NCERT Solutions Class 10 Mathematics Chapter 1 Real Numbers
Exercise 1.1 Q.1) Use Euclid’s division algorithm to find the HCF of: (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 Sol.1) (i) 135 and 225 We start with the larger number 225 By Euclid’s division algorithm, we have 225 = 1 × 135 + 90 135 = 1 × 90 + 45 = 2 × 45 + 0…
CBSE Class 10 Mathematics Real Numbers Notes Set B
Classification of Natural Numbers I) Natural numbers are divided into three groups:- i) Unit:-1 is the only unit in natural numbers. ii) Prime:-A natural number “a” is said to be Prime if it is divisible by 1 and ‘”a” itself. For example 2,3,5,7,11,13,17,19,23,29,31…
CBSE Class 10 Mathematics Real Numbers MCQs
More Questions: Question: The product of two consecutive integers is divisible by a) 2 b) 3 c) 5 d) 7 Answer: 2 Question: The product of three consecutive integers is divisible by a) 6 b) 7 c) none of these d) 5 Answer: 6 Question: n2 -1 is divisible by 8, if n is a…
CBSE Class 10 Mathematics Real Numbers Notes And Examples
EUCLID’S DIVISION ALGORITHM : If ‘a’ and ‘b’ are positive integers such that a = bq + r, then every common divisor of ‘a’ and ‘b’ is a common divisor of ‘b’ and ‘r’ and vice-versa. Illustration-4 Use Euclid’s division algorithm to find the H.C.F. of 196 and 38318…
CBSE Class 10 Mathematics Real Numbers Notes Set A
Chapter 1: Real Numbers Points to Remember Key Concepts 5.Euclid’s Division Algorithm is stated for only positive integers but it can be extended for all integers except zero, i.e, b ≠ 0. 6.The numbers which can be represented in the form of p/q where q 0…