NCERT Class 10 Maths Constructions

In Class IX, you have done certain constructions using a straight edge (ruler) and a compass, e.g., bisecting an angle, drawing the perpendicular bisector of a line segment, some constructions of triangles etc. and also gave their justifications. In this chapter, we shall study some more constructions by using the knowledge of the earlier constructions. You would also be expected to give the mathematical reasoning behind why such constructions work.
11.2 Division of a Line Segment
Suppose a line segment is given and you have to divide it in a given ratio, say 3 : 2. You may do it by measuring the length and then marking a point on it that divides it in the given ratio. But suppose you do not have any way of measuring it precisely, how would you find the point? We give below two ways for finding such a point. Construction 11.1 : To divide a line segment in a given ratio. Given a line segment AB, we want to divide it in the ratio m : n, where both m and
n are positive integers. To help you to understand it, we shall take m = 3 and n = 2.
Steps of Construction :
1. Draw any ray AX, making an acute angle with AB.
2. Locate 5 (= m + n) points A1, A2, A3, A4 and A5 on AX so that AA1 = A1A2 = A2A3 = A3A4 = A4A5.

3. Join BA5.
4. Through the point A3 (m = 3), draw a line parallel to A5B (by making an angle equal to Ð AA5B) at A3 intersecting AB at the point C (see Fig. 11.1). Then, AC : CB = 3 : 2.

Please refer to attached file for NCERT Class 10 Maths Constructions