Practice Class 11 Mathematics Permutations and Combinations MCQs Set 05 provided below. The MCQ Questions for Class 11 Chapter 6 Permutations and Combinations Mathematics with answers and follow the latest CBSE/ NCERT and KVS patterns. Refer to more Chapter-wise MCQs for CBSE Class 11 Mathematics and also download more latest study material for all subjects
MCQ for Class 11 Mathematics Chapter 6 Permutations and Combinations
Class 11 Mathematics students should review the 50 questions and answers to strengthen understanding of core concepts in Chapter 6 Permutations and Combinations
Chapter 6 Permutations and Combinations MCQ Questions Class 11 Mathematics with Answers
Question. There are 3 routes from Guntur to Madras and 4 routes from Madras to Cochin, in how many different ways a person can travel from Guntur to Cochin via Madras is
(a) 21
(b) 24
(c) 12
(d) 20
Answer: (c) 12
Question. The number of permutations of 8 things taken ‘r’ at a time is 1680. Then r =
(a) 4
(b) 5
(c) 6
(d) 7
Answer: (a) 4
Question. The number of permutations of ‘n’ dissimilar things taken 'r' at a time, in which a particular thing always occur is
(a) \( {}^{(n-1)}P_{(r-1)} \)
(b) \( r \cdot {}^{(n-1)}P_{(r-1)} \)
(c) \( r \cdot {}^{(n-1)}P_{r} \)
(d) \( r! \cdot {}^{(n-1)}P_{(r-1)} \)
Answer: (b) \( r \cdot {}^{(n-1)}P_{(r-1)} \)
Question. \( 1 \cdot {}^{1}P_{1} + 2 \cdot {}^{2}P_{2} + \dots + 6 \cdot {}^{6}P_{6} = \)
(a) 720
(b) 5039
(c) 7!
(d) 8!
Answer: (b) 5039
Question. The remainder obtained when 1!+2!+......+100! is divided by 240 is
(a) 153
(b) 154
(c) 155
(d) 156
Answer: (a) 153
Question. The number of ways in which the candidates \( A_1, A_2, \dots, A_{10} \) can be ranked if \( A_1 \) and \( A_2 \) are next to each other is
(a) 9! 2!
(b) 9!
(c) \( \frac{10!}{2!} \)
(d) \( \frac{9!}{4!} \)
Answer: (a) 9! 2!
Question. The number of ways in which the candidates \( A_1, A_2, \dots, A_{10} \) can be ranked if \( A_1 \) is always above \( A_2 \) is
(a) 9! 2!
(b) 9!
(c) \( \frac{10!}{2} \)
(d) 10!
Answer: (c) \( \frac{10!}{2} \)
Question. The number of ways in which 10 candidates \( A_1, A_2, A_3, A_4, \dots, A_{10} \) can be ranked if \( A_1 \) is just above \( A_2 \) is
(a) 9! 2!
(b) 10!
(c) 10! 2!
(d) 9!
Answer: (d) 9!
Question. The number of words that can be formed from the letters of the word "INTERMEDIATE" in which no two vowels are together is
(a) \( 6! \cdot {}^{7}P_{6} \)
(b) \( \frac{6!}{2!} \cdot \frac{{}^{7}P_{6}}{2! 3!} \)
(c) \( \frac{6!}{2! 3!} \cdot \frac{{}^{7}P_{6}}{2! 3!} \)
(d) \( \frac{7! \cdot {}^{7}P_{6}}{2! 5!} \)
Answer: (b) \( \frac{6!}{2!} \cdot \frac{{}^{7}P_{6}}{2! 3!} \)
Question. The number of ways to rearrange the letters of the word CHEESE is
(a) 119
(b) 240
(c) 720
(d) 6
Answer: (a) 119
Question. If the letters of word ‘VICTORY’ are arranged in the order of a dictionary. Then rank of the word ‘VICTORY’ is
(a) 3731
(b) 3732
(c) 3733
(d) 3720
Answer: (c) 3733
Question. The rank of the word ‘SEASON’ is
(a) 210
(b) 220
(c) 230
(d) 270
Answer: (d) 270
Question. The number of ways in which 5 boys and 3 girls can sit around a table so that all the girls do not come together is
(a) 4020
(b) 4120
(c) 4220
(d) 4320
Answer: (d) 4320
Question. The number of ways that a garland is made with 18 flowers such that the two specified flowers should be side by side in the garland is
(a) 15
(b) 120
(c) 17!
(d) 16!
Answer: (d) 16!
FUNDAMENTAL PRINCIPLE
Question. A student has 5 pants and 8 shirts. The number of ways in which he can wear the dress in different combinations is
(a) \( ^{8}P_{5} \)
(b) \( ^{8}C_{5} \)
(c) \( 8! \times 5! \)
(d) 40
Answer: (d) 40
Question. An automobile dealer provides motor cycles and scooters in three body patterns and 4 different colours each. The number of choices open to a customer is
(a) \( ^{5}C_{3} \)
(b) \( ^{4}C_{3} \)
(c) \( 4 \times 3 \)
(d) \( 4 \times 3 \times 2 \)
Answer: (d) \( 4 \times 3 \times 2 \)
Question. In a class there are 10 boys and 8 girls. The teacher wants to select either a boy or a girl to represent the class in a function. The number of ways the teacher can make this selection.
(a) 18
(b) 80
(c) \( ^{10}P_{8} \)
(d) \( ^{10}C_{8} \)
Answer: (a) 18
PROBLEMS BASED ON \( ^{n}P_{r} \) FORMULA
Question. If \( ^{9}P_{5} + 5 \cdot ^{9}P_{4} = ^{10}P_{r} \) then \( r = \)
(a) 4
(b) 5
(c) 6
(d) 7
Answer: (b) 5
Question. If \( \frac{^{20}P_{r-1}}{a} = \frac{^{20}P_{r}}{3} = \frac{^{20}P_{r+1}}{4} \) then \( a = \)
(a) 9/7
(b) 7/9
(c) 3/4
(d) 4/3
Answer: (a) 9/7
Question. If \( ^{(2n+1)}P_{n-1} : ^{(2n-1)}P_{n} = 3 : 5 \) then \( n = \)
(a) 4
(b) 5
(c) 6
(d) 3
Answer: (a) 4
Question. If \( ^{n}P_{7} = 42 \cdot ^{n}P_{5} \) then \( n = \) [EAM-98]
(a) 5
(b) -1
(c) 7
(d) 12
Answer: (d) 12
Question. If \( ^{15}P_{r} = 32760 \), then \( r = \)
(a) 4
(b) 5
(c) 6
(d) 7
Answer: (a) 4
Question. If \( ^{n}P_{r} = 5040 \) then \( (n, r) = \)
(a) (9, 4)
(b) (10, 4)
(c) (11, 3)
(d) (11, 4)
Answer: (b) (10, 4)
Question. The value of \( \sum_{r=1}^{10} r \cdot P(r, r) \) is
(a) \( P(11, 11) \)
(b) \( P(11, 11) - 1 \)
(c) \( P(11, 11) + 1 \)
(d) \( 12! - 1 \)
Answer: (b) \( P(11, 11) - 1 \)
PROBLEMS BASED ON REMAINDER & OTHER MODELS
Question. The value of \( 1 + 1 \cdot 1! + 2 \cdot 2! + 3 \cdot 3! + \dots + n \cdot n! \) is
(a) \( (n+1)!+1 \)
(b) \( (n-1)!+1 \)
(c) \( (n+1)!-1 \)
(d) \( (n+1)! \)
Answer: (d) \( (n+1)! \)
Question. The last two digits in \( X = \sum_{k=1}^{100} k! \) are
(a) 10
(b) 11
(c) 12
(d) 13
Answer: (d) 13
Question. The remainder obtained when \( 1!+2!+ \dots 49! \) is divided by 20 is
(a) 13
(b) 33
(c) 12
(d) 11
Answer: (a) 13
Question. When \( n! + 1 \) is divided by any natural number between 2 and n then remainder obtained is
(a) 1
(b) 2
(c) 3
(d) 4
Answer: (a) 1
Question. If \( \sum_{k=1}^{m} (k^{2} + 1)k! = 1999(2000!) \), then m is
(a) 1999
(b) 2000
(c) 2001
(d) 2002
Answer: (a) 1999
PERMUTATIONS OF DISSIMILAR THINGS
Question. The number of different signals can be given by using any number of flags from 4 flags of different colours is
(a) 24
(b) 256
(c) 64
(d) 60
Answer: (c) 64
Question. Three Men have 4 coats 5 waist Coats, and 6 caps. The number of ways they can wear them is
(a) \( ^{15}P_{3} \)
(b) \( 4^{3} 5^{3} 6^{3} \)
(c) \( ^{4}P_{3} \cdot ^{5}P_{3} \cdot ^{6}P_{3} \)
(d) 180
Answer: (c) \( ^{4}P_{3} \cdot ^{5}P_{3} \cdot ^{6}P_{3} \)
Question. A railway carriage can seat 5 each side. The number of ways a party of 4 girls and 6 boys can seat themselves so that the girls may always have the corner seats is
(a) 17,430
(b) 17,431
(c) 17,280
(d) 17,281
Answer: (c) 17,280
Question. The number of words that can be formed using any number of letters of the word "KANPUR" is
(a) 720
(b) 1956
(c) 360
(d) 370
Answer: (b) 1956
Question. The number of words that can be formed using all the letters of the word "KANPUR" when the vowels are in even places is
(a) 144
(b) 36
(c) 24
(d) 48
Answer: (a) 144
Question. The letters of the word "LOGARITHM" are arranged in all possible ways. The number of arrangements in which the relative positions of the vowels and consonants are not changed is
(a) 4320
(b) 720
(c) 4200
(d) 3420
Answer: (a) 4320
Question. The number of ways one can arrange words with the letters of the word "MADHURI" so that always vowels occupy the beginning, middle and end places is
(a) 7!
(b) \( ^{3}C_{3} \cdot ^{4}P_{3} \)
(c) \( 3 \cdot ^{4}C_{4} \)
(d) \( 3! \cdot 4! \)
Answer: (d) \( 3! \cdot 4! \)
Question. The letters of the word "FLOWER" are taken 4 at a time and arranged in all possible ways. The number of arrangements which begin with 'F' and end with 'R' is
(a) 20
(b) 18
(c) 14
(d) 12
Answer: (d) 12
Question. The number of permutations that can be made from the letters of the word "SUNDAY" without beginning with 'S' or without ending with 'Y' is
(a) 696
(b) 624
(c) 604
(d) 504
Answer: (a) 696
Question. Ten guests are to be seated in a row of which three are ladies. The ladies insist on sitting together while two of the gentlemen refuse to take consecutive seats. In how many ways can the guests be seated?
(a) 2399976
(b) 21844
(c) 630624
(d) 181440
Answer: (d) 181440
Question. The number of ways in which 6 Boys and 5 Girls can sit in a row so that all the girls maybe together is
(a) \( 6! \cdot 5! \)
(b) \( 6! \cdot ^{7}P_{5} \)
(c) \( (6!)^{2} \)
(d) \( 7! \cdot 5! \)
Answer: (d) \( 7! \cdot 5! \)
Free study material for Chapter 6 Permutations and Combinations
MCQs for Chapter 6 Permutations and Combinations Mathematics Class 11
Students can use these MCQs for Chapter 6 Permutations and Combinations to quickly test their knowledge of the chapter. These multiple-choice questions have been designed as per the latest syllabus for Class 11 Mathematics released by CBSE. Our expert teachers suggest that you should practice daily and solving these objective questions of Chapter 6 Permutations and Combinations to understand the important concepts and better marks in your school tests.
Chapter 6 Permutations and Combinations NCERT Based Objective Questions
Our expert teachers have designed these Mathematics MCQs based on the official NCERT book for Class 11. We have identified all questions from the most important topics that are always asked in exams. After solving these, please compare your choices with our provided answers. For better understanding of Chapter 6 Permutations and Combinations, you should also refer to our NCERT solutions for Class 11 Mathematics created by our team.
Online Practice and Revision for Chapter 6 Permutations and Combinations Mathematics
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