in liquids of densities d1, d2 and d3 respectively. Which of the following statement is correct?

(a) d1 >d2> d3                      

(b) d1 > d2 < d3

(c) d1 < d2 > d3                       

(d) d1 < d2 < d3 

Answer 5:   (d) d1 < d2 < d3. 

A higher density liquid allows more of the object to stay outside the liquid. Since (part of the body outside the liquid) densities of liquid determine the order of part of their volume outside the liquid,  
1/9<2/11<3/7  
Thus, the order of densities in increasing order is 
d1<d2< d3 
 

Question 6:  In the relation F = GMm/d2, the quantity G
(a) depends on the value of g at the place of observation
(b) is used only when the earth is one of the two masses
(c) is greatest at the surface of the earth
(d) is universal constant of nature

Answer 6:   (d) is universal constant of nature. 

The quantity G is a natural universal constant. It is applicable to all living things in the world. In Newton's universal law of gravitation, it is the proportionality constant.

G is 6.67x 1CT-11 Nm2 kg-2, which is the accepted value.

 

Question 7:  Law of gravitation gives the gravitational force between
(a) the earth and a point mass only
(b) the earth and the sun only
(c) any two bodies having some mass
(d) two charged bodies only

Answer 7:   (c) any two bodies having some mass.

NCERT Exemplar Solutions Class 9 Science Gravitation

where,              F = Force of attraction between the two bodies

              m1 m2   = Mass of two bodies

                         G = Gravitational Constant

                          r = Distance between the two bodies

 

Question 8:  The value of quantity G in the law of gravitation
(a) depends on mass of the earth only
(b) depends on radius of earth only
(c) depends on both mass and radius of the earth
(d) is independent of mass and radius of the earth

Answer 8:   (d) is independent of mass and radius of the earth.

G, also known as the universal gravitational constant, is a proportionality constant. It is unaffected by the earth's mass or radius.

 

Question 9:  Two particles are placed at some distance. If the mass of each of the two particle is doubled, keeping the distance between them unchanged, the value of gravitational force between them will be

(a) 14 times

(b) 4 times

(c) 12 times

(d) unchanged

Answer 9:   (b) 4 times.

We know that, according to gravitational force

NCERT Exemplar Solutions Class 9 Science Gravitation

 

Question 10:  The atmosphere is held to the earth by

(a) gravity                                                 

(b) wind

(c) clouds                                                   

(d) earth’s magnetic field

Answer 10:   (a) gravity. 

Gravity binds the atmosphere to the surface.

 

Question 11:  The force of attraction between two unit point masses separated by a unit distance is called

(a) gravitational potential                       

(b) acceleration due to gravity

(c) gravitational field                                 

(d) universal

Answer 11:   (d) universal.

We know that, the gravitational force,

NCERT Exemplar Solutions Class 9 Science Gravitation

 

As a result, the universal gravitational constant is the force of attraction between two unit point masses separated by a unit distance.

 

Question 12:  The weight of an object at the centre of the earth of radius R, is

(a) zero

(b) infinite

(c) R times the weight at the surface of the earth

(d) 1/R2 times the weight at the surface of the earth

Answer 12:  (a) zero. 

The weight of an object, w = mg
At the centre of the earth, acceleration due to gravity g is zero. And is given by

NCERT Exemplar Solutions Class 9 Science Gravitation

where h = distance from surface of the earth to centre of the earth and at
centre (h = R) i.e., g’=0.
So, w = m x 0 = 0

 

Question 13:  An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be
(a) 2N       

(b) 8N                         

(c) 10N                    

(d) 12N

Answer 13:   (a) 2N.

Given, Weight of an object in air = 10N

             Weight of an object in water = 8N
So, the weight of the liquid displaced by the object F = 10 - 8 =2N, and we know that buoyancy force = weight of the liquid displaced by the body, according to Archimedes' Theory.

 

Question 14:  A girl stands on a box having 60 cm length, 40 cm breadth and 20 cm width in three ways. In which of the following cases, pressure exerted by the brick will be
(a) maximum when length and breadth form the base
(b) maximum when breadth and width form the base
(c) maximum when width and length form the base
(d) the same in all the above three cases


Answer 14:  (b) maximum when breadth and width form the base. 

Now, when the base is shaped by breadth and width, according to the query. The amount of space available would be minimal. As a result, the strain would be at its peak.

 

Question 15:  An apple falls from a tree because of gravitational attraction between the earth and apple. If is the magnitude of force exerted by the earth on the apple and f2 is the magnitude of force exerted by apple on earth, then 

(a) F1 is very much greater than F2        

(b) F2 is very much greater than F1

(c) F1 is only a little greater than F2       

(d) F1 and F2 are equal

Answer 15:   (d) F1 and F2 are equal.

According to Newton’s universal law of gravitation, force exerted by the one body to other body is equal in magnitude and given by

 

NCERT Exemplar Solutions Class 9 Science Gravitation

 

Short Answer Type Questions...........................

 

Question 16:  What is the source of centripetal force that a planet requires to revolve around the sun? On what factors does that force depend? 

Answer 16:   The centripetal force is responsible for the planet's rotation around the earth. The gravitational force between the earth and the sun produces this centripetal force. 

NCERT Exemplar Solutions Class 9 Science Gravitation
This force is proportional to the mass of the sun and the mass of the earth, as well as the distance between them. 

 

Question 17:  On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?

Answer 17:

Time taken by both stone is given by second equation of motion s = ut +1/2 at2
As,     uy = 0, so, s = 1/2at2
and here                                              s = h
Where, m = Initial velocity in y-axis
a = g acceleration due to gravity
t = time displacement to time

NCERT Exemplar Solutions Class 9 Science Gravitation 

As a result, if we drop a stone from a height (h) while simultaneously throwing another stone in a horizontal direction, both stones would hit simultaneously the earth at different locations.  

 

Question 18:  Suppose gravity of the earth suddenly becomes zero, then in which direction will the moon begin to move if no other celestial body affects it? 

Answer 18:    The moon goes off in a straight line because the earth's gravity is absent. A tangent to the circular path would be this straight line.

 NCERT Exemplar Solutions Class 9 Science Gravitation

 

Question 19:  Identical packets are dropped from two airplanes, one above the equator and the other above the north pole, both at height h. Assuming all conditions are identical, will those packets take same time to reach the surface of earth. Justify your answer.

Answer 19:   No, such packets do not take the same amount of time to hit the earth's surface. Due to the rotation of the planet, the value of g (i.e., gravity acceleration) differs at the poles and equator, and is given by g'= g -a>2rsin0, with 0 = 0 at the poles and 0 = 90° at the equator.

So, value of g at equator is less than value of g at poles and we know that,

NCERT Exemplar Solutions Class 9 Science Gravitation

Due to the fact that g is greater at the poles than at the equator. As a result, a packet dropped over the north pole would be the first to hit the earth's surface.

 

Question 20:  The weight of any person on the moon is about 1/6 times that on the earth. He can lift a mass of 15 kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

Answer 20:
Weight of person on moon = 1/6th of weight on earth

Therefore, ‘g’ on moon = 1/6th ‘g’ on earth

The force that is applied by the man to lift mass ‘m’ is

F = mg = 15kg    (on earth)

If he can lift a certain mass ‘m’ by applying the same force on moon, then

F = 15 * 6 = 90kg

This shows that the acceleration due to gravity on the moon is one-sixth that on Earth. As a result, on the moon, an individual can lift a mass that is six times heavier than on Earth.

 

Question 21:  Calculate the average density of the earth in terms of g, G and R.

Answer 21:

NCERT Exemplar Solutions Class 9 Science Gravitation

 

Question 22:  The earth is acted upon by gravitation of the sun, even though it does not fall into the sun. Why?

Answer 22:   The sun is the centre of the universe, and the world revolves around it. The world needs the centripetal force to revolve around the sun. The gravitational force between the sun and the earth provides this centripetal force. This gravitational force prevents the earth from colliding with the sun. 

 

Long Answer Type Questions......................

 

Question 23:  How does the weight of an object vary with respect to mass and radius of the earth? In a hypothetical case, if the diameter of the earth becomes half of its present value and its mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected? 

Answer 23:  Let R and M be the radius and mass of the earth 

Then 

Weight of the object = M/R2 

Original weight W0 = mg = mg M/R2 

Hypothetically 4m and R becomes R/2 

Then, weight = mG 4M /(R/2) 2 

= (16m g) M/R2 

= 10xW0 

Weight will be 16 times. 

 

Question 24:  How does the force of attraction between the two bodies depend upon their masses and distance between them? A student thought that two bricks tied together would fall faster than a single one under the action of gravity. Do you agree with his hypothesis or not? Comment. 

Answer 24:   Newton's universal law of gravitation describes the force of attraction between two bodies of mass m1 and m2 and separated by a distance r

NCERT Exemplar Solutions Class 9 Science Gravitation

 

(where M = Mass of the earth, R = Radius of the earth)
And it's obvious from the equation that gravity's acceleration (g) is solely determined by the earth's mass and radius. As a result, under the influence of gravity, two bricks bound together would not fall faster than a single brick. As a consequence, the hypothesis is false. 

 

Question 25:  Two objects of masses m1 and m2 having the same size are dropped simultaneously from heights /7a and h2 respectively. Find out the ratio of time they would take in reaching the ground. Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid and (ii) both of them are hollow, size remaining the same in each case? Give reason. 

Answer 25:

NCERT Exemplar Solutions Class 9 Science Gravitation


Question 26:  (i) A cube of side 5 cm is immersed in water and then in saturated salt solution. In which case will it experience a greater buoyant force? If each side of the cube is reduced to 4 cm and then immersed in water, what will be the effect on the buoyant force experienced by the cube as compared to the first case for water? Give reason for each case.
(ii) A ball weighing 4 kg of density 4000 kgm−3 is completely immersed in water of density 103 kgm−3. Find the force of buoyancy on it. (Given, g= 10 ms−2)

Answer 26:

i)        Buoyant force, F = Vpg
(where, p= Density of water, V = Volume of water displaced by the body)
Since saturated salt solutions have a higher density than water, buoyant force is determined by volume and density. As a result, in a saturated solution, the buoyant force on the cube would be greater.
If each side of the cube is cut down to 4 cm, the volume of the cube is reduced. Since buoyant force is proportional to volume. As a result, the buoyant force would be lower than in the first case for water.

ii)       The magnitude of the buoyant force given by F = Vpg
where V = Volume of body immersed in water or volume of water displaced,

                        p = Density of liquid.
                     [∴ Given, mass of a ball = 4 kg, density = 4000 kgm-3

    ∴                                Volume of solid =  (Mass )/Density

                                                                = 4/4000 = 1/1000 m3 

           Buoyancy,                                          F = Vρg

                                                               = 1/1000 × 1000 × 10 = 10 N