CBSE Class 6 Mathematics Revision Assignment 1

A. Write the following numeral for each of following number
a. Nine thousand eighteen = 9018
b. Fifty four thousand seventy three = 54073
c. Twenty Lakh ten thousand eight = 2010008
d. Fifteen core fifty Lakh twenty thousand sixty eight = 155020068

B. Write each of the following number in word using Indian place value system
a. 63,005 = Sixty three thousand five
b. 34,20,019 = Thirty four lakh twenty thousand nineteen
c. 5,10,03,604 = Five crore ten lakh three thousand six hundred four
d. 6,15,30,807 = Six crore fifteen lakh thirty thousand eight hundred seven

C. Insert commas using International place value system . Also write the number name of each
a. 97645310 = 97,645,310 = Ninety seven million six hundred forty five thousand three hundred ten
b. 279453 = 279, 453 = Two hundred seventy nine thousand four hundred fifty three
c. 5035472 = 5, 035, 472 – Five million thirty five thousand four hundred seventy two.

D. By how much is 132465160 larger than 4658642
Solution ---
If a and b two number (a>b)
to find a is how much larger than b
we subtract b from a
here a= 13246510
b = 4658642

required number a- b
13246510
- 4658642
8587868

E. Arrange the following numbers in descending order
63872604, 4965328, 63890503, 5023145, 576943
63890503 , 63872604, 5023145, 4965328, 576943

F. The difference between two numbers is 9476583. If the smallest number is 6873547. Find the greater number.
Solution ->
Difference between the two number = 9476583
Smaller number = 6873547
Hence greater number = (9476583 – 6873547)
C TL L T.TH TH. H T O
9 4 7 6 5 8 3
+ 6 8 7 3 5 4 7
______________
1 6 3 5 0 1 3 0
______________

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