Practice Class 11 Mathematics Sequences and Series MCQs Set 11 provided below. The MCQ Questions for Class 11 Chapter 8 Sequences and Series Mathematics with answers and follow the latest CBSE/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for CBSE Class 11 Mathematics and also download more latest study material for all subjects
MCQ for Class 11 Mathematics Chapter 8 Sequences and Series
Class 11 Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Chapter 8 Sequences and Series
Chapter 8 Sequences and Series MCQ Questions Class 11 Mathematics with Answers
Question. If \( a_1, a_2, a_3, \dots, a_{n+1} \) are in A.P., of non zero terms then \( \frac{1}{a_1 a_2} + \frac{1}{a_2 a_3} + \dots + \frac{1}{a_n a_{n+1}} \), is
(a) \( \frac{n-1}{a_1 a_{n+1}} \)
(b) \( \frac{1}{a_1 a_{n+1}} \)
(c) \( \frac{n+1}{a_1 a_{n+1}} \)
(d) \( \frac{n}{a_1 a_{n+1}} \)
Answer: (d) \( \frac{n}{a_1 a_{n+1}} \)
Question. If \( a_1, a_2, a_3, \dots, a_n \) is an A.P of non zero terms such that \( \frac{1}{a_1 a_n} + \frac{1}{a_2 a_{n-1}} + \frac{1}{a_3 a_{n-2}} + \dots + \frac{1}{a_n a_1} = \lambda \left\{ \frac{1}{a_1} + \frac{1}{a_2} + \dots + \frac{1}{a_n} \right\} \) then \( \lambda = \)
(a) 2
(b) \( a_1 + a_n \)
(c) \( 2(a_1 + a_n) \)
(d) \( \frac{2}{a_1 + a_n} \)
Answer: (d) \( \frac{2}{a_1 + a_n} \)
Question. If \( A_1, A_2, A_3, \dots, A_n \) are 'n' numbers inserted between a,b to form A.P. then \( A_1 + A_2 + A_3 + \dots + A_n \)
(a) \( \frac{a+b}{2} \)
(b) \( \frac{n}{2}(a+b) \)
(c) \( \frac{n}{4}(a+b) \)
(d) \( \frac{n}{3}(a+b) \)
Answer: (b) \( \frac{n}{2}(a+b) \)
Question. If the arthimetic mean between a and b is \( \frac{a^{n+1} + b^{n+1}}{a^n + b^n} \), then n =
(a) 0
(b) 1
(c) –1
(d) 1/2
Answer: (a) 0
Question. If the number of terms in a G.P. is odd, then product of terms =
(a) \( (middle\ term)^{no\ of\ terms} \)
(b) \( (middle\ term)^{no\ of\ terms - 1} \)
(c) \( (middle\ term)^{no\ of\ even\ terms + 2} \)
(d) \( (middle\ term)^{no\ of\ terms + 1} \)
Answer: (a) \( (middle\ term)^{no\ of\ terms} \)
Question. If the number of terms in a G.P. is even, then product of terms =
(a) \( (G.M.\ of\ middle\ terms)^{no\ of\ terms} \)
(b) \( (A.M.\ of\ middle\ terms)^{no\ of\ terms} \)
(c) \( (H.M.\ of\ middle\ terms)^{no\ of\ terms} \)
(d) \( (G.M.\ of\ middle\ terms)^{no\ of\ terms - 1} \)
Answer: (a) \( (G.M.\ of\ middle\ terms)^{no\ of\ terms} \)
Question. If \( G_1, G_2, G_3 \dots G_n \) are n numbers inserted between a,b of G.P. then common ratio is
(a) \( \left( \frac{a}{b} \right)^{\frac{1}{n+1}} \)
(b) \( \left( \frac{b}{a} \right)^{\frac{1}{n+1}} \)
(c) \( \left( \frac{b}{a} \right)^{n+1} \)
(d) \( \left( \frac{a}{b} \right)^{n+1} \)
Answer: (b) \( \left( \frac{b}{a} \right)^{\frac{1}{n+1}} \)
Question. If \( G_1, G_2, G_3 \dots G_n \) are n numbers inserted between a,b to form a G.P. then \( G_1 G_2 G_3 \dots G_n = \)
(a) \( \sqrt{ab} \)
(b) \( (\sqrt{ab})^n \)
(c) \( (\sqrt{ab})^{n+1} \)
(d) \( \left( \frac{a+b}{2} \right)^n \)
Answer: (b) \( (\sqrt{ab})^n \)
Question. If the geometric mean between a and b is \( \frac{a^{n+1} + b^{n+1}}{a^n + b^n} \) then n =
(a) 0
(b) 1/2
(c) – 1/2
(d) 1/4
Answer: (c) – 1/2
Question. If the harmonic mean between a and b is \( \frac{a^{n+1} + b^{n+1}}{a^n + b^n} \), then n=
(a) 0
(b) –1
(c) –1/2
(d) 1
Answer: (b) –1
Question. In an A.P., if first term is 4, 9th term is 20, then 15th term is
(a) 16
(b) 32
(c) 18
(d) 36
Answer: (b) 32
Question. The number of numbers that are divisible by 9 between 1 and 1000 is
(a) 101
(b) 110
(c) 111
(d) 100
Answer: (c) 111
Question. Let \( T_r \) be the \( r^{th} \) term of an A.P. whose first term is a and common difference is d. If for some positive integers m,n, \( m \neq n \), \( T_m = \frac{1}{n} \) and \( T_n = \frac{1}{m} \), then a-d=
(a) 0
(b) \( \frac{1}{m} + \frac{1}{n} \)
(c) \( \frac{1}{mn} \)
(d) 1
Answer: (a) 0
Question. If \( p^{th}, q^{th}, r^{th} \) terms of an A.P are a, b, c then a(q – r) + b(r – p) + c(p – q) =
(a) 0
(b) 1
(c) a + b + c
(d) abc
Answer: (a) 0
Question. If the numbers \( a, b, c, d, e \) form an A.P., then the value of \( a - 4b + 6c - 4d + e \) is
(a) 1
(b) 2
(c) 0
(d) None of the options
Answer: (c) 0
Question. If \( S_n = nP + \frac{n}{2}(n-1)Q \), where \( S_n \) denotes the sum of the first n terms of an A.P., then the common difference is
(a) \( P + Q \)
(b) \( 2P + 3Q \)
(c) 2Q
(d) Q
Answer: (d) Q
Question. In an A.P., if common difference is 2, sum to n terms is 49, 7th term is 13, then n=
(a) 0
(b) 5
(c) 7
(d) 13
Answer: (c) 7
Question. Consider an A.P. with first term \( a \) and common difference \( d \). Let \( S_k \) denote the sum of the first \( k \) terms. If \( \frac{S_{kx}}{S_x} \) is independent of \( x \), then
(a) \( a = 2d \)
(b) \( a = d \)
(c) \( 2a = d \)
(d) \( 2a = 3d \)
Answer: (c) \( 2a = d \)
Question. If \( a_1, a_2, a_3, \dots \) are in A.P. such that \( a_1 + a_5 + a_{10} + a_{15} + a_{20} + a_{24} = 225 \), then \( a_1 + a_2 + a_3 + \dots + a_{23} + a_{24} = \)
(a) 909
(b) 75
(c) 750
(d) 900
Answer: (d) 900
Question. The degree of the expression \( (1+x)(1+x^6)(1+x^{11}) \dots (1+x^{101}) \) is
(a) 1081
(b) 1061
(c) 1071
(d) 1091
Answer: (c) 1071
Question. If the sum of three numbers which are in A.P is 27 and the product of first and last is 77, then the numbers are
(a) 7, 9, 11
(b) 6, 9, 12
(c) 7, 10, 11
(d) 7, 11, 9
Answer: (a) 7, 9, 11
Question. If the ratio of \( n^{th} \) terms of two A.P.'s is \( (2n+8):(5n-3) \), then the ratio of the sums of their n terms is
(a) \( (2n+18):(5n+1) \)
(b) \( (5n-1):(2n+18) \)
(c) \( (2n+18):(5n-1) \)
(d) \( (3n+18):(4n+1) \)
Answer: (c) \( (2n+18):(5n-1) \)
Question. Between 1 and 31 are inserted m arithmetic means, so that the ratio of the 7th and \( (m-1)^{th} \) means is 5:9. Then the value of m is
(a) 12
(b) 13
(c) 14
(d) 15
Answer: (c) 14
Question. If \( S_1, S_2, S_3 \) are the sums of first n natural numbers, their squares and their cubes respectively, then \( S_3(1+8S_1)= \)
(a) \( S_2^2 \)
(b) \( 9S_2 \)
(c) \( 9S_2^2 \)
(d) \( 3S_2^2 \)
Answer: (c) \( 9S_2^2 \)
Question. If 6th term of a G.P. is –1/32 and 9th term is 1/256, then 11th term =
(a) 1024
(b) 1/1024
(c) 1/256
(d) 1/512
Answer: (b) 1/1024
Question. If \( (1-y)(1+2x+4x^2+8x^3+16x^4+32x^5)=1-y^6 \), (\( y \neq 1 \)), then a value of y/x is
(a) 1/2
(b) 2
(c) 25/24
(d) 24/25
Answer: (b) 2
Question. If the sum of three numbers in a G.P. is 26 and the sum of products taken two at a time is 156, then the numbers are
(a) 2,6,18
(b) 1,8,64
(c) 1,5,25
(d) 1,4,1
Answer: (a) 2,6,18
Question. One of the 5 geometric means between \( \frac{1}{3} \) and 243 is
(a) 79
(b) 80
(c) 81
(d) 82
Answer: (c) 81
Question. If the fourth term of a H.P is 1/3 and 7th term is 1/4, then 16th term is
(a) 1/5
(b) 1/6
(c) 1/7
(d) 1/8
Answer: (c) 1/7
Question. If a, b, c are in H.P and ab + bc + ca = 15, then ca =
(a) 5
(b) 7
(c) 9
(d) 10
Answer: (a) 5
Question. If \( \frac{1}{1^2} + \frac{1}{2^2} + \frac{1}{3^2} + \dots \text{upto } \infty = \frac{\pi^2}{6} \), then value of \( \frac{1}{1^2} + \frac{1}{3^2} + \frac{1}{5^2} + \dots \text{up to } \infty \) is
(a) \( \frac{\pi^2}{4} \)
(b) \( \frac{\pi^2}{6} \)
(c) \( \frac{\pi^2}{8} \)
(d) \( \frac{\pi^2}{12} \)
Answer: (c) \( \frac{\pi^2}{8} \)
Question. The sum of \( \frac{3}{1.2} \left( \frac{1}{2} \right) + \frac{4}{2.3} \left( \frac{1}{2} \right)^2 + \frac{5}{3.4} \left( \frac{1}{2} \right)^3 + \dots \) to n terms is equal to
(a) \( 1 - \frac{1}{(n+1)2^n} \)
(b) \( 1 - \frac{1}{n \cdot 2^{n-1}} \)
(c) \( 1 + \frac{1}{(n+1) \cdot 2^n} \)
(d) \( 1 + \frac{1}{n \cdot 2^{n-1}} \)
Answer: (a) \( 1 - \frac{1}{(n+1)2^n} \)
Question. If \( \sum_{r=1}^n (r^2+1)r! = 200 \times 201! \), then n =
(a) 200
(b) 201
(c) 199
(d) 202
Answer: (a) 200
Free study material for Chapter 8 Sequences and Series
MCQs for Chapter 8 Sequences and Series Mathematics Class 11
Students can use these MCQs for Chapter 8 Sequences and Series to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Class 11 Mathematics released by CBSE. Our expert teachers suggest that you should practice daily and solving these objective questions of Chapter 8 Sequences and Series to understand the important concepts and better marks in your school tests.
Chapter 8 Sequences and Series NCERT Based Objective Questions
Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for Class 11. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Chapter 8 Sequences and Series, you should also refer to our NCERT solutions for Class 11 Mathematics created by our team.
Online Practice and Revision for Chapter 8 Sequences and Series Mathematics
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