Class 11 Mathematics Trigonometric Equations MCQs Set 06

Practice Class 11 Mathematics Trigonometric Equations MCQs Set 06 provided below. The MCQ Questions for Class 11 Chapter 3 Trigonometric Functions Mathematics with answers and follow the latest CBSE/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for CBSE Class 11 Mathematics and also download more latest study material for all subjects

MCQ for Class 11 Mathematics Chapter 3 Trigonometric Functions

Class 11 Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Chapter 3 Trigonometric Functions

Chapter 3 Trigonometric Functions MCQ Questions Class 11 Mathematics with Answers

SINGLE ANSWER QUESTIONS

Question. If \( x = \sec \theta + \tan \theta, y = \operatorname{cosec} \theta - \cot \theta \) then \( y = \)
(a) \( \frac{1+x}{1-x} \)
(b) \( \frac{1-x}{1+x} \)
(c) \( \frac{x+1}{x-1} \)
(d) \( \frac{x-1}{x+1} \)
Answer: (d) \( \frac{x-1}{x+1} \)

 

Question. \( 0 \leq a \leq 3, 0 \leq b \leq 3 \) and the equation \( x^2 + 4 + 3\cos(ax+b) = 2x \) has at least one solution then the value of (a+b)
(a) \( \frac{\pi}{2} \)
(b) \( \frac{\pi}{4} \)
(c) \( \frac{\pi}{3} \)
(d) \( \pi \)
Answer: (d) \( \pi \)

 

Question. If \( \frac{\sin^4 \theta}{a} + \frac{\cos^4 \theta}{b} = \frac{1}{a+b} \) then \( \frac{\sin^8 \theta}{a^3} + \frac{\cos^8 \theta}{b^3} = \)
(a) \( \frac{1}{(a+b)^3} \)
(b) \( \frac{1}{(a+b)^2} \)
(c) \( a+b \)
(d) \( \frac{1}{a+b} \)
Answer: (a) \( \frac{1}{(a+b)^3} \)

 

Question. If \( \sin^3 x \sin 3x = \sum_{m=0}^6 c_m \cos^m x \), where \( c_0, c_1, \dots, c_6 \) are constants, then
(a) \( c_0 + c_2 + c_4 + c_6 = 0 \)
(b) \( c_1 + c_3 + c_5 = 6 \)
(c) \( 2c_2 + 3c_6 = 0 \)
(d) \( c_4 + 2c_6 = 0 \)
Answer: (a) \( c_0 + c_2 + c_4 + c_6 = 0 \)
 

Question. The minimum value of \( 2\cos \theta + \frac{1}{\sin \theta} + \sqrt{2}\tan \theta \) in \( \left(0, \frac{\pi}{2}\right) \) is
(a) \( 2+\sqrt{2} \)
(b) \( 3\sqrt{2} \)
(c) \( 2\sqrt{3} \)
(d) \( 3+\sqrt{2} \)
Answer: (b) \( 3\sqrt{2} \)

 

Question. If \( \tan(\pi \cos \theta) = \cot(\pi \sin \theta), 0 < \theta < \frac{3\pi}{4} \) then \( \sin\left(\theta + \frac{\pi}{4}\right) = \)
(a) \( \frac{1}{\sqrt{2}} \)
(b) \( -\frac{1}{\sqrt{2}} \)
(c) \( \frac{1}{2\sqrt{2}} \)
(d) \( -\frac{1}{2\sqrt{2}} \)
Answer: (c) \( \frac{1}{2\sqrt{2}} \)

 

Question. If \( \tan \alpha = \frac{1}{\sqrt{x(x^2+x+1)}}, \tan \beta = \frac{\sqrt{x}}{\sqrt{x^2+x+1}} \) and \( \tan \gamma = \sqrt{x^{-3}+x^{-2}+x^{-1}} \) then \( \alpha + \beta = \)
(a) \( \gamma \)
(b) \( 2\gamma \)
(c) \( -\gamma \)
(d) \( \gamma/2 \)
Answer: (a) \( \gamma \)

 

Question. \( (\sin^8 75^\circ - \cos^8 75^\circ) = \)
(a) 1
(b) \( \frac{3\sqrt{3}}{8} \)
(c) \( \frac{3\sqrt{3}}{16} \)
(d) \( \frac{7\sqrt{3}}{16} \)
Answer: (d) \( \frac{7\sqrt{3}}{16} \)

 

Question. \( \sin 20^\circ(4 + \sec 20^\circ) = \)
(a) \( \frac{1}{2} \)
(b) \( \sqrt{2} \)
(c) \( \sqrt{3} \)
(d) 1
Answer: (c) \( \sqrt{3} \)

 

Question. \( 3\tan^6 10^\circ - 27\tan^4 10^\circ + 33\tan^2 10^\circ = \)
(a) 0
(b) 1
(c) 2
(d) 3
Answer: (b) 1

 

Question. If \( 4n\alpha = \pi \), then the numerical value of \( \tan \alpha \tan 2\alpha \tan 3\alpha \dots \tan(2n-1)\alpha \) is equal to
(a) -1
(b) 0
(c) 1
(d) 2
Answer: (c) 1

 

Question. If \( \sec^4 \theta + \sec^2 \theta = 10 + \tan^4 \theta + \tan^2 \theta \) then \( \sin^2 \theta = \)
(a) \( \frac{2}{3} \)
(b) \( \frac{3}{4} \)
(c) \( \frac{4}{5} \)
(d) \( \frac{5}{6} \)
Answer: (c) \( \frac{4}{5} \)

 

Question. In \( \Delta ABC \), \( A = \frac{\pi}{4} \) and \( \tan B \tan C = P \) then all possible values of P is
(a) \( (-\infty, 3-2\sqrt{2}) \cup (3+2\sqrt{2}, \infty) \)
(b) \( (-\infty, 3-2\sqrt{2}] \cup [3+2\sqrt{2}, \infty) \)
(c) \( (3-2\sqrt{2}, 3+2\sqrt{2}) \)
(d) \( [3-2\sqrt{2}, 3+2\sqrt{2}] \)
Answer: (b) \( (-\infty, 3-2\sqrt{2}] \cup [3+2\sqrt{2}, \infty) \)

 

Question. \( \sin \frac{2\pi}{7} + \sin \frac{4\pi}{7} + \sin \frac{8\pi}{7} = \)
(a) \( \sqrt{7}/2 \)
(b) \( 7/2 \)
(c) \( -\sqrt{7}/2 \)
(d) \( -7/2 \)
Answer: (a) \( \sqrt{7}/2 \)

 

Question. \( \sin \frac{\pi}{7} \sin \frac{2\pi}{7} \sin \frac{4\pi}{7} = \)
(a) \( \frac{\sqrt{7}}{8} \)
(b) \( \frac{\sqrt{7}}{4} \)
(c) \( \frac{\sqrt{7}}{2} \)
(d) \( \sqrt{7} \)
Answer: (a) \( \frac{\sqrt{7}}{8} \)

 

Question. If \( \tan\left(x + \frac{\pi}{4}\right) = a \) then \( \sec^2 x = \)
(a) \( 1 + a^2 \)
(b) \( \frac{4a}{(a+1)^2} \)
(c) \( \frac{2(a^2+1)}{(a+1)^2} \)
(d) \( \left(\frac{a-1}{a+1}\right)^2 \)
Answer: (c) \( \frac{2(a^2+1)}{(a+1)^2} \)

 

Question. If \( \alpha, \beta, \gamma \) do not differ by a multiple of \( \pi \) and if \( \frac{\cos(\alpha+\theta)}{\sin(\beta+\gamma)} = \frac{\cos(\beta+\theta)}{\sin(\gamma+\alpha)} = \frac{\cos(\gamma+\theta)}{\sin(\alpha+\beta)} = k \). Then k equals
(a) \( \pm 2 \)
(b) \( \pm \frac{1}{2} \)
(c) 0
(d) \( \pm 1 \)
Answer: (d) \( \pm 1 \)

 

Question. If A, B, C are in A.P and \( B = \frac{\pi}{4} \) then \( \tan A \tan B \tan C = \)
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (a) 1

 

Question. If \( \theta = \frac{\pi}{2^n+1} \) then \( \cos \theta \cos 2\theta \cos 2^2\theta \dots \cos 2^{n-1}\theta \) is equal to
(a) \( \frac{1}{2^n} \)
(b) \( \cos \theta \)
(c) 2
(d) \( 2^n \)
Answer: (a) \( \frac{1}{2^n} \)

 

Question. If ABC is a triangle and \( \tan \frac{A}{2}, \tan \frac{B}{2}, \tan \frac{C}{2} \) are in H.P then the minimum value of \( \cot \frac{B}{2} \) is equal to
(a) \( -\sqrt{3} \)
(b) \( \sqrt{3} \)
(c) 2
(d) -2
Answer: (b) \( \sqrt{3} \)

 

Question. \( \sum_{r=1}^{10} \cos^3 \frac{r\pi}{3} = \)
(a) \( -\frac{1}{8} \)
(b) \( -\frac{7}{8} \)
(c) \( -\frac{9}{8} \)
(d) \( \frac{1}{8} \)
Answer: (c) \( -\frac{9}{8} \)

 

Question. If \( \sin \frac{\pi}{18} \sin \frac{5\pi}{18} \sin \frac{7\pi}{18} = \)
(a) 8
(b) \( \frac{1}{8} \)
(c) 1/7
(d) 6
Answer: (b) \( \frac{1}{8} \)

 

Question. The value of \( \cos y \cos(\pi/2 - x) - \cos(\pi/2 - y)\cos x + \sin y \cos(\pi/2 - x) + \cos x\sin(\pi/2 - y) \) is zero if
(a) \( x = 0 \)
(b) \( y = 0 \)
(c) \( x = y \)
(d) \( x = n\pi - \pi/4 + y (n \in I) \)
Answer: (d) \( x = n\pi - \pi/4 + y (n \in I) \)

 

Question. If \( \tan \theta_1, \tan \theta_2, \tan \theta_3 \) and \( \tan \theta_4 \) are the roots of the equation \( x^4 - x^3\sin 2\beta + x^2\cos 2\beta - x\cos \beta - \sin \beta = 0 \) then \( \tan(\theta_1 + \theta_2 + \theta_3 + \theta_4) \) is equal to
(a) \( \sin \beta \)
(b) \( \cos \beta \)
(c) \( \tan \beta \)
(d) \( \cot \beta \)
Answer: (d) \( \cot \beta \)

 

Question. If \( \frac{\sin^3 \theta - \cos^3 \theta}{\sin \theta - \cos \theta} - \frac{\cos \theta}{\sqrt{1+\cot^2 \theta}} = -2\tan \theta \cot \theta = -1, \theta \in [0, 2\pi] \) then
(a) \( \theta \in (0, \pi/2) - \{\pi/4\} \)
(b) \( \theta \in \left(\frac{\pi}{2}, \pi\right) - \{3\pi/4\} \)
(c) \( \theta \in \left(\pi, \frac{3\pi}{2}\right) - \{5\pi/4\} \)
(d) \( \theta \in (0, \pi) - \{\pi/4, \pi/2\} \)
Answer: (d) \( \theta \in (0, \pi) - \{\pi/4, \pi/2\} \)

 

Question. If \( \frac{\tan(\alpha+\beta-\gamma)}{\tan(\alpha-\beta+\gamma)} = \frac{\tan \gamma}{\tan \beta} \) \( (\beta \neq \gamma) \) then \( \sin 2\alpha + \sin 2\beta + \sin 2\gamma = \)
(a) 0
(b) 1
(c) 2
(d) 1/2
Answer: (a) 0

 

Question. \( \cos 56^\circ + \cos 58^\circ - \cos 66^\circ - 4\cos 28^\circ \cos 29^\circ \sin 33^\circ = \)
(a) 0
(b) 1
(c) -1
(d) 2
Answer: (c) -1

 

Question. If \( \frac{x}{y} = \frac{\cos A}{\cos B} \) then \( \frac{x\tan A + y\tan B}{x+y} = \)
(a) \( \tan \frac{A+B}{2} \)
(b) \( \tan \frac{A-B}{2} \)
(c) \( \cot \frac{A+B}{2} \)
(d) \( \cot \frac{A-B}{2} \)
Answer: (a) \( \tan \frac{A+B}{2} \)

 

Question. If \( \sin x + \operatorname{cosec} x + \tan y + \cot y = 4 \) where \( x \) and \( y \in \left(0, \frac{\pi}{2}\right) \) \( \tan \frac{y}{2} \) is a root of the equation
(a) \( \alpha^2 + 2\alpha + 1 = 0 \)
(b) \( \alpha^2 + 2\alpha - 1 = 0 \)
(c) \( 2\alpha^2 - 2\alpha - 1 = 0 \)
(d) \( \alpha^2 - \alpha - 1 = 0 \)
Answer: (b) \( \alpha^2 + 2\alpha - 1 = 0 \)

 

Question. An integral value of a for which there is a solution of the equation \( a\cos x + \cot x + 1 = \operatorname{cosec} x \) is \( (\sin 2x \neq 0) \)
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (c) 3

 

Question. If \( y = (1+\tan A)(1-\tan B) \) where \( A - B = \frac{\pi}{4} \) then \( (y+1)^{y+1} = \)
(a) 27
(b) 9
(c) 81
(d) 4
Answer: (a) 27

 

Question. Let A, B, C be three angles such that \( A = \frac{\pi}{4} \) and \( \tan B \tan C = p \). Then, all possible values of p such that A, B, C are the angles of a triangle is
(a) \( \leq (\sqrt{2}+1)^2 \)
(b) \( \geq (\sqrt{2}+1)^2 \)
(c) \( > (\sqrt{2}+1)^2 \)
(d) \( < (\sqrt{2}+1)^2 \)
Answer: (b) \( \geq (\sqrt{2}+1)^2 \)

 

Question. If \( \tan \alpha = \frac{P}{q} \) where \( \alpha = 2\beta \), \( \alpha \) being an acute angle then \( \frac{1}{2}[p\operatorname{cosec} 2\beta + q\sec 2\beta] \) is equal to
(a) \( \sqrt{p^2+q^2} \)
(b) \( \sqrt{p^2-q^2} \)
(c) \( \sqrt{2p^2+q^2} \)
(d) \( 2\sqrt{p^2+q^2} \)
Answer: (a) \( \sqrt{p^2+q^2} \)

 

Question. If \( \frac{\cos x}{a} = \frac{\cos(x+\theta)}{b} = \frac{\cos(x+2\theta)}{c} = \frac{\cos(x+3\theta)}{d} \) then \( \frac{a+c}{b+d} \) is equal to
(a) a/d
(b) c/d
(c) b/c
(d) d/a
Answer: (c) b/c

 

Question. If \( \sqrt{2}\cos A = \cos B + \cos^3 B \) and \( \sqrt{2}\sin A = \sin B - \sin^3 B \) then \( \sin(A-B) = \)
(a) \( \pm 1 \)
(b) \( \pm \frac{1}{2} \)
(c) \( \pm \frac{1}{3} \)
(d) \( \pm \frac{1}{4} \)
Answer: (c) \( \pm \frac{1}{3} \)

MCQs for Chapter 3 Trigonometric Functions Mathematics Class 11

Students can use these MCQs for Chapter 3 Trigonometric Functions to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Class 11 Mathematics released by CBSE. Our expert teachers suggest that you should practice daily and solving these objective questions of Chapter 3 Trigonometric Functions to understand the important concepts and better marks in your school tests.

Chapter 3 Trigonometric Functions NCERT Based Objective Questions

Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for Class 11. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Chapter 3 Trigonometric Functions, you should also refer to our NCERT solutions for Class 11 Mathematics created by our team.

Online Practice and Revision for Chapter 3 Trigonometric Functions Mathematics

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