Maharashtra Board Class 12 Maths Part 2 Chapter 5 Index Numbers 5.3 Solutions

Get the most accurate MSBSHSE Solutions for Class 12 Maths Commerce Chapter 5 Index Numbers 5.3 here. Updated for the 2026-27 academic session, these solutions are based on the latest MSBSHSE textbooks for Class 12 Maths Commerce. Our expert-created answers for Class 12 Maths Commerce are available for free download in PDF format.

Detailed Chapter 5 Index Numbers 5.3 MSBSHSE Solutions for Class 12 Maths Commerce

For Class 12 students, solving MSBSHSE textbook questions is the most effective way to build a strong conceptual foundation. Our Class 12 Maths Commerce solutions follow a detailed, step-by-step approach to ensure you understand the logic behind every answer. Practicing these Chapter 5 Index Numbers 5.3 solutions will improve your exam performance.

Class 12 Maths Commerce Chapter 5 Index Numbers 5.3 MSBSHSE Solutions PDF

Calculate the cost of living index in problems 1 to 3.

Question 1.

GroupBase YearCurrent Year
 PriceQuantityPrice
Food12015170
Clothing15020190
Fuel &
Lighting
13030220
House Rent16010180
Miscellaneous20012200


Answer: Solution:

GroupP0q0P1P1q0P0q0
Food1201517025501800
Clothing1502019038003000
Fuel & Lighting1303022066003900
House Rent1601018018001600
Miscellaneous2001220024002400
    1715012700

\(\Sigma P_1 q_0 = 17150, \Sigma P_0 q_0 = 12700\) Cost of living index is \[CLI = \frac{\Sigma P_1 q_0}{\Sigma P_0 q_0} \times 100\] \[CLI = \frac{17150}{12700} \times 100\] \( = 135.04\) In simple words: The Cost of Living Index (CLI) is calculated by summing the products of current year prices and base year quantities, dividing by the sum of products of base year prices and base year quantities, and then multiplying by 100. It measures the relative change in the cost of a fixed basket of goods and services.

🎯 Exam Tip: Ensure accurate calculation of \(\Sigma P_1 q_0\) and \(\Sigma P_0 q_0\) as these are critical for the correct determination of the Cost of Living Index. Present your answer with two decimal places.

 

Question 2.

GroupBase YearCurrent Year
 PriceQuantityPrice
Food401545
Clothing301035
Fuel &
Lighting
202525
House Rent602070
Miscellaneous702080


Answer: Solution:

GroupP0q0P1P1q0P0q0
Food401545675600
Clothing301035350300
Fuel & Lighting201725425340
House rent60227015401320
Miscellaneous70258020001750
    49904310

\(\Sigma P_1 q_0 = 4990\) \(\Sigma P_0 q_0 = 4310\) \[CLI = \frac{\Sigma P_1 q_0}{\Sigma P_0 q_0} \times 100\] \[CLI = \frac{4990}{4310} \times 100\] \( = 115.78\) In simple words: The Cost of Living Index for Question 2 is calculated using the same formula, which involves summing up the product of current prices and base quantities and dividing it by the sum of the product of base prices and base quantities, then multiplying by 100.

🎯 Exam Tip: Pay close attention to the quantity \((q_0)\) in the base year when calculating both \(\Sigma P_1 q_0\) and \(\Sigma P_0 q_0\). A common mistake is to use incorrect quantities.

 

Question 3.

GroupBase YearCurrent Year
 PriceQuantityPrice
Food13010170
Clothing15012160
Fuel &
Lighting
16220180
House Rent17018195
Miscellaneous1205120


Answer: Solution:

GroupP0q0P1P1q0P0q0
Food1321017017001320
Clothing1541216019201848
Fuel & Lighting1642018036003280
House rent1751819535103150
Miscellaneous1285120600640
    1133010238

\(\Sigma P_1 q_0 = 11330, \Sigma P_0 q_0 = 10238\) \[CLI = \frac{\Sigma P_1 q_0}{\Sigma P_0 q_0} \times 100\] \[CLI = \frac{11330}{10238} \times 100\] \( = 110.67\) In simple words: Following the standard method, the Cost of Living Index for the third problem is computed by dividing the total value of current prices at base year quantities by the total value of base prices at base year quantities, then multiplying by 100.

🎯 Exam Tip: Double-check all arithmetic operations, especially in summation, to avoid errors. Ensure the correct application of the Laspeyres' method for Cost of Living Index calculation.

Base year weights (W) and current year price relatives (I) are given in problems 4 to 8. Calculate the cost of living index in each case.

 

Question 4.

GroupFoodClothingFuel & Light-ingHouse RentMiscellane-ous
I70901006080
W53246


Answer: Solution:

GroupIWIW
Food705350
Clothing903270
Fuel & Lighting1002200
House Rent604240
Miscellaneous806480
  201540

\(\Sigma W = 20, \Sigma IW = 1540\) \[CLI = \frac{\Sigma IW}{\Sigma W}\] \[ = \frac{1540}{20}\] \( = 77\) In simple words: The Cost of Living Index for problems 4-8 is calculated using the weighted average of price relatives, where price relatives (I) are multiplied by their respective weights (W) and then summed up, finally divided by the sum of weights.

🎯 Exam Tip: For the weighted average method, clearly identify the price relatives (I) and weights (W). Calculate the product IW for each group accurately before summing them up.

 

Question 5.

GroupFoodClothingFuel & Light-ingHouse RentMiscellane-ous
I400300150120100
W33452


Answer: Solution:

GroupIWIW
Food40031200
Clothing3003900
Fuel & Lighting1504600
House Rent1205600
Miscellaneous1002200
  173500

\(\Sigma W = 17, \Sigma IW = 3500\) \[CLI = \frac{\Sigma IW}{\Sigma W}\] \[ = \frac{3500}{17}\] \( = 205.88\) In simple words: The Cost of Living Index in this case is determined by summing the products of individual price relatives (I) and their corresponding weights (W), and then dividing this sum by the total sum of the weights.

🎯 Exam Tip: Ensure precise calculation of the sum of IW and the sum of W. Rounding errors should be minimized until the final result is obtained, typically to two decimal places.

 

Question 6.

GroupFoodClothingFuel & Light-ingHouse RentMiscellane-ous
I200150120180160
W3020104050


Answer: Solution:

GroupIWIW
Food200306000
Clothing150203000
Fuel & Lighting120101200
House Rent180407200
Miscellaneous160508000
  15025400

\(\Sigma W = 150, \Sigma IW = 25400\) \[CLI = \frac{\Sigma IW}{\Sigma W}\] \[ = \frac{25400}{150}\] \( = 169.33\) In simple words: The Cost of Living Index is calculated by first finding the sum of (Price Relative × Weight) for all groups, and then dividing this sum by the sum of all weights.

🎯 Exam Tip: When dealing with larger numbers, use a calculator carefully to avoid calculation errors. Always verify your summations before proceeding to the final division.

 

Question 7.

GroupFoodClothingFuel & Light-ingHouse RentMiscellane-ous
I180120300100160
W456x3


Answer: Solution:

GroupIWIW
Food1804720
Clothing1205600
Fuel & Lighting30061800
House Rent100x100x
Miscellaneous1603480
  x+18100x + 3600

\(\Sigma W = x + 18, \Sigma IW = 100x + 3600\) CLI = 150 \(\frac{\Sigma IW}{\Sigma W} = 150\)
\( \implies \frac{100x + 3600}{x + 18} = 150\)
\( \implies 100x + 3600 = 150x + 2700\)
\( \implies 50x = 900\)
\( \implies x = 18\) In simple words: When a weight is unknown but the Cost of Living Index is given, we can set up an equation using the formula for CLI. By substituting the known values and solving the algebraic equation, the value of the unknown weight can be found.

🎯 Exam Tip: Remember to correctly form the equation when an unknown variable is involved. Be careful with algebraic manipulation and cross-multiplication to solve for the unknown.

 

Question 8. Find y if the cost of living index is 200

GroupFoodClothingFuel & Light-ingHouse RentMiscellane-ous
I180120160300200
W453y2


Answer: Solution:

GroupIWIW
Food1804720
Clothing1205600
Fuel & Lighting1603480
House Rent300y300y
Miscellaneous2002400
  y + 14300y + 2200

\(\Sigma W = y + 14, \Sigma IW = 300y + 2200\) CLI = 200 \(\frac{\Sigma IW}{\Sigma W} = 200\)
\( \implies \frac{300y + 2200}{y + 14} = 200\)
\( \implies 300y + 2200 = 200y + 2800\)
\( \implies 100y = 600\)
\( \implies y = 6\) In simple words: Given the Cost of Living Index and an unknown weight, we apply the weighted average formula, creating an algebraic equation. Solving this equation by isolating the unknown variable will yield its value.

🎯 Exam Tip: Practice solving algebraic equations involving CLI. Ensure all terms are correctly transposed and combined to avoid errors in finding the unknown weight.

 

Question 9. The cost of living Index numbers for years 1995 and 1999 are 140 and 200 respectively. A person earns Rs. 11,200 per month in the year 1995. What should be his monthly earning in the year 1999 in order to maintain his standard of living as in the year 1995?
Answer: Solution: CLI (1995) = 140 CLI (1999) = 200 Income (1995) = Rs. 11200 Income (1999) = ? For year 1995 Real Income = \(\frac{\text{Income}}{\text{CLI}} \times 100\) \[ = \frac{11200}{140} \times 100\] \( = \text{Rs. } 8000\) For year 1999 Real Income = \(\frac{\text{Income}}{\text{CLI}} \times 100\) \[8000 = \frac{\text{Income}}{200} \times 100\]
\( \implies \text{Income} = 16000\) Income in 1999 = Rs. 16000 In simple words: To maintain the same standard of living, real income must remain constant. By calculating the real income in the base year, we can then determine the nominal income required in a future year by adjusting for the change in the Cost of Living Index.

🎯 Exam Tip: Understand the concept of real income and its relationship with the Cost of Living Index. Remember that "maintaining the standard of living" implies keeping real income constant across different time periods.

MSBSHSE Solutions Class 12 Maths Commerce Chapter 5 Index Numbers 5.3

Students can now access the MSBSHSE Solutions for Chapter 5 Index Numbers 5.3 prepared by teachers on our website. These solutions cover all questions in exercise in your Class 12 Maths Commerce textbook. Each answer is updated based on the current academic session as per the latest MSBSHSE syllabus.

Detailed Explanations for Chapter 5 Index Numbers 5.3

Our expert teachers have provided step-by-step explanations for all the difficult questions in the Class 12 Maths Commerce chapter. Along with the final answers, we have also explained the concept behind it to help you build stronger understanding of each topic. This will be really helpful for Class 12 students who want to understand both theoretical and practical questions. By studying these MSBSHSE Questions and Answers your basic concepts will improve a lot.

Benefits of using Maths Commerce Class 12 Solved Papers

Using our Maths Commerce solutions regularly students will be able to improve their logical thinking and problem-solving speed. These Class 12 solutions are a guide for self-study and homework assistance. Along with the chapter-wise solutions, you should also refer to our Revision Notes and Sample Papers for Chapter 5 Index Numbers 5.3 to get a complete preparation experience.

FAQs

Where can I find the latest Maharashtra Board Class 12 Maths Part 2 Chapter 5 Index Numbers 5.3 Solutions for the 2026-27 session?

The complete and updated Maharashtra Board Class 12 Maths Part 2 Chapter 5 Index Numbers 5.3 Solutions is available for free on StudiesToday.com. These solutions for Class 12 Maths Commerce are as per latest MSBSHSE curriculum.

Are the Maths Commerce MSBSHSE solutions for Class 12 updated for the new 50% competency-based exam pattern?

Yes, our experts have revised the Maharashtra Board Class 12 Maths Part 2 Chapter 5 Index Numbers 5.3 Solutions as per 2026 exam pattern. All textbook exercises have been solved and have added explanation about how the Maths Commerce concepts are applied in case-study and assertion-reasoning questions.

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Yes, we provide bilingual support for Class 12 Maths Commerce. You can access Maharashtra Board Class 12 Maths Part 2 Chapter 5 Index Numbers 5.3 Solutions in both English and Hindi medium.

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